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9 months ago

courses to become a btech btech

What are the documents required for admission to BTech course at KAU?

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Rachit Kumar

Contributor-Level 10

After filling out the application form for the BTech course at KAU, candidates are required to attach several documents. Moreover, at the time of the counselling process too, candidates must submit original/ copies of several documents. The names of the important documents are as follows:

Class 10 mark sheet and pass certificate
Class 12 mark sheet and pass certificate
Entrance exam scorecard
Character certificate
Migration certificate
Domicile certificate (if applicable)
A hard copy of application form

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9 months ago

Dr. Babasaheb Ambedkar Open University (BAOU) B.Sc. Eligibility

Who is eligible to apply for BAOU BSc programmes?

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Virajita Mehra

Contributor-Level 10

Candidates who have passed a Diploma in Computer Engineering/ Information Technology can apply for BSc at BAOU. Additionally, the aspirants who have passed 10th Std + ITI (2 or More Years) + NCVT/GCVT + GSHEB/gose 12th English Exam, 10th + 3 Years Diploma (polytechnic) are also eligible to apply. The applicants must hold the relevant documents at the time of form filling and course admission.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

Given that $x, y$ and $b$ are real numbers and $x < y, b < 0$ , then

(a) $\frac{x}{b} < \frac{y}{b}$

(b) $\frac{x}{b} \leq \frac{y}{b}$

(c) $\frac{x}{b} > \frac{y}{b}$

(d) $\frac{x}{b} \geq \frac{y}{b}$

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} G i v e n t h a t x < y, b < 0 \\ \Rightarrow \frac{x}{b} > \frac{y}{b}, b < 0 \\ H e r e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

If $x < 5$ , then

(a) $- x < - 5$

(b) $- x \leq - 5$

(c) $- x > - 5$

(d) $- x \geq - 5$

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} I f x < 5 t h e n - x > - 5 \\ H e r e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

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9 months ago

Medi-Caps University M.Sc.

Is there any entrance exam for admission to the M.Sc. in Chemistry at Medi-Caps University?

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9 months ago

Dr. Babasaheb Ambedkar Open University (BAOU) B.Sc.

What is the cost of studying BSc at BAOU?

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Mohit Sharma

Contributor-Level 10

BAOU BSc fees has to be paid once the final selection is done for admission confirmation. Some of the components included in the structure are tuition fees, registration fees, etc. BAOU BSc tuition fees amounts to INR 60,000. This fee is taken as per the data curated from the official website/ sanctioning body. It is however, still subject to changes and hence, is indicative.

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9 months ago

courses to become a btech btech

What is the last date to apply for BTech courses at KAU?

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Piyush Jain

Contributor-Level 10

The deadlines/ last date to apply for BTech courses at KAU are released for the academic batch of 2025. The official deadline to apply for BTech for the 2025–26 intake was June 30, 2025. To get admission into BTech course, application can be submitted online via the KAU admissions portal.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

Show that the following system of linear inequalities has no solution: $x + 2 y \leq 3, 3 x + 4 y \geq 12, x \geq 0, y \geq 1 .$

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

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9 months ago

KAU - Kerala Agricultural University B.Tech

Can we join BTech at Kerala Agricultural University directly?

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Vishakha

Contributor-Level 10

Kerala Agricultural University BTech admission is completely entrance-based. The university offers three specialisations in the BTech course and accepts entrance examination scores. The accepted entrance exams are KEAM Engineering and ICAR CUET (the Common University Entrance Test (CUET) conducted for admissions to undergraduate programmes in agriculture and allied sciences at various Agricultural Universities (AUs) in India). Therefore, candidates are not allowed to get direct admission to BTech courses at KAU.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

Find the linear inequalities for which the shaded region in the given figure is the solution set.

