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When light of maximum wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter however light of maximum wavelength 600 nm causes photoelectric emission. The ratio of work functions of first emitter to second emitter will be

Option 1 -

1 : 2

Option 2 -

2 : 1

Option 3 -

1 : 1

Option 4 -

1 : 4

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 weeks ago
    Correct Option - 2


    Detailed Solution:
    Kindly go through the solution

     

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