Two long conductors, separated by a distance d carry current $I_{1}$ and $I_{2}$ in the same direction. They exert a force F on each other. Now the current in one of them is increased to two times and its directions is reversed. The distance is also increased to 3 d. The new value of the force between them is

Option 1 - -2F

Option 2 - F/3

Option 3 - 2F/3

Option 4 - -F/3

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Answered by

Raj Pandey | Contributor-Level 9

4 months ago

Correct Option - 3

Detailed Solution:

$F \propto \frac{i_{1} i_{2}}{a}$ Since one of the current increase two times

and distance increases three times, so force become $\frac{2}{3}$ times. Also due to the reversal of direction of current force becomes negative.

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