Ask & Answer: India's Largest Education Community

Given,  $\Delta =\left|\begin{array}{ccc}\hfill 1\hfill & \hfill x\hfill & \hfill yz\hfill \\ \hfill 1\hfill & \hfill y\hfill & \hfill zx\hfill \\ \hfill 1\hfill & \hfill z\hfill & \hfill xy\hfill \end{array}\right|$

Co-factor of elements of third column

∴ Δ = a₁₃A₁₃ + a₂₃A₂₃ + a₃₃A₃₃

 = yz (z-y) + zx [- (z-x)] + xy (y-x)

 = y z²-y²z-z²x+ zx² + xy²-x²y.

 = yz²-y²z+ (xy²-xz²) + (zx²-x²y)

 = yz (z-y) + x (y² – z²) -x² (y-z)

 = -yz (y-z) + x (y + z) (y-z) -x² (y-z)

= (y-z) [-yz + x (y + z) -x²]

 = (y-z) [-yz + xy + xz-x²]

 = (y-z) [-y (z-x) + x (z-x)]

 = (y-z) (z-x) (x -y)

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Range = $\sqrt[]{2hR}=\sqrt[]{2\times 20\times 6.4\times {10}^6}=16km$

Area = $\pi R^2=3.14\times 16\times 16$ =803.84km²

When H= 25 m

Range = $\sqrt[]{2hR}+\sqrt[]{2HR}=\sqrt[]{2\times 20\times 6.4\times {10}^6}+\sqrt[]{2\times 25\times 6.4\times {10}^6}$ = 33.9km

Area= 3.14 $\times 33.9\times 33.9=3608.52km$ ²

percentage increase = $\frac{3608.52-803.84}{803.84}\times 100=348.9$ %

Given,  $?=\left|\begin{array}{lll}5\hfill & 3\hfill & 8\hfill \\ 2\hfill & 0\hfill & 1\hfill \\ 1\hfill & 2\hfill & 3\hfill \end{array}\right|$

Co-factors of elements of second row,

? ? = a₂₁A₂₁ + a₂₂A₂₂ + a₂₃A₂₃

= 2 * 7 + 0 * 7 + 1 * (-7) = 14 + 0 - 7 = 7.

Emversity School of Hospitality, Bangalore has 50 seats for BVoc course. The seat allotment is done based on fulfilment of eligibility criteria. The given seat count is as per official sources. Hence, is indicative.

Pursuing MBA in Russia is very affordable with annual tuition fee as low as INR 2 L. On average, the annual cost ranges between INR 2 L - INR 6 L. Check out the table below for the annual tuition cost required in the top B-schools in Russia:

(i) Given, A = $\left|\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right|$

So,

(ii)Given,  $\Delta =\left|\begin{array}{ccc}\hfill 1\hfill & \hfill 0\hfill & \hfill 4\hfill \\ \hfill 3\hfill & \hfill 5\hfill & \hfill -1\hfill \\ \hfill 0\hfill & \hfill 1\hfill & \hfill 2\hfill \end{array}\right|$

Deen Dayal Upadhyay Hospital offers several DNB courses in full-time mode. The average tuition fee at Deen Dayal Upadhyay Hospital ranges around INR 2.25 lacs. However, this fee is exclusive of other charges such as examination fee, hostel fee, application fee, etc. Candidates are advised to visit the official website before applying.