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t u s f i r s t c o n s i d e r t h e l i n e x + y = 4 \\ W e o b s e r v e t h a t t h e s h a d e d r e g i o n a n d t h e o r i g i n (0, 0) b o t h o n t h e o p p o s i t e s i d e a n d (0, 0) \\ s a t i s f y t h e constraint x + y \leq 4 . \\ S o, x + y \geq 4 i s t h e l i n e a r i n e q u a l i t y . \\ N o w, t a k e t h e l i n e a r e q u a t i o n x + y = 8 . \\ I n t h i s c a s e, t h e s h a d e d r e g i o n a n d t h e o r i g i n (0, 0) b o t h l i e o n t h e s a m e s i d e o f t h e g r a p h \\ a n d (0, 0) s a t i s f y t h e constraint x + y \leq 8 . \\ S o, x + y \leq 4 i s a n o t h e r l i n e a r i n e q u a l i t y . \\ C o n s i d e r, x = 5 . I t i s c l e a r t h a t t h e s h a d e d a r e a l i e s t o w a r d s t h e o r i g i n . S o, x \leq 5 i s t h e \\ constraints a n d s i m i l a r l y y \leq 5 i s a l s o t h e constraints. W e a l s o o b s e r v e t h a t t h e s h a d e d r e g i o n \\ l i e s i n f i r s t q u a d r a n t, S o x \geq 0 a n d y \geq 0 . \\ H e n c e, t h e r e q u i r e d l i n e a r i n e q u a l i t i e s a r e \\ x + y \geq 4, x + y \leq 8, x \leq 5, y \leq 5, x \geq 0 a n d y \geq 0 . \end{array}$

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9 months ago

B.Tech btech

What is the fees for BTech at KAU?

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Phani Patnana

Beginner-Level 1

B.Tech Fees in INR at KAU (Kerala Agricultural University)

1. Semester-wise tuition and other charges

– B.Tech Agricultural Engineering tuition fee: 47,760 per semester

– Caution deposit (one-time at admission): 100,000

– Application fee: 1000 (500 for SC/ST/Kerala nativity/differently abled)

You will also incur standard college charges (as listed for other programs), such as admission, library, exam, and e-learning fees, which appear consistent across disciplines .

2. Summary per semester (approximate)

Tuition Fee 47,760

Additional Fees* ~25,000

Total per semester ~72,760

*Includes adm

...more

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

Find the linear inequalities for which the shaded region in the given figure is the solution set.

0 Follower 6 Views

Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

\begin{array}{l} L e t u s c o n s i d e r t h e l i n e a r e q u a t i o n 3 x + 2 y = 48 . W e o b s e r v e t h a t t h e s h a d e d r e g i o n a n d t h e \\ o r i g i n b o t h o n t h e s a m e s i d e o f t h e g r a p h o f t h e l i n e a n d (0, 0) s a t i s f y t h e constraint 3 x + 3 y \leq 48 . \\ S i m i l a r l y, w e o b s e r v e t h a t t h e s h a d e d r e g i o n a n d t h e o r i g i n b o t h o n t h e s a m e s i d e o f t h e g r a p h \\ o f t h e l i n e a n d (0, 0) s a t i s f y t h e constraint x + y \leq 20 . \\ W e s e e t h a t t h e s h a d e d r e g i o n i s i n t h e f i r s t q u a d r a n t w h e r e x \geq 0 a n d y \geq 0 \\ H e n c e, t h e r e q u i r e d l i n e a r i n e q u a l i t i e s a r e \\ 3 x + 3 y \leq 48, x + y \leq 20, x \geq 0 a n d y \geq 0 . \end{array}

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9 months ago

Hal Management Academy Hal Management Academy Placement

How are the placement opportunities at Hal Management Academy?

