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9 months ago

NIT Raipur - National Institute of Technology NIT Raipur - National Institute of Technology Courses

What is the ranking for BTech courses at NIT Raipur?

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Kartik Sharma

Contributor-Level 10

The 2025 ranking for the BTech course/ engineering category at NIT Raipur has not been released yet. However, the course has been ranked by NIRF for the academic years 2022, 2023 and 2024. Check out the ranking assigned to 'Engineering Category' in different academic years from the table below:

Publisher	2022	2023	2024
NIRF	65	70	71

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9 months ago

What are the weightage of each indicator in the QS World University Rankings?

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Raushan Kumar

Contributor-Level 10

The QS World University rankings indicators include academic reputation which has weightage of:

Academic Reputation – 30%
Citations per Faculty – 20%
Employer Reputation – 15%
Faculty-Student Ratio – 10%
International Faculty Ratio – 5%
International Student Ratio – 5%
International Research Network – 5%
Employment Outcomes – 5%
Sustainability – 5%

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9 months ago

How are QS rankings calculated?

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Raushan Kumar

Contributor-Level 10

For the QS World University Rankings, the institutes are assessed on 9 indicators, which includes, academic reputation, research work, faculty-student ratio, employer opinion, international students and staff, employment outcomes, and even sustainability efforts.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

A box contains 2 white balls, 3 black balls, and 4 red balls. The number of ways three balls can be drawn from the box if at least one black ball is to be included in the draw is ______.

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e h a v e 2 w h i t e, 3 b l a c k a n d 4 r e d b a l l s \\ I t i s g i v e n t h a t a t l e a s t 1 b l a c k b a l l i s t o b e i n c l u d e d . \\ ∴ Required n u m b e r o f w a y s = {}_{3}{C_{1}} \times {}_{6}{C_{2}} + {}_{3}{C_{2}} \times {}_{6}{C_{1}} + {}_{3}{C_{3}} \\ = 3 \times 15 + 3 \times 6 + 1 = 45 + 18 + 1 = 64 \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s 64 . \end{array}$

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9 months ago

Mohanlal Sukhadia University Computers & IT (Non-Engg)

What is the fee for a postgraduate Diploma in Computer Applications at Mohanlal Sukhadia University?

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

A committee of 6 is to be chosen from 10 men and 7 women so as to contain at least 3 men and 2 women. In how many different ways can this be done if two particular women refuse to serve on the same committee?
[Hint: At least 3 men and 2 women: The number of ways = ¹⁰C₃ × ¹⁰C₃ + ¹⁰C₄ × ⁷C₂. For 2 particular women to be always there: the number of ways = ¹⁰C₄ × ¹⁰C₃ × ⁵C₁. The total number of committees when two particular women are never together = Total – together.]

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e h a v e 10 m e n a n d 7 w o m e n o u t o f w h i c h a c o m m i t t e e o f 6 i s t o b e f o r m e d w h i c h c o n t a i n \\ a t l e a s t 3 m e n a n d 2 w o m e n \\ T h e r e f o r e, N u m b e r o f w a y s = {}_{10}{C_{3}} \times {}_{7}{C_{3}} + {}_{10}{C_{4}} \times {}_{7}{C_{2}} \\ = \frac{10 \times 9 \times 8}{3 \times 2 \times 1} \times \frac{7 \times 6 \times 5}{3 \times 2 \times 1} + \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} \times \frac{7 \times 6}{2 \times 1} \\ = 120 \times 35 + 210 \times 21 = 4200 + 4410 = 8610 \\ I f 2 p a r t i c u l a r w o m e n t o b e a l w a y s p r e s e n t, t h e n t h e n u m b e r o f w a y s = {}_{10}{C_{4}} \times {}_{5}{C_{0}} + {}_{10}{C_{3}} \times {}_{5}{C_{1}} \\ = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} \times 1 + \frac{10 \times 9 \times 8}{3 \times 2 \times 1} \times 5 = 210 + 120 \times 5 \\ = 210 + 600 = 810 \\ ∴ T o t a l n u m b e r o f c o m m i t t e e = 8610 - 810 = 7800 \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s 7800 . \end{array}$

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9 months ago

ICFAI Business School, Jaipur Colleges in Jaipur

When are application forms out at IBS Jaipur?

