Y = A sin <math><mrow><mrow><mo>(</mo><mrow><mi>ω</mi><mi>t</mi><mo>+</mo><msub><mrow><mi>?</mi></mrow><mrow><mn>0</mn></mrow></msub></mrow><mo>)</mo></mrow></mrow></math> is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is y = <math><mrow><mfrac><mrow><mi>A</mi></mrow><mrow><mn>2</mn></mrow></mfrac></mrow></math> and it moving along negative x-direction. Then the initial phase angle <math><mrow><msub><mrow><mi>?</mi></mrow><mrow><mn>0</mn></mrow></msub></mrow></math> will be

Using general equation of SHM :y=Asin (ωt+? 0)=A2ωt+? 0=π6, 5π6At t = 0? 0=π6, 5π6Since it is moving in – x direction? =5π6

Y = A sin&nbsp;<math><mrow><mrow><mo>(</mo><mrow><mi>ω</mi><mi>t</mi><mo>+</mo><msub><mrow><mi>?</mi></mrow><mrow><mn>0</mn></mrow></msub></mrow><mo>)</mo></mrow></mrow></math>&nbsp;is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is y =&nbsp;<math><mrow><mfrac><mrow><mi>A</mi></mrow><mrow><mn>2</mn></mrow></mfrac></mrow></math>&nbsp;and it moving along negative x-direction. Then the initial phase angle&nbsp;<math><mrow><msub><mrow><mi>?</mi></mrow><mrow><mn>0</mn></mrow></msub></mrow></math>&nbsp;will be

Ask & Answer Question

Option 1 -

$\frac{5 π}{6}$

Option 2 -

$\frac{π}{6}$

Option 3 -

$\frac{π}{3}$

Option 4 -

$\frac{2 π}{3}$

4 Views | Posted a month ago

Answered by

Payal Gupta | Contributor-Level 10

a month ago

Correct Option - 1

Detailed Solution:

Using general equation of SHM :

$y = A s i n (ω t + ?_{0}) = \frac{A}{2}$

$ω t + ?_{0} = \frac{π}{6}, \frac{5 π}{6}$

At t = 0

$?_{0} = \frac{π}{6}, \frac{5 π}{6}$

Since it is moving in – x direction

$? = \frac{5 π}{6}$