When a particle executes SHM, the nature of graphical representation of velocity as a function of

Option 1 -

Circular

Option 2 -

Straight line

Option 3 -

Parabolic

Option 4 -

Elliptical

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

Let x = A sin $ω t$ & v = $A ω c o s ω t$

$∴ v = ω \sqrt[]{A^{2} - x^{2}}$

$v^{2} = ω^{2} x^{2} - ω^{2} A^{2}$

$\frac{v^{2}}{ω^{2} A^{2}} + \frac{x^{2}}{A^{2}} = 1$

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