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Nishtha Shukla

Guide-Level 15

IBS Jaipur applications are currently open for 2026 session. Aspirants have to fill out the form on the institute's website. Candidates have to fill out the application form with basic, personal and qualification details. Candidates also need to pay an application fee to apply for a course.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

The total number of ways in which six ‘+’ and four ‘–’ signs can be arranged in a line such that no two signs ‘–’ occur together is ______.

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} T h e f o l l o w i n g m a y b e t h e a r r a n g e m e n t o f (-) a n d (+) \\ (-) (+) (-) (+) (-) (+) (-) (+) (-) (+) (-) (+) (-) \\ T h e r e f o r e,' +' s i g n c a n b e a r r a n g e d o n l y i s 1 w a y b e c a u s e a l l a r e i d e n t i c a l . \\ a n d 4 (-) s i g n s c a n b e a r r a n g e d a t 7 p l a c e s i n {}_{7}{C_{4}} w a y s \\ ∴ T o t a l n u m b e r o f w a y s = {}_{7}{C_{4}} \times 1 = \frac{7 \times 6 \times 5 \times 4}{4 \times 3 \times 2 \times 1} \times 1 = 35 w a y s \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s 35 . \end{array}$

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9 months ago

Alva's Law College Law

Which entrance exams are accepted by Alva's Law College?

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Ashwin Yadav

Contributor-Level 10

Alva's Law College provides different Law courses such as BA LLB, BCom LLB, BBA LLB. Students seeking admissions at the institute must note that the enrolment process is conducted on the basis of merit. Hence, there are no entrance exams prescribed as such for admissions. Students can visit the official website and start the application process by heading to the admissions page.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Nine Exemplar Solution

The lengths of three unequal edges of a rectangular solid block are in G.P. The volume of the block is $216 c m^{3}$ and the total surface area $252 c m^{2}$ is . The length of the longest edge is:

(a) 12

(b) 6

(c) 18

(d) 3

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alok kumar singh

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} L e t t h e l e n g t h, b r e a d t h a n d h e i g h t o f a rectangular b l o c k b e \frac{a}{r}, a a n d a r . \\ Since t h e y a r e i n G . P \\ ∴ V o l u m e = l \times b \times h \\ 216 = \frac{a}{r} \times a \times a r \\ \Rightarrow a^{3} = 216 \Rightarrow a = 6 \\ N o w t o t a l s u r f a c e a r e a = 2 [l b + b h + h l] \\ 252 = 2 [\frac{a}{r} . a + a . a r + \frac{a}{r} . a r] \\ \Rightarrow 252 = 2 [\frac{a^{2}}{r} + a^{2} r + a^{2}] \Rightarrow 252 = 2 a^{2} [\frac{1}{r} + r + 1] \\ \Rightarrow 252 = 2 {(6)}^{2} [\frac{1 + r^{2} + r}{r}] \Rightarrow 252 = 72 [\frac{1 + r^{2} + r}{r}] \\ \Rightarrow \frac{252}{72} = [\frac{1 + r^{2} + r}{r}] \Rightarrow \frac{7}{2} = \frac{1 + r^{2} + r}{r} \\ \Rightarrow 2 + 2 r + 2 r^{2} = 7 r \Rightarrow 2 r^{2} - 5 r + 2 = 0 \\ \Rightarrow 2 r^{2} - 4 r - r + 2 = 0 \Rightarrow 2 r (r - 2) - 1 (r - 2) = 0 \\ \Rightarrow (r - 2) (2 r - 1) = 0 \Rightarrow r - 2 = 0 a n d 2 r - 1 = 0 \\ \Rightarrow r = 2, \frac{1}{2} \\ T h e r e f o r e, t h e t h r e e e d g e a r e : \\ I f r = 2 t h e n e d g e s a r e 3, 6, 12 \\ I f r = \frac{1}{2} t h e n e d g e s a r e 12, 6, 3 \\ S o, t h e l e n g t h o f t h e l o n g e s t e d g e = 12 \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

In a football championship, 153 matches were played. Every two teams played one match with each other. The number of teams participating in the championship is ______.

