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New Question

5 months ago

0 Follower 1 View

M
Ms Shruti Gupta

Contributor-Level 10

The total estimated cost of pursuing a BTech degree at NIT Jalandhar in 2025 ranges between INR 5.38 Lacs and INR 8.96 Lakh. Here is a breakdown:

  • Tuition fee: INR 2.5 Lacs - INR 5 Lakh
  • Accommodation charges (hostel and mess): INR 2.1 Lacs - INR 2.79 Lakh
  • Miscellaneous fees (library, laboratory, examination, registration, and administrative services): INR 78,000 - INR 1.17 Lakh

New Question

5 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

A = 1/3 [ 1; 1 ω ω² 1 ω² ω ]
A² = A * A = 1/9 [ . ]
(The calculation in the image shows A² is the identity matrix, let's verify)
A² leads to I (Identity matrix).
So A² = I.
A³ = A² * A = I * A = A.
A? = (A²)² = I² = I.
A³? = (A²)¹? = I¹? = I.

New Question

5 months ago

0 Follower 1 View

M
Ms Shruti Gupta

Contributor-Level 10

The tuition fee for the four-year BTech programme at NIT Jalandhar in 2025 ranges between INR 2.5 Lacs - INR 5 Lakh. This fee is payable semester-wise throughout the course duration. Students are required to pay the first instalment of tuition fees to confirm their admission.

New Question

5 months ago

0 Follower 2 Views

N
Nishtha Surbhi

Contributor-Level 7

Here are five the highest paying jobs in Singapore for Indians with their approximate annual salaries (SGD):

Job TitleAverage Annual Salary (SGD)
Regional Sales Director218,000
Finance Director200,000
Full Stack Developer78,000+
IT Cybersecurity Specialist473,000 (USD 350,000 approx)
Managing Director (Banking & Finance)675,000 (USD 500,000 approx)

New Question

5 months ago

0 Follower 5 Views

A
Atul Arora

Contributor-Level 9

Today Nursing is one of highest demanding professions worldwide. You can measure importance of a Nursing course by fact that there are only 1.9 Nurses per 1,000 people far below WHO's recommendation of a ratio of 3 nurses per 1,000.

Nurses are centre of any healthcare facility across globe not only providing care to patients but also assisting other healthcare professionals helping medical system run smoothly.

New Question

5 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

y = √ (2cos²α / (sinα cosα) + 1/sin²α)
y = √ (2cotα + cosec²α)
y = √ (2cotα + 1 + cot²α) = √ (1 + cotα)²) = |1 + cotα|.
Given α is in a range where 1+cotα is negative, y = -1 - cotα.
dy/dα = - (-cosec²α) = cosec²α.
At α = 5π/6, dy/dα = cosec² (5π/6) = (1/sin (5π/6)² = (1/ (1/2)² = 2² = 4.

New Question

5 months ago

0 Follower 1 View

K
Krishnendu Kumar

Contributor-Level 10

NIELIT Calicut offers M.Tech in three specialisations. The names of the offered specialisations are  Embedded Systems,  Electronics Design and Technology, and  Automotive Electronics. The eligibility requirements and admission process of every offered specialsiations are similar. Moreover, candidates having a valid GATE score shall be given preference for admission and are eligible for a scholarship from AICTE. 

New Question

5 months ago

0 Follower 1 View

A
abhishek gaurav

Contributor-Level 9

Eligibility for BTech at Dr. Babasaheb Ambedkar Technological University involves passing Class 12 with Physics, Chemistry, and Mathematics as mandatory subjects. The students should have secured minimum 60% marks in aggregate to apply. Admission is given only on the basis of valid JEE Main or MHT CET marks. Candidates must also achieve the cutoff while undergoing counselling for final selection.

New Question

5 months ago

0 Follower 9 Views

R
Raj Pandey

Contributor-Level 9

Let z = αi + βj be a complex number & √3i + j = (√3 + i) where I = √-1.
|z| = |z - (√3 + i)| and |z| = |√3 + i| = 2.
This implies z lies on the perpendicular bisector of the segment from 0 to √3+i and on a circle of radius 2 centered at the origin.
z = (√3 + i) ( (1+i)/√2 )
z = (1/√2) [ (√3 - 1) + I (√3 + 1)]
∴ α = (√3 - 1)/√2, β = (√3 + 1)/√2
Area of required triangle = (1/2) * base * height = (1/2) * |α| * |β| * 2 (This seems to be area of triangle with vertices 0, z, and another point)
The provided calculation:

...more

New Question

5 months ago

0 Follower 20 Views

A
alok kumar singh

Contributor-Level 10

Given Re (z-1)/ (2z+i) = 1, where z = x + iy.
(z-1)/ (2z+i) = [ (x-1) + iy] / [2x + I (2y+1)]
To rationalize, multiply the numerator and denominator by the conjugate of the denominator [2x - I (2y+1)].
Numerator = [ (x-1) + iy] * [2x - I (2y+1)] = 2x (x-1) - I (x-1) (2y+1) + i2xy + y (2y+1)
Real part of the numerator = 2x (x-1) + y (2y+1).
Denominator = (2x)² + (2y+1)².
Re (z-1)/ (2z+i) = [2x (x-1) + y (2y+1)] / [ (2x)² + (2y+1)²] = 1.
2x² - 2x + 2y² + y = 4x² + 4y² + 4y + 1.
0 = 2x² + 2y² + 2x + 3y + 1.
So, 2x² + 2y² + 2x + 3y + 1 = 0.