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Total distance = 5km and loss is 2 dB/km

So total loss = 5 (2)= 10 dB

Total gain in amplifier  10+20= 30dB and gain in signal is 20dB

So by the formula 20= 10log_{10 $\frac{p_o}{p_i}$}

log_{10 $\frac{p_o}{p_i}$} = 2

so po/pi= 10²

so Po= Pi (100)= 101mW

(i) We know that,

Minor of element a_ij is m_ij and its co-factor is A_ij = (–1)^i+j M_ij

So,

M₁₁ = 3 and A₁₁ = (- 1)^{1 + 1} M₁₁ = 1 * 3 = 3

M₁₂ = 0 and A₁₂ = (-1)¹⁺² M₁₂ = -1 * 0 = 0

M₂₁ = -4 and A₂₁ = (-1)²⁺¹ M₂₁ = (-1) * (-4) = 4

M₂₂ = 2 and A₂₂ = (-1)²⁺² M₂₂ = 1 * 2 = 2

(ii) Given A = $\left|\begin{array}{cc}\hfill a\hfill & \hfill c\hfill \\ \hfill b\hfill & \hfill d\hfill \end{array}\right|$

So,

M₁₁ = d and A₁₁ = (-1)¹⁺¹ M₁₁ = 1 * d = d

M₁₂ = b and A₁₂ = (-1)¹⁺² M₁₂ = (-1) * b = -b

M₂₁ = c and A₂₁ = (-1)^{2+ 1} M₂₁ = (–1) * c = –c

M₂₂ = a and A₂₂ = (-1)²⁺² M₂₂ = 1 * a = a

This is a  Short Answer Type Questions as classified in NCERT Exemplar

In modulating signal we add career wave or noise signal to send it to receiver end and this wave is varied from time to time that is why more noise appear.

But in frequency modulation frequency is not varied so less noise appear.

Once students have registered for the Emversity School of Health Sciences and Hospitality Bengaluru BVoc course, they are reached out to by appointed admission counsellors. These counsellors help students throughout the admission process. Moreover, registered students are encouraged to visit the campus and evaluate the services and amenities provided by the institute.

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Frequency tuned amplifier is $\frac{1}{2\pi \sqrt[]{LC}}=1MHz$

$\sqrt[]{LC}$ =1/2 $\pi \times {10}^6$

$LC=2.54\times {10}^{-14}s$

Given,

Area of triangle = 35 sq. Units

$\Rightarrow \frac{1}{2}\left|\begin{array}{ccc}\hfill 2\hfill & \hfill -6\hfill & \hfill 1\hfill \\ \hfill 5\hfill & \hfill 4\hfill & \hfill 1\hfill \\ \hfill k\hfill & \hfill 4\hfill & \hfill 1\hfill \end{array}\right|=35.$

∴ Option D is correct.

Deen Dayal Upadhyay Hospital admissions take place online. The admissions to DDU Hospital are based on the merit obtained in the entrance exam (NEET PG). Interested candidates can apply online through the official website. Deen Dayal Upadhyay Hospital admissions are currently not open. Students must first register for NEET PG in order to secure admission to DDU Hospital.

This is a  Short Answer Type Questions as classified in NCERT Exemplar

Maximum amplitude = Am+Ac =12 while minimum amplitude is Ac-Am=3

Using elimination method = 2Ac= 18

Ac=9 and Am= 6V

So modulating index m = 6/9= 2/3

(i) Let P (x, y) be any point on line joining A (1, 2) & B (3, 6)

Then, area of triangle (ABP) = 0 {the point are collinear

$\frac{1}{2}\left|\begin{array}{ccc}\hfill 1\hfill & \hfill 2\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill 6\hfill & \hfill 1\hfill \\ \hfill x\hfill & \hfill y\hfill & \hfill 1\hfill \end{array}\right|=0$

This is a  Short Answer Type Questions as classified in NCERT Exemplar

As frequency of B is more than A so it has more refractive index also and if a wave have higher refractive index then it has less angle of refraction. So wave B travel more in ionosphere.

(i) Area of the triangle = 4 sq. units (given)

$\Rightarrow \frac{1}{2}\left|\begin{array}{ccc}\hfill k\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 4\hfill & \hfill 0\hfill & \hfill 1\hfill \\ \hfill 0\hfill & \hfill 2\hfill & \hfill 1\hfill \end{array}\right|=4$

(ii) Area of the triangle = 4 sq units