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The University of Luxembourg is well-known for its academic and better research opportunities. This university surely stands out as one of the most popular universities in the world. The university has constantly secured a high ranking complimenting its industrial expertise.

Although these courses are not as highly ranked among the top, based on the rankings released by Shiksha Popularity, they rank at #1 for Engineering in Luxembourg. 

IIT Madras trains its students to become industry leaders and professionals. The college provides placement assistance to students and is visited by top companies for placements such as JP Morgan Chase, Texas Instruments, Adobe, and others. The college even provides scholarships to deserving students. 

International applicants must make sure to fulfill the admission requirements and submit necessary documents and finally pay the application fee as per their level of programs. For UConn, the application fee for UG and PG programs differ.

For UG programs: USD 80 (INR 6.9 K)

For PG programs: USD 75 (INR 6.4 K)

Renowned for its academic excellence and high-quality research opportunities, the University of Luxembourg surely stands out as one of the most popular universities in the world. The university has constantly secured a high ranking complimenting its industrial expertise.

According to Shiksha Popularity Rankings, Engineering courses at this university rank #1 among the best courses in the world. Based on the rankings by THE, they ranked at #176 in the year 2025.

According to the unofficial website, the University of Massachusetts, Dartmouth acceptance rate is about 92% over the years. This shows the university is lenient when it comes to admission, and candidates generally get selected as long as they meet the admission requirements and submit all the mandatory documents required for admission. The minimum eligibility criteria include meeting the academic requirements as well as English language requirements

The UMASS Dartmouth acceptance rate is approximately 92% as of recent years, according to unofficial websites. As of 2024-2025, the university received over 10,000 applications, and out of that, 1,303 finally enrolled. This shows the university is lenient when it comes to admission and candidates generally get selected as long as they meet the admission requirements and submit all the mandatory documents required for admission.

At its Bannerghatta Road Campus, Christ University offers a full-time BA (Hons) in Liberal Arts. The course duration is four years, which is further divided into eight semesters. The subjects included in the curriculum depend on the specialisations/ tracks selected by the students pursuing a BA (Hons) in Liberal Arts. There are seven discipline specialisation options, including Psychology, Economics, Business & Management, etc. It also includes Incubation and Capstone projects. Students have to secure a total of 169 credits to complete the BA (Hons) course.

Yes, Institute of Technology, Nirma University accepts GUJCET scores for BTech and MCA courses under the ACPC quota. Candidates must register for GUJCET and participate in the counselling process. Allotment is based on merit and category.

Institute of Technology, Nirma University 2025 last admission cutoff applicants are to wait until final expansion of counselling rounds. The candidates have to refer to ACPC or the official Nirma University site to find new deadlines.

The University of Luxembourg offers only one intake, which is the Winter intake for both bachelor's and Master's programs. The application period begins in March for undergraduate students and in February for postgraduate students. For most of the Engineering programs, a Summer semester is unavailable.

Below are the University of Luxembourg Engineering admission deadlines 2026:

Admission to institute of technology, Nirma university is entrance based into all major courses in the university. GUJCET/JEE Main is required to get BTech and GATE is needed to get MTech. One cannot directly be admitted without the qualifying exams.

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}GiventhatBisaskewsymmetricmatrix\therefore B^{\text{'}}=-B\\ LetP=A^{\text{'}}BA\\ \Rightarrow P^{\text{'}}={\left(A^{\text{'}}BA\right)}^{\text{'}}\\ \Rightarrow =A^{\text{'}}{B}^{\text{'}}{\left(A^{\text{'}}\right)}^{\text{'}}\left[{\left(A^{\text{'}}B\right)}^{\text{'}}=B^{\text{'}}{A}^{\text{'}}\right]\\ \Rightarrow =A^{\text{'}}\left(-B\right)A\\ \Rightarrow =A^{\text{'}}BA=-P\\ So{P}^{\text{'}}=-P\\ Hence,A^{\text{'}}BAisaskewsymmetricmatrix.\end{array}$

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}Toshowthat:{\left(I+A\right)}^3=7A+I\\ L.H.S.{\left(I+A\right)}^3=I^3+A^3+3I^{2}A+3I{A}^2\\ \Rightarrow =I+A^2.A+3IA+3I{A}^2\\ \Rightarrow =I+A.A+3IA+3IA\left[?A^2=A\right]\\ \Rightarrow =I+A^2+3IA+3IA\\ \Rightarrow =I+A+3IA+3IA\left[?A^2=A\right]\\ \Rightarrow =I+A+3A+3A\Rightarrow 7A+IR.H.S.\\ L.H.S.=R.H.S.Hence,proved.\end{array}$

