What is the ratio of minimum acceleration to the maximum velocity of a simple harmonic oscillator?

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Payal Gupta | Contributor-Level 10

7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

As we know equation of SHM is x= Asinwt

V= dx/dt=Awsinwt

V_max=Awcoswt_max

= Aw

A=dv/dt=-wAwsinwt

= -w²Asinwt

A_max=-w²A

From above equations

$\frac{V_{m a x}}{A_{m a x}}$ =wA/w²A=1/w

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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025

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