Two particles are executing SHM which are described by the equations x1 = asin(ωt + π/6) and x2 = asin(ωt + π/4). Find the minimum time interval between the particles to cross their mean position.
Two particles are executing SHM which are described by the equations x1 = asin(ωt + π/6) and x2 = asin(ωt + π/4). Find the minimum time interval between the particles to cross their mean position.
Option 1 - <p>π/(12ω)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>π/(6ω)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>π/(4ω)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>π/(3ω)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
2 Views|Posted 5 months ago
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5 months ago
Correct Option - 1
Detailed Solution:
at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/6)
⇒ ωt? + π/6 = π
at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/4)
⇒ ωt? + π/4 = π
From (i) and (ii)
ω (t? - t? ) = π/4 - π/6 ⇒ t? - t? = π/ (12ω)
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