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t t h e n u m b e r o f p a r t i c i p a t i n g t e a m s b e n . \\ G i v e n t h a t e v e r y t w o t e a m s p l a y e d o n e m a t c h w i t h e a c h o t h e r . \\ ∴ T o t a l n u m b e r o f m a t c h e s p l a y e d = {}_{n}{C_{2}} \\ S o {}_{n}{C_{2}} = 153 \\ \Rightarrow \frac{n (n - 1)}{2} = 153 \Rightarrow n^{2} - n = 306 \\ \Rightarrow n^{2} - n - 306 = 0 \Rightarrow n^{2} - 18 n + 17 n - 306 = 0 \\ \Rightarrow n (n - 18) + 17 (n - 18) = 0 \Rightarrow (n - 18) (n + 17) = 0 \\ \Rightarrow n - 18 = 0 a n d n + 17 = 0 \Rightarrow n = 18, n \neq - 17 \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s 18 . \end{array}$

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9 months ago

IIT Bhilai - Indian Institute of Technology M.Sc.

How are the MSc placements at IIT Bhilai?

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Meitankeisangbam Vasundhara devi

Contributor-Level 10

The MSc placements are out for seasons 2024 and 2023 on the official website. Check out the table for more information:

Particulars	Placement Statistics (2023)	Placement Statistics (2024)
Average Package	INR 6.11 LPA	INR 7.8 LPA
Median Package	INR 6.22 LPA	INR 8 LPA
Placement Rate	66.67%	62.5%

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9 months ago

Science ICAR AIEEA analysis

Was the reasoning section difficult in this year ICAR AIEEA Exam 2025?

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Ishita Chauhan

Contributor-Level 10

As compared to the previous year, students who appeared for the ICAR AIEEA PG Exam this year, found the reasoning section to be on the easier side. The exam was concluded on July 3, 2025, between 10:00 am to 12:00 (noon).

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9 months ago

Law RULET Eligibility

What is RULET reservation criteria?

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Damini Aggarwal

Contributor-Level 10

The following reservation policy will be used for filling BA LLB seats in various categories.

Category	Reservation (%)
Unreserved	56
OBC	25
SC	19
MBC	06
ST	14
EWS	12

5% seat will be reserved for the persons with disabilities in all categories.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

The number of six-digit numbers, all digits of which are odd, is ______.

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} O u t o f t h e d i g i t s 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 t h e o d d d i g i t s a r e 1, 3, 5, 7, 9 . \\ T h e r f o r e, n u m b e r o f 6 d i g i t s n u m b e r s = {(5)}^{6} \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s {(5)}^{6} . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Nine Exemplar Solution

If $t_{n}$ denotes the $n$ -th term of the series $2 + 3 + 6 + 11 + 18 + \dots$ , then $t_{50}$ is:

(a) $492 - 1$

(b) $492$

(c) $502 + 1$

(d) $492 + 2$

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alok kumar singh

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} L e t S_{n} = 2 + 3 + 6 + 11 + 18 + \dots + t_{50} \\ Using m e t h o d o f d i f f e r e n c e, w e g e t \\ S_{n} = 2 + 3 + 6 + 11 + 18 + \dots + t_{50} \dots (i) \\ a n d S_{n} = 0 + 2 + 3 + 6 + 11 + \dots + t_{49} + t_{50} \dots (i i) \\ S u b t r a c t i n g e q n . (i i) f r o m (i), w e g e t \\ 0 = 2 + 1 + 3 + 5 + 7 + \dots - t_{50} t e r m s \\ \Rightarrow t_{50} = 2 + (1 + 3 + 5 + 7 + \dots u p t o 49 t e r m s) \\ \Rightarrow t_{50} = 2 + \frac{49}{2} [2 \times 1 + (49 - 1) 2] = 2 + \frac{49}{2} [2 + 96] \\ = 2 + \frac{49}{2} \times 98 = 2 + 49 \times 49 = 4 9^{2} + 2 \\ H e n c e, t h e c o r r e c t o p t i o n i s (d) . \end{array}$

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9 months ago

NIT Raipur - National Institute of Technology B.Tech

What is the cutoff for BTech in Computer Science and Engineering at NIT Raipur?

