Two sources of light emit X  - rays of wavelength   1 n m and visible light of wavelength 500 n m   , respectively. Both the sources emit light of the same power 200 W   . The ratio of the number density of photons of X  - rays to the number density of photons of the visible light of the given wavelengths is:

Option 1 -

1 500

Option 2 -

500

Option 3 -

250

Option 4 -

1 250

0 2 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 months ago
    Correct Option - 1


    Detailed Solution:

    Power = Number of photons emitted per sec ×  Energy of 1 photon

    P = n × h c λ n λ

     

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