0 Follower 3 Views

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

Solve the following system of inequalities: $\frac{2 x + 1}{7 x - 1} > 5, \frac{x + 7}{x - 8} > 2$

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t u s t a k e t h e i n e q u a t i o n \\ \frac{2 x + 1}{7 x - 1} > 5 \Rightarrow \frac{2 x + 1}{7 x - 1} - 5 > 0 \\ \Rightarrow \frac{2 x + 1 - 5 (7 x - 1)}{7 x - 1} > 0 \Rightarrow \frac{2 x + 1 - 35 x + 5}{7 x - 1} > 0 \\ \Rightarrow \frac{- 33 x + 6}{7 x - 1} > 0 \Rightarrow \frac{33 x - 6}{7 x - 1} < 0 \\ S o, x \in (\frac{1}{7}, \frac{2}{11}) \dots (i) \\ N o w f r o m second i n e q u a l i t y, w e h a v e \\ \Rightarrow \frac{x + 7}{x - 8} > 2 \Rightarrow \frac{x + 7}{x - 8} - 2 > 0 \\ \Rightarrow \frac{x + 7 - 2 x + 16}{x - 8} > 0 \Rightarrow \frac{- x + 23}{x - 8} > 0 \\ \Rightarrow \frac{x - 23}{x - 8} < 0 \\ S o, x \in (8, 23) \dots (i i) \\ N o w n o t h i n g i s c o m m o n t o t h e t w o v a l u e s o f x i . e ., n u l l s e t . \\ H e n c e, t h e g i v e n i n e q u a l i t i e s h a s n o s o l u t i o n . \end{array}$

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9 months ago

courses to become a btech btech Eligibility

What is the eligibility criteria for admission to BTech courses at KAU?

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Tanisha Pandey

Contributor-Level 10

The minimum eligibility criteria for admission to BTech courses at KAU are that candidates must complete their Class 12 from the PCM stream with an aggregate of 50%. Additionally, for the selection process, the university and its affiliated college accept the scores of entrance exams, i.e., KEAM Engineering and ICAR CUET.

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9 months ago

Does Kerala Agricultural University offers BTech courses?

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Chanchal Gaurav

Contributor-Level 10

Yes, Kerala Agricultural University does offer BTech courses for the duration of four years, divided into eight semesters, and offered in full-time mode. The BTech courses at KAU are offered through the faculty of Agriculture and Agricultural Engineering and Technology. The university offers BTech courses through the campus and affiliated colleges in three specialisations. The names of the offered specialisations are Agricultural Engineering, Food Engineering, and Biotechnology.

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

In drilling the world’s deepest hole, it was found that the temperature T in degrees Celsius, x below the earth’s surface, was given by $T = 30 + 25 (x - 3), 3 \leq x \leq 15 .$ At what depth will the temperature be between $15 5^{\circ} C$ and $20 5^{\circ} C$ ?

0 Follower 4 Views

Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} G i v e n t h a t, T e m p e r a t u r e T = 3 0^{0} + 2 5^{0} (x - 3), 3 \leq x \leq 15 \\ R a n g e o f t h e t e m p e r a t u r e i s 15 5^{0} C t o 20 5^{0} C \\ ∴ 15 5^{0} < T < 20 5^{0} \\ \Rightarrow 15 5^{0} < 3 0^{0} + 2 5^{0} (x - 3) < 20 5^{0} \Rightarrow 12 5^{0} < 2 5^{0} (x - 3) < 17 5^{0} \\ \Rightarrow \frac{125}{25} < (x - 3) < \frac{175}{25} \Rightarrow 5 < x - 3 < 7 \\ \Rightarrow 8 < x < 10 \\ H e n c e, t h e r e q u i r e d t e m p e r a t u r e a t t h e d e p t h f r o m 8 k m t o 10 k m l i e s b e t w e e n 15 5^{0} C a n d 20 5^{0} C . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

