What will be the average value energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T? (kB is Boltzmann constant)
What will be the average value energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T? (kB is Boltzmann constant)
Option 1 - <p>kBT<br><!--[endif]--></p>
Option 2 - <p>(2/3)kBT<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>(3/2)kBT</p>
Option 4 - <p>(1/2)kBT</p>
2 Views|Posted 5 months ago
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1 Answer
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5 months ago
Correct Option - 4
Detailed Solution:
According to principle of equi-partition of Energy, the average energy per molecules associated with each degree of freedom is (1/2)kT.
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physics ncert solutions class 11th 2023
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