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Abhishek Hazarika

Contributor-Level 10

Currently, the JEE Main round third closing rank for admission to the BTech in CSE course at NIT Raipur is 12619. Moreover, as per the comparison of cutoffs of similar rounds in the years 2025, 2024, and 2023 it shows that the ranks slightly get higher and the competitions get a little lower. For better details, check out the accurate ranks in the below table:

Course	2023	2024	2025
BTech in Computer Science and Engineering	11951	11488	12619

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Seven Exemplar Solution

Three balls are drawn from a bag containing 5 red, 4 white, and 3 black balls. The number of ways in which this can be done if at least 2 are red is ______.

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e h a v e 5 r e d, 4 w h i t e a n d 3 b l a c k b a l l s o u t o f w h i c h a t l e a s t 2 r e d b a l l s a r e t o b e d r a w n . \\ ∴ N u m b e r o f w a y s = {}_{5}{C_{2}} \times {}_{7}{C_{1}} + {}_{5}{C_{3}} \\ = 10 \times 7 + 10 = 70 + 10 = 80 \\ H e n c e, t h e v a l u e o f t h e f i l l e r i s 80 . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Nine Exemplar Solution

Let $S_{n}$ denote the sum of the cubes of the first $n$ natural numbers and $s_{n}$ denote the sum of the first $n$ natural numbers. Then

$\frac{1}{S_{n}} \sum_{r = 1} r^{3} s_{r} =$

(a) $\frac{n (n + 1) (n + 2)}{6}$

(b) $\frac{n (n + 1)}{2}$

(c) $\frac{2 n^{3} + 3 n^{2} + n}{6}$

(d) None of these

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alok kumar singh

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l} G i v e n t h a t \sum_{i = 1}^{n} \frac{S_{r}}{s_{r}} = \frac{S_{1}}{s_{1}} + \frac{S_{2}}{s_{2}} + \frac{S_{3}}{s_{3}} + \dots + \frac{S_{n}}{s_{n}} \\ L e t T_{n} b e t h e n t h t e r m o f t h e a b o v e s e r i e s \\ ∴ T_{n} = \frac{S_{n}}{s_{n}} = \frac{{[\frac{n (n + 1)}{2}]}^{2}}{\frac{n (n + 1)}{2}} = \frac{n (n + 1)}{2} = \frac{n^{2} + n}{2} \\ N o w s u m o f t h e g i v e n s e r i e s \\ \sum_{}^{} T_{n} = \frac{1}{2} \sum_{}^{} [n^{2} + n] = \frac{1}{2} [\sum_{}^{} n^{2} + \sum_{}^{} n] \\ = \frac{1}{2} [\frac{n (n + 1) (2 n + 1)}{6} + \frac{n (n + 1)}{2}] \\ = \frac{1}{2} . \frac{n (n + 1)}{2} [\frac{2 n + 1}{3} + 1] = \frac{n (n + 1)}{4} [\frac{2 n + 1 + 3}{3}] \\ = \frac{n (n + 1)}{4} . \frac{(2 n + 4)}{3} = \frac{n (n + 1) (n + 2)}{6} \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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9 months ago

Elphinstone College

When will candidates be called for document verification process at Elphinstone College?

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Saurabh Khanduri

Contributor-Level 10

The candidates who get shortlisted for admissions into Elphinstone College will be called for the documentation process on the next day of the release of merit list. However, these dates are subject to change and may take longer if any issues are detected during document verification.

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