The longest side of a triangle is twice the shortest side, and the third side is 2 longer than the shortest side. If the perimeter of the triangle is more than 166, then find the minimum length of the shortest side.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t t h e l e n g t h o f t h e s h o r t e s t s i d e b e x c m \\ ∴ L e n g t h o f t h e l o n g e s t s i d e = 2 x c m \\ a n d l e n g t h o f t h e t h i r d s i d e b e (x + 2) c m \\ P e r i m e t e r o f t h e t r i a n g l e = x c m + 2 x c m + (x + 2) c m = (4 x + 2) c m \\ A s p e r t h e c o n d i t i o n o f t h e q u e s t i o n, \\ P e r i m e t e r > 166 c m \\ \Rightarrow 4 x + 2 > 166 \Rightarrow 4 x > 166 - 2 \\ \Rightarrow 4 x > 164 \Rightarrow x > 41 c m \\ H e n c e, t h e minimum l e n g t h o f t h e s h o r t e s t s i d e o f t h e t r i a n g l e i s 41 c m . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

A solution is to be kept between $4 0^{\circ} C$ and $4 5^{\circ} C$ . What is the range of temperature in degrees Fahrenheit if the conversion formula is $F = \frac{9}{5} C + 32 ?$

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} G i v e n t h a t t h e r a n g e o f t e m p e r a t u r e o f t h e s o l u t i o n i s 4 0^{0} C a n d 4 5^{0} C \\ F o r m u l a o f c o n v e r s a t i o n i s F = {\frac{9}{5}}^{0} C + 3 2^{0} \\ \Rightarrow F - 3 2^{0} = {\frac{9}{5}}^{0} C \Rightarrow^{0} C = \frac{5}{9} (F - 3 2^{0}) \\ 4 0^{0} <^{0} C < 4 5^{0} \\ \Rightarrow 4 0^{0} < \frac{5}{9} (F - 3 2^{0}) < 4 5^{0} \Rightarrow 4 0^{0} \times \frac{9}{5} < F - 3 2^{0} < 4 5^{0} \times \frac{9}{5} \\ \Rightarrow 7 2^{0} < F - 3 2^{0} < 8 1^{0} \Rightarrow 7 2^{0} + 3 2^{0} < F < 8 1^{0} + 3 2^{0} \\ \Rightarrow 10 4^{0} < F < 11 3^{0} \\ H e n c e, t h e r e q u i r e d r a n g e i s 10 4^{0} F t o 11 3^{0} F . \end{array}$

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9 months ago

Maths NCERT Exemplar Solutions Class 11th Chapter Six Exemplar Solution

A solution of 9% acid is to be diluted by adding 3% acid solution to it. The resulting mixture is to be more than 5% but less than 7% acid. If there are 460 liters of the 9% solution, how many liters of the 3% solution will have to be added?

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t x l i t r e s o f 3 % s o l u t i o n b e a d d e d t o 460 l i t r e s o f 9 % . \\ ∴ T o t a l a m o u n t o f m i x t u r e = (460 + x) l i t r e s \\ G i v e n t h a t t h e a c i d c o n t e n t s i n t h e r e s u l t i n g m i x t u r e i s m o r e t h a n 5 % b u t l e s s t h a n 7 % a c i d . \\ ∴ 5 % o f (460 + x) < 460 \times \frac{9}{100} + \frac{3}{100} \times x < 7 % o f (460 + x) \\ \Rightarrow \frac{5}{100} (460 + x) < \frac{4140 + 3 x}{100} < \frac{7}{100} (460 + x) \\ \Rightarrow 5 (460 + x) < 4140 + 3 x < 7 (460 + x) \\ \Rightarrow 2300 + 5 x < 4140 + 3 x < 3220 + 7 x \\ \Rightarrow 2300 + 5 x < 4140 + 3 x a n d 4140 + 3 x < 3220 + 7 x \\ \Rightarrow 5 x - 3 x < 4140 - 2300 a n d 3 x - 7 x < 3220 - 4140 \\ \Rightarrow 2 x < 1840 a n d - 4 x < - 920 \\ \Rightarrow x < \frac{1840}{2} a n d 4 x > 920 \\ \Rightarrow x < 920 a n d x > \frac{920}{4} ∴ x > 230 \\ H e n c e, t h e r e q u i r e d a m o u n t o f a c i d s o l u t i o n i s m o r e t h a n 230 l i t r e s a n d l e s s t h a n 920 l i t r e s . \end{array}$

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