New Question

5 months ago

0 Follower 1 View

A
abhishek gaurav

Contributor-Level 9

Admission to the BTech course of Dr. Babasaheb Ambedkar Technological University is on the basis of a valid JEE Main score. Maharashtra state students also get a chance through scores in MHT CET. The university makes merit lists as per ranks in entrance exams. Better scores enhance the possibility of securing the desired specialisation.

New Question

5 months ago

0 Follower 2 Views

A
abhishek gaurav

Contributor-Level 9

The BTech programme of Dr. Babasaheb Ambedkar Technological University is a four-year full-time course. The course is provided in 9 different specialisations in Engineering. The admission is strictly through entrance exam performance. Eligibility and cutoff criteria have to be met by students to get a seat.

New Question

5 months ago

0 Follower 1 View

A
abhishek gaurav

Contributor-Level 9

The Dr. Babasaheb Ambedkar Technological University offers the BArch programme at the UG level. The course is offered in both four-year and five-year duration courses. Architectural design, planning, and associated fields are trained in by students during the programme. The intake is only made to qualified candidates who meet both academic and entrance examination criteria.

New Question

5 months ago

0 Follower 1 View

S
Saumya Shukla

Contributor-Level 10

Candidates applying for Uttar Pradesh University of Medical Sciences BSc must be Class 12 or equivalent examination pass. The qualifying exam should have been passed from a recognised board or authority. UPUMS may prescribe a minimum aggregate requirement as well. During form filling and admission, candidates must have the important documents as a proof of eligibility. 

New Question

5 months ago

0 Follower 2 Views

A
abhishek gaurav

Contributor-Level 9

Admission to the BArch programme of Dr. Babasaheb Ambedkar Technological University is entirely merit-based on the NATA exam. The candidates need to secure the qualifying score in NATA for being eligible for admission. No other alternative test is accepted by the university for BArch. Final selection is done through counselling and allotment of seats.

New Question

5 months ago

0 Follower 1 View

A
abhishek gaurav

Contributor-Level 9

To take admission in BArch at Dr. Babasaheb Ambedkar Technological University, students must pass Class 12 with Mathematics as a mandatory subject. At least 50% aggregate is a must for general category students. SC, ST, and PwD Maharashtra State candidates require at least 45%. Also, students must possess a valid NATA score for admission.

New Question

5 months ago

0 Follower 3 Views

T
Tanisha Pandey

Contributor-Level 10

The primary eligibility requirements for admission to the M.Tech course at NIELIT Calicut are that applicants must complete their BTech/ BE/ MSc course from a relevant stream with an aggregate of 60% (54% SC/ ST/ PwD). Moreover, the selection process is based on applicants' achieved scores in GATE, followed by a counselling process. Moreover, vacant seats can be filled by Non-GATE applicants from Kerala state based on the nativity certificate and merit. 

New Question

5 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

dy/dx + 2y tan (x) = sin (x)
I.F. = e^ (∫2tan (x)dx) = e^ (2ln (sec (x) = sec² (x)
Solution is y sec² (x) = ∫sin (x)sec² (x)dx = ∫sec (x)tan (x)dx
⇒ y sec² (x) = sec (x) + c
y (π/3) = 0 ⇒ 0 * sec² (π/3) = sec (π/3) + c ⇒ 0 = 2 + c ⇒ c = -2.
∴ y = (sec (x) - 2) / sec² (x)
Now let g (t) = (t - 2)/t² = 1/t - 2/t² for |t| ≥ 1.
g' (t) = -1/t² + 4/t³
g' (t) = 0 ⇒ t = 4.
g' (t) = 2/t³ - 12/t? g' (4) < 0, hence maximum.
∴ g (t)max = g (4) = (4 - 2)/4² = 2/16 = 1/8.

New Question

5 months ago

0 Follower 9 Views

R
Rashmi Srivastava

Contributor-Level 9

Hi,

Candidates should know that avg salary can be different according to company, job and location. A registered nurse can earn around 4.3 LPA (approx). 

But this salary can be different according to different hospitals too. Like Manipal Hospitals offers INR 3.9 LPA to Nurses, King Fahad Specialist Hospital offers INR 3.4 LPA, Apollo offers INR 3 LPA but under Ministry of Health one can get INR 12.5 LPA.

Hope this answer helps!

New Question

5 months ago

0 Follower 1 View

H
Himanshu Singh

Contributor-Level 10

The medium of instruction for the BA at DDE Pondicherry University is English. All study materials, lectures, assignments, and examinations are delivered in English to ensure consistency and accessibility for students from diverse academic and regional backgrounds.

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