Water drops are falling from a nozzle of a shower onto the floor, from a height of 9.8m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.

Option 1 -

7.35m

Option 2 -

2.45m

Option 3 -

2.94m

Option 4 -

4.18m

0 5 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Time taken by first drop to reach the ground,

    t 1 = 2 h g = 2 × 9 . 8 9 . 8 = 2 s              

    Time for which second drop has fallen,

    t 2 = t 1 t 1 2 = 2 1 2 s

    Height of the second drop

    = 9 . 8 1 2 × 9 . 8 × ( 2 1 2 ) 2 = 7 . 3 5 m

                  

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