Wires X₁ and W₂ are made of same material having the breaking stress of 1.25 × 10⁹ N/m². W₁ and W₂ have cross-sectional area of 8 × 10^-⁷m² and 4 × 10^-⁷m², respectively. Masses of 20kg and 10kg hang from them as shown in the figure. THE maximum mass that can be placed in the pan without breaking the wires is_______kg.

(Use g = 10 m/s²)

2 Views | Posted 2 months ago

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Answered by

alok kumar singh | Contributor-Level 10

2 months ago

For $W_{1},$

$\frac{(m + 10 + 20) \times 10}{8 \times 1 0^{- 7}} \leq 1.25 \times 1 0^{9}$

$\Rightarrow m \leq 70 k g$

For W₂,

$\frac{(m + 10) \times 10}{4 \times 1 0^{- 7}} \leq 1.25 \times 1 0^{9}$

-> $m \leq 40 k g$

Thus, $m \leq 40 k g$

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