Two identical springs of spring constant ‘2k’ are attached to a block of mass m and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. The time period of oscillations of this system is

Option 1 -

 πmk

Option 2 -

πm2k

Option 3 -

2πmk

Option 4 -

2πm2k

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Since both spring applied force in same direction.

    Equivalent spring constant = 4k

    T = 2 π m 4 k

    T = π m k

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