Two particles are executing SHM which are described by the equations x1 = asin(ωt + π/6) and x2 = asin(ωt + π/4). Find the minimum time interval between the particles to cross their mean position.
Two particles are executing SHM which are described by the equations x1 = asin(ωt + π/6) and x2 = asin(ωt + π/4). Find the minimum time interval between the particles to cross their mean position.
Option 1 -
π/(12ω)
Option 2 -
π/(6ω)
Option 3 -
π/(4ω)
Option 4 -
π/(3ω)
Asked by Shiksha User
-
1 Answer
-
Correct Option - 1
Detailed Solution:at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/6)
⇒ ωt? + π/6 = π
at t = t? , x? = 0 ⇒ 0 = asin (ωt? + π/4)
⇒ ωt? + π/4 = π
From (i) and (ii)
ω (t? - t? ) = π/4 - π/6 ⇒ t? - t? = π/ (12ω)
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers