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Two plane mirrors M1 and M2 are at right angle to each shown. A point sources ‘P’ is placed at ‘a’ and ‘2a’ meter away from M1 and M2 respectively. The shortest distance between the images thus formed is :   ( T a k e     5 = 2 . 3 )

 

Option 1 -

2 1 0     a

Option 2 -

2.3 a

Option 3 -

4.6 a

Option 4 -

3 a

0 6 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    2 months ago
    Correct Option - 3


    Detailed Solution:

    dist l1 l2 = 2 5 a

    = 2 * 2.3 a

    = 4.6 a

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