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The placement rate for Bharati Vidyapeeth's Institute of Management Studies and Research has not been disclosed yet. However, Bharati Vidyapeeth's Institute of Management Studies and Research provides good placement to its students. The data tabulated below provides Bharati Vidyapeeth's Institute of Management Studies and Research placement highlights for 2025:

We have, y = [x (x- 2)]².

Differentiating the above w rt. x we get,

$\frac{dy}{dx}=\frac{d}{dx}[x]{(x-2)}^2$

$=2[x(x-2)]\frac{d}{dx}[x(x-2)]$

$=2[x(x-2)]\left[x\frac{d}{dx}(x-2)+(x-2)\frac{dx}{dx}\right]$

= 2 [x (x- 2)] (x + x- 2)

= 2x (x - 2) (2x - 2)

$\frac{dy}{dx}$ = 4x (x - 2) (x - 1).

Now, $\frac{dy}{dx}=0$

$\Rightarrow$ 4x (x - 2) (x - 1) = 0.

i e, x = 0, x = 2, x = 1 divides the real line into

four disjoint interval. $(-\infty ,0],$ [0,1],[1,2] and $\left[2,\infty \right].$

when x $\left[-\infty ,0\right].$

$\frac{dy}{dx}=(-ve)(-ve)(-ve)=$ $(-ve)\le 0,0x=0$

∴f (x) is decreasing in $\left[-\infty ,0\right].$

When $x\in [0,1]$

$\frac{dy}{dx}=(+ve)(-ve)(-ve)$ $=(+ve)\ge 0,x=0x=1$

∴f (x) is increasing in [0,1].

When x $\in [1,2]$

$\frac{dy}{dx}=(+ve)(-ve)(+ve)=(-ve)\le 0,$ $\mathrm{0for}x=1+x=2$

∴f (x) is decreasing.

When $x\in \left(2,\infty \right).$

$\frac{dy}{dx}=(+ve)(+ve)(+ve)=(+ve)\ge \mathrm{0,}0,forx=2$

∴f (x) is in creasing

Hence, f (x) is increasing for x $\in [0,1)x\in [2,\infty )$

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (i) is the correct answer.

Standard reduction potential of bromine is higher than Iodine, hence Bromine is a stronger oxidant than iodine.

B.N.M Institute of Technology considers KCET scores for admission to BE programme. However, it is not mandatory to pass KCET for admission. Aspirants with a valid score in COMEDK UGET can also get admission in the BE programme. For all other courses, the selection requirement is different. 

We have, y = log $(1+x)-\frac{2x}{2+x},x>-1$

Differentiating the above wrt.x.we get,

$\frac{dy}{dx}=\frac{1}{1+x}\frac{d}{dx}(1+x)-$ $\frac{(2+x)\frac{d}{dx}2x-2x\frac{d}{dx}(2+x)}{{(2+x)}^2}$

$\Rightarrow \frac{dy}{dx}=\frac{1}{1+x}-\frac{(2+x)\cdot 2-2x}{{(2+x)}^2}.$

$\Rightarrow \frac{dy}{dx}=\frac{1}{1+x}-\frac{4+2x-2x}{{(2+x)}^2}=\frac{1}{1+x}-\frac{4}{{(2+x)}^2}.$

$=\frac{{(2+x)}^2-4(1+x)}{(1+x){(2+x)}^2}$

$=\frac{4+x^2+4x-4-4x}{(1+x){(2+x)}^2}$

$\frac{dy}{dx}=\frac{x^2}{(1+x){(2+x)}^2}.$

The given domain of the given function isx> -1.

$\Rightarrow$ (x + 1) > 0.

Also, $x^2\ge 0$

(2 + x)²> 0.

Hence, $\frac{dy}{dx}=\frac{(+ve)}{(+v)(+ve)}=(+ve)>0.$

∴ y is an increasing function of x throughout its domain.

This is a Multiple Choice Questions as classified in NCERT Exemplar

Option (iv) is the correct answer.

E? will be negative for the pair Ag and Fe³⁺. Hence the reaction is not feasible.

Not at all, That's the beauty of an MBA. Anyone who has completed a bachelor's degree in any stream which can be arts, science, commerce, engineering, or anything else is eligible to pursue this course. Most colleges ask for at least 50% marks in graduation (or 45% for reserved categories).

Also, you will probably need to clear an entrance exam like CAT, XAT, MAT, etc.

Hope this helps!!!

The key highlights recorded during the Bharati Vidyapeeth's Institute of Management Studies and Research MMS placements are provided in the table below:

B.N.M Institute of Technology offers courses at UG, PG and doctoral levels. The institute offers a four-year BE at UG and two-year M.Tech and MBA programmes at the PG level. Besides, candidates can also apply for PhD and MSc by Research at the institute. BNMIT offers programmes in Engineering, Management and Science streams. Interested candidates can apply online for the preferred course.

The necessary abilities or skills required for MBBS are:

• Strong Academic Foundation

• Critical Thinking

• Communication Skills

• Emotional Resilience

• Attention to Detail

• Time Management

• Teamwork

• Empathy and Compassion

Yes, passing Class 12 is the basic eligibility criteria in order to get a seat to UG and PG courses at Shree Swaminarayan Physiotherapy College. Students need to pass Class 12 with relevant subjects to secure a seat to Shree Swaminarayan Physiotherapy College.

 MMS graduates from Bharati Vidyapeeth's Institute of Management Studies and Research Pune get placed into various sectors such as:

• Finance

• Consulting

• Marketing

• IT and Technology

• Logistics

• Entrepreneurship, etc.

We have, f (x) = 2x² 3x

So, f (x) = $\frac{d}{dx}\left(2x^2-3x\right)=4x-3.$

Atf (x) = 0.

$\Rightarrow$ 4x - 3 = 0

i e,  $x=\frac{3}{4}$ divides the real line into two

disjoint interval $\left(-\infty ,\frac{3}{4}\right)\left(\frac{3}{4},\infty \right)$

(a) Now,

f (x) = 4x - 3 > 0 $\forall x\in \left(\frac{3}{4},\infty \right)$

So, f (x) is strictly increasing in $\left(\frac{3}{4},\infty \right)$

(b) Now, f (x) = 4x - 3 < 0 $\forall x\left(-\infty ,\frac{3}{4}\right)$

So, f (x) is strictly decreasing in $\left(-\infty ,\frac{3}{4}\right)$

The overall average package recorded during Bharati Vidyapeeth's Institute of Management Studies and Research MMS placements was INR 5.5 LPA. Refer to the table below to know more:

To be eligible for admission to UG and PG courses, students must meet the basic educational requirements of the programme at the time of admission. Check below the course-wise eligibility and selection criteria for both the courses: