Water drops are falling from a nozzle of a shower onto the floor, from a height of 9.8m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.

Option 1 - <p>7.35m</p>
Option 2 - <p>2.45m</p>
Option 3 - <p>2.94m</p>
Option 4 - <p>4.18m</p>
15 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 1
Detailed Solution:

Time taken by first drop to reach the ground,

t 1 = 2 h g = 2 * 9 . 8 9 . 8 = 2 s              

Time for which second drop has fallen,

t 2 = t 1 t 1 2 = 2 1 2 s

Height of the second drop

= 9 . 8 1 2 * 9 . 8 * ( 2 1 2 ) 2 = 7 . 3 5 m

              

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