<p>What is meant by the phase of SHM?</p>

Ask & Answer Question

Simple Harmonic Motion Physics Oscillations Physics Class 11th

What is meant by the phase of SHM?

1 View | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

Syed Aquib Ur Rahman | Contributor-Level 10

a month ago

The phase in SHM tells us the position and direction of motion of the particle at a specific instant. It determines the state of oscillation and includes both displacement and time information.

0 Upvotes 0 Downvotes

Similar Questions for you

Two simple harmonic motion are represented by,

And

The ratio of their amplitudes is

Raj Pandey

$A_{1} = \sqrt[]{{(5)}^{2} + {(5 \sqrt[]{3})}^{2}} = 10$

$A_{2} = 5$

Then, $\frac{A_{1}}{A_{2}} = \frac{10}{5} = \frac{2}{1}$

For an SHM oscillator, the amplitude is 5 cm and its time period is 4 seconds. The minimum time taken by the particle to pass between points which are at distances 4 cm and 3 cm from the centre of oscillation on the same side of it will be

alok kumar singh

$y = A \sin ? \frac{2 π t}{T}$

$t_{2} - t_{1} = \frac{T}{2 π} [\sin^{- 1} ? \frac{x_{1}}{A} - \sin^{- 1} ? \frac{x_{2}}{A}]$

The given arrangement is in vertical plane and initially the springs are in natural length. The uniform rod is hinged at end O, about which it can freely rotate. The angular frequency of small oscillations of the rod is n/8 √(k/m). Find n. (Given: m = mass of rod, L = length of rod and k = mg/L)