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Yes, Chetana's Institute of Management and Research offers decent placements annually for its PGDM courses. As per the latest report, the highest and average package offered during Chetana's Institute of Management and Research placements in 2025 stood at INR 13.3 LPA and INR 7.04 LPA, respectively. The key highlights of Chetana's Institute of Management and Research placements for the PGDM Class of 2025 are tabulated below:

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Givenequationisy=3x-1\\ Slope=3\\ Slopeofthelinethroughthegiven\left(1,2\right)andparalleltothegivenline=3\\ So,theequationoftherequiredlineis\\ \Rightarrow y-2=3\left(x-1\right)\\ Hence,thecorrectoptionis\left(c\right).\end{array}$

Chetana's Institute of Management and Research has a good record of placements for its PGDM courses. In 2025, the the highest and average package offered stood at INR 13.3 LPA and INR 7.04 LPA, respectively. The key highlights of Chetana's Institute of Management and Research placements for the PGDM Class of 2025 are tabulated below:

The highest package offered during St Joseph's College of Engineering placements 2025 stood at INR 47 LPA. The table below presents the same:

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}LetthegivenlinemeetstheaxesatA\left(a,0\right)andB\left(0,b\right).\\ GiventhatC\left(3,2\right)isthemidofAB\\ \therefore 3=\frac{a+0}{2}\Rightarrow a=6\\ and2=\frac{0+b}{2}\Rightarrow b=4\\ InterceptformofthelineAB\frac{x}{a}+\frac{y}{b}=1\\ \Rightarrow \frac{x}{6}+\frac{y}{4}=1\Rightarrow 2x+3y=12\\ Hence,thecorrectoptionis\left(a\right).\end{array}$

The placements at St Joseph's College of Engineering are good. The following table presents the placement statistics for St Joseph's College of Engineering.

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Givenequationisy=3x+4\\ \Rightarrow 3x-y+4=0\dots \left(i\right)\\ Slope=3\\ Equationofanylinethroughthe\left(2,3\right)is\\ y-3=m\left(x-2\right)\dots \left(ii\right)\\ Ifeqn.\left(i\right)isperpendiculartoeqn.\left(ii\right)then\\ m\times 3=-1\left[?m_1\times m_2=-1\right]\\ \Rightarrow m=-\frac{1}{3}\\ Puttingthevalueofmineqn.\left(ii\right)weget\\ \Rightarrow y-3=-\frac{1}{3}\left(x-2\right)\\ \Rightarrow 3y-9=-x+2\\ \Rightarrow x+3y=11\dots \left(iii\right)\\ Solvingeqn.\left(i\right)andeqn.\left(iii\right)weget\\ 3x-y=-4\Rightarrow y=3x+4\dots \left(iv\right)\\ Puttingthevalueofyineqn.\left(iii\right)weget\\ x+3\left(3x+4\right)=11\\ \Rightarrow x+9x+12=11\\ \Rightarrow 10x=-1\Rightarrow x=\frac{-1}{10}\\ Fromeqn.\left(iv\right)weget,y=3\left(\frac{-1}{10}\right)+4\\ \Rightarrow y=\frac{-3}{10}+4\Rightarrow y=\frac{37}{10}\\ So,therequiredcoordinatesare\left(\frac{-1}{10},\frac{37}{10}\right).\\ Hence,thecorrectoptionis\left(b\right).\end{array}$

ISB&M COC mode of application is online/ offline. The students can download or apply online. Aspirants need to pay a non-refundable application fee to register. The steps to apply for admission are visit the official website, click on apply online and fill the form, then upload documents and pay admission fees.

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Givenequationsarey=mx+c_1\dots \left(i\right)\\ andy=mx+c_2\dots \left(ii\right)\\ Slopesofeqn.\left(i\right)andeqn.\left(ii\right)aresamei.e.,m\\ So,theyareparallellines.\\ \therefore betweenthetwolines=\frac{\left|c_1-c_2\right|}{\sqrt[]{1+m^2}}\\ Hence,thecorrectoptionis\left(b\right).\end{array}$

Yes, for admission to Lakehead Uni, there could be an ask to submit GRE / GMAT scores for Master's admission. Also, to take admission, it is best to have a good score in these standardized tests. In GRE, the students should aim a minimum score of 300 and in GMAT, they must aim for a 500. A few of the documents that students have to submit to take admission to Lakehead Uni are previous degree transcripts, reference letters, updated CV, etc. 

