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When a particle of mass m is attached to a vertical spring of spring constant k and released, its motion is described by y(t) = y₀sin² ωt, where ' y ' is measured from the lower end of unstretched spring. Then ω is:

Option 1 -

(1/2)√(g/y₀)

Option 2 -

√(g/y₀)

Option 3 -

√(g/2y₀)

Option 4 -

√(2g/y₀)

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:
    Kindly go through the solution

     

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