Two long parallel conductors S1 and S2 are separated by a distance 10 cm and carrying currents of 4A and 2A respectively. The conductors are placed along x-axis in X-Y plane. There is a point P located between the conductors (as shown in figure).

A charge particle of 3p coulomb is passing through the point P with velocity v = ( 2 i ^ + 3 j ^ ) m/s; where   i ^ a n d j ^ represents unit vector along x & y axis respectively. The force acting on the charge particle is 4p * 10-5 ( x i ^ + 2 j ^ ) N .  The value of x is

Option 1 - <p>2</p>
Option 2 - <p>1</p>
Option 3 - <p>3</p>
Option 4 - <p>-3</p>
12 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
P
8 months ago
Correct Option - 3
Detailed Solution:

B N e t = μ 0 4 π * 2 [ i 1 d 1 i 2 d 2 ] ( k ^ )

= 1 0 7 * 2 [ 4 4 * 1 0 0 2 6 * 1 0 0 ] ( k ^ )

= 2 * 1 0 5 [ 1 1 3 ] k ^

B N e t = 4 3 * 1 0 5 ( k ^ )                        

q = 3πc

v = 2 i ^ + 3 j ^

F = q ( v * B )               

= 3 π [ ( 2 i ^ * 3 j ^ ) * 4 3 * 1 0 5 ( k ^ ) ]

F = 4 π * 1 0 5 ( 3 i ^ + 2 j ^ ) N  

x = 3

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Physics NCERT Exemplar Solutions Class 12th Chapter Eight 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Eight 2025

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