Two identical springs of spring constant '2k' are attached to a block of mass m and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this system is

Option 1 - <p>&nbsp;<math><mrow><mi>π</mi><mroot><mrow><mfrac><mrow><mi>m</mi></mrow><mrow><mi>k</mi></mrow></mfrac></mrow></mroot></mrow></math></p>
Option 2 - <p><math><mrow><mi>π</mi><mroot><mrow><mfrac><mrow><mi>m</mi></mrow><mrow><mn>2</mn><mi>k</mi></mrow></mfrac></mrow></mroot></mrow></math></p>
Option 3 - <p><math><mrow><mn>2</mn><mi>π</mi><mroot><mrow><mfrac><mrow><mi>m</mi></mrow><mrow><mi>k</mi></mrow></mfrac></mrow></mroot></mrow></math></p>
Option 4 - <p><math><mrow><mn>2</mn><mi>π</mi></mrow></math><math><mrow><mroot><mrow><mfrac><mrow><mi>m</mi></mrow><mrow><mn>2</mn><mi>k</mi></mrow></mfrac></mrow></mroot></mrow></math></p>
4 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
6 months ago
Correct Option - 1
Detailed Solution:

Since both spring applied force in same direction.

Equivalent spring constant = 4k

T = 2 π m 4 k

T = π m k

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Physics Oscillations 2025

Physics Oscillations 2025

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