According to unofficial sources Lakehead Univ has an acceptance rate of 90%. This means that university accepts 90 out of 100 student so the admission process is not at all selective. If students work hard on  applications by working hard on academics and extra curriculars, they can increase their chance of getting into university.

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Equationofanylinethrough\left(1,0\right)is\\ y-0=m\left(x-1\right)\Rightarrow mx-y-m=0\\ ofthelinefromoriginis\frac{\sqrt[]{3}}{2}\\ \Rightarrow \frac{\sqrt[]{3}}{2}=\left|\frac{m\times 0-0-m}{\sqrt[]{1+m^2}}\right|\\ \Rightarrow \frac{\sqrt[]{3}}{2}=\left|\frac{-m}{\sqrt[]{1+m^2}}\right|\\ Squaringbothsides,weget\\ \frac{3}{4}=\frac{m^2}{1+m^2}\\ \Rightarrow 4m^2=3+3m^2\Rightarrow 4m^2-3m^2=3\\ \Rightarrow m^2=3\therefore m=\pm \sqrt[]{3}\\ \therefore equationsare\\ \pm \sqrt[]{3}x-y?\sqrt[]{3}=0\\ i.e.,\sqrt[]{3}x-y-\sqrt[]{3}=0and-\sqrt[]{3}x-y+\sqrt[]{3}=0\\ \Rightarrow \sqrt[]{3}x+y-\sqrt[]{3}=0\\ Hence,thecorrectoptionis\left(a\right).\end{array}$

This is a Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Equationoflineisgivenby\\ \sqrt[]{3}x+y+1=0\\ \Rightarrow y=-\sqrt[]{3}x-1\\ \therefore Slopeofthisline,m_1=-\sqrt[]{3}\\ Let{m}_{2}betheslopeoftherequiredline\\ \therefore tan\theta =\left|\frac{m_1-m_2}{1+m_1{m}_2}\right|\\ \Rightarrow tan60^0=\left|\frac{-\sqrt[]{3}-m_2}{1+\left(-\sqrt[]{3}\right)m_2}\right|\\ \Rightarrow \sqrt[]{3}=\pm \left(\frac{-\sqrt[]{3}-m_2}{1-\sqrt[]{3}{m}_2}\right)\\ \Rightarrow \sqrt[]{3}=\frac{-\sqrt[]{3}-m_2}{1-\sqrt[]{3}{m}_2}\left[Taking\left(+\right)sign\right]\\ \Rightarrow \sqrt[]{3}-3m_2=-\sqrt[]{3}-m_2\\ \Rightarrow 2m_2=2\sqrt[]{3}\Rightarrow m_2=\sqrt[]{3}\\ and\sqrt[]{3}=-\left(\frac{-\sqrt[]{3}-m_2}{1-\sqrt[]{3}{m}_2}\right)\left[Taking\left(-\right)sign\right]\\ \Rightarrow \sqrt[]{3}=\frac{\sqrt[]{3}+m_2}{1-\sqrt[]{3}{m}_2}\\ \Rightarrow \sqrt[]{3}-3m_2=\sqrt[]{3}+m_2\\ \Rightarrow 4m_2=0\Rightarrow m_2=0\\ \therefore Equationoflinethroughthe\left(3,-2\right)withslope\sqrt[]{3}is\\ y+2=\sqrt[]{3}\left(x-3\right)\\ \Rightarrow y+2=\sqrt[]{3}x-3\sqrt[]{3}\\ \Rightarrow \sqrt[]{3}x-y-2-3\sqrt[]{3}=0\\ andtheequationoflinethroughthe\left(3,-2\right)withslope0is\\ y+2=0\left(x-3\right)\Rightarrow y+2=0\\ Hence,thecorrectoptionis\left(a\right).\end{array}$