Two satellites A and B, having masses in the ration 4 : 3, are revolving in circular orbits of radii 3r and 4r respectively around the earth. The ratio of total mechanical energy of A to B is:

Option 1 -

9 : 16

Option 2 -

16 : 9

Option 3 -

1 : 1

Option 4 -

4 : 3

3 Views | Posted 2 months ago

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

$\frac{E_{A}}{E_{B}} = \frac{- \frac{G M m_{A}}{2 \times 3 r}}{\frac{- G M m_{B}}{2 \times 4 r}} = \frac{m_{A}}{m_{B}} \times \frac{4}{3} = \frac{4}{3} \times \frac{4}{3} = \frac{16}{9}$

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