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Two light beams of intensities in the ratio of 9 : 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be

Option 1 -

2 : 3       

Option 2 -

16 : 81 

Option 3 -

25 : 169

Option 4 -

25 : 1

0 2 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago
    Correct Option - 4


    Detailed Solution:

     l1I2=94 lmaxlmax=l1+l2+2l1l2l1+l2−2l1l2

    =94+1+29494+1−294

    =134+2×32134−2×32=251

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