Two identical thin metal plates has charge q₁ and q₂ respectively such that q₁ > q₂. The plates were brought close to each other to from a parallel plate capacitor of capacitance C. The potential difference between them is:

Correct Option - 3


Detailed Solution:

V =   $\frac{q_{\left(capacitance\right)}}{C}=\frac{q_1-q_2}{2c}$

 

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