This is a short answer type question as classified in NCERT Exemplar

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}LetA=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill a\hfill & \hfill 3\hfill \\ \hfill 2\hfill & \hfill b\hfill & \hfill -1\hfill \\ \hfill c\hfill & \hfill 1\hfill & \hfill 0\hfill \end{array}\right]A^{\text{'}}=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill 2\hfill & \hfill c\hfill \\ \hfill a\hfill & \hfill b\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]\\ Forskewsymmetricmatrix,A^{\text{'}}=-A\\ \left[\begin{array}{ccc}\hfill 0\hfill & \hfill 2\hfill & \hfill c\hfill \\ \hfill a\hfill & \hfill b\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]=-\left[\begin{array}{ccc}\hfill 0\hfill & \hfill a\hfill & \hfill 3\hfill \\ \hfill 2\hfill & \hfill b\hfill & \hfill -1\hfill \\ \hfill c\hfill & \hfill 1\hfill & \hfill 0\hfill \end{array}\right]\\ \Rightarrow \left[\begin{array}{ccc}\hfill 0\hfill & \hfill 2\hfill & \hfill c\hfill \\ \hfill a\hfill & \hfill b\hfill & \hfill 1\hfill \\ \hfill 3\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]=\left[\begin{array}{ccc}\hfill 0\hfill & \hfill -a\hfill & \hfill -3\hfill \\ \hfill -2\hfill & \hfill -b\hfill & \hfill 1\hfill \\ \hfill -c\hfill & \hfill -1\hfill & \hfill 0\hfill \end{array}\right]\\ Equatingthecorrespondingelements,weget\\ a=-2,b=-b\Rightarrow 2b=0\Rightarrow b=0andc=-3\\ Hence,a=-2,b=0andc=-3.\end{array}$

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}Here,A=\left[\begin{array}{cc}\hfill cos\alpha \hfill & \hfill sin\alpha \hfill \\ \hfill -sin\alpha \hfill & \hfill cos\alpha \hfill \end{array}\right]\\ Giventhat:A^{-1}=A^{\text{'}}\\ Pre-multiplyingbothsidesbyA\\ A{A}^{-1}=A{A}^{\text{'}}\\ \Rightarrow I=A{A}^{\text{'}}\left[?A{A}^{-1}=I\right]\\ \Rightarrow \left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill cos\alpha \hfill & \hfill sin\alpha \hfill \\ \hfill -sin\alpha \hfill & \hfill cos\alpha \hfill \end{array}\right]\left[\begin{array}{cc}\hfill cos\alpha \hfill & \hfill -sin\alpha \hfill \\ \hfill sin\alpha \hfill & \hfill cos\alpha \hfill \end{array}\right]\\ \Rightarrow \left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill co{s}^2\alpha +si{n}^2\alpha \hfill & \hfill -sin\alpha cos\alpha +sin\alpha cos\alpha \hfill \\ \hfill -sin\alpha cos\alpha +cos\alpha sin\alpha \hfill & \hfill si{n}^2\alpha +co{s}^2\alpha \hfill \end{array}\right]\\ \Rightarrow \left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]\\ Hence,itistrueforallvaluesof\alpha .\end{array}$

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}Giventhat:A=\left[\begin{array}{cc}\hfill 1\hfill & \hfill 2\hfill \\ \hfill 4\hfill & \hfill 1\hfill \end{array}\right]\\ A^2=A.A=\left[\begin{array}{cc}\hfill 1\hfill & \hfill 2\hfill \\ \hfill 4\hfill & \hfill 1\hfill \end{array}\right]\left[\begin{array}{cc}\hfill 1\hfill & \hfill 2\hfill \\ \hfill 4\hfill & \hfill 1\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 1+8\hfill & \hfill 2+2\hfill \\ \hfill 4+4\hfill & \hfill 8+1\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 9\hfill & \hfill 4\hfill \\ \hfill 8\hfill & \hfill 9\hfill \end{array}\right]\\ \therefore A^2+2A+7I=\left[\begin{array}{cc}\hfill 9\hfill & \hfill 4\hfill \\ \hfill 8\hfill & \hfill 9\hfill \end{array}\right]+2\left[\begin{array}{cc}\hfill 1\hfill & \hfill 2\hfill \\ \hfill 4\hfill & \hfill 1\hfill \end{array}\right]+7\left[\begin{array}{cc}\hfill 1\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 1\hfill \end{array}\right]\\ =\left[\begin{array}{cc}\hfill 9\hfill & \hfill 4\hfill \\ \hfill 8\hfill & \hfill 9\hfill \end{array}\right]+\left[\begin{array}{cc}\hfill 2\hfill & \hfill 4\hfill \\ \hfill 8\hfill & \hfill 2\hfill \end{array}\right]+\left[\begin{array}{cc}\hfill 7\hfill & \hfill 0\hfill \\ \hfill 0\hfill & \hfill 7\hfill \end{array}\right]\\ =\left[\begin{array}{cc}\hfill 9+2+7\hfill & \hfill 4+4+0\hfill \\ \hfill 8+8+0\hfill & \hfill 9+2+7\hfill \end{array}\right]=\left[\begin{array}{cc}\hfill 18\hfill & \hfill 8\hfill \\ \hfill 16\hfill & \hfill 18\hfill \end{array}\right]\\ Hence,A^2+2A+7I=\left[\begin{array}{cc}\hfill 18\hfill & \hfill 8\hfill \\ \hfill 16\hfill & \hfill 18\hfill \end{array}\right]\end{array}$