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Two rods of length d1 and d2 and coefficients of thermal conductivities K1 and K2 are kept touching each other. Both have the same area of cross?section, the equivalent thermal conductivity is

Option 1 -

K 1 + K 2

Option 2 -

K 1 d 1 + K 2 d 2

Option 3 -

d 1 K 1 + d 2 K 2 d 1 + d 2

Option 4 -

d 1 + d 2 ( d 1 / K 1 + d 2 / K 2 )

0 3 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    3 weeks ago
    Correct Option - 4


    Detailed Solution:

    When Two rods are connected in series

    Q=A (T1−T2)td1K1+d2K1=A (T1−T2)t (d1+d2)/K

    d 1 + d 2 K = d 1 K 1 + d 2 K 2

    K= (d1+d2)d1K1+d2K1

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