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Comparing E = 20 cos (2 × 10¹⁰ t – 200x) V/m to

$E=E_{0}cos\left(\omega t-kx\right)v/m$              

$\omega =2\times 10^{10},K=200$               

Speed = $\frac{2\times 10^{10}}{200}=10^{8}m/s$  

R.I. $=\frac{C}{speed}=\frac{3\times 10^8}{10^8}=3$  

$NowR.I.=\sqrt[]{{\epsilon }_r{\mu }_r}$

$3=\sqrt[]{{\epsilon }_r\times 1}$

${\epsilon }_r=9$              

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Capacitor makes potential difference constant.

To pursue a BSc from Ajeenkya DY Patil University Seamedu, students must meet the specified eligibility criteria for their chosen specialisation. Generally, the required eligibility crtieria for the BSc programme is that students must have cleared their Class 12 with 50% aggregate marks from a recognised board.

Using faraday's law magnetic field should be outward and decreasing with time

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Work done is equal to change in K.E.

$So{W}_1+W_2=\frac{1}{2}M{\left(0.8\sqrt[]{gh}\right)}^2-0$ W₁ ^-> work done by mg

$mgh+W_2=\frac{1}{2}m\times 0.64gh$  W₂ -> work done by air friction

$W_2=0.32mgh-mgh=-0.68mgh$              

W₂ = -0.68 mgh

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BSc programme at Ajeenkya DY Patil University Seamedu typically spans three to four years. The duration may vary depending on the specialisation you choose. This undergraduate course is designed to give students a comprehensive foundation in creative fields, preparing them for a successful career in the media and entertainment industry.

Students should prepare complete syllabus when they have time to prepare. However, you can use the list of highweightage chapters in last minute revision for scoring well.

• The p-Block Elements: This chapter holds a high weightage of 8–10 marks. (in the latest syllabus this is deleted)

• Aldehydes, Ketones, and Carboxylic Acids: This chapter contributes around 8–10 marks.

• Biomolecules: This chapter accounts for around 8 marks.

• Chemical Kinetics: This chapter holds a high weightage of 5-6 marks. 

• The d- and f-Block Elements: This chapter contributes around 5-6 marks.

• Amines: This chapter contributes around 5-6 marks.

$LHS=\underset{x\to 0^{-}}{lim}f\left(x\right)=\underset{h\to \infty }{lim}\frac{-1}{h}ln\left(\frac{1-\frac{h}{a}}{1+\frac{h}{b}}\right)=\underset{h\to 0}{lim}\frac{ln\left(1-\frac{h}{a}\right)}{a\left(\frac{-h}{a}\right)}+\underset{h\to 0}{lim}\frac{ln\left(1+\frac{h}{b}\right)}{b\left(\frac{h}{b}\right)}=\frac{1}{a}+\frac{1}{b}.............\left(i\right)$

$RHS=\underset{x\to 0^{+}}{lim}f\left(x\right)=\underset{x\to 0}{lim}\frac{cos2x-1}{x^2+1-1}\left(\sqrt[]{x^2+1}+1\right)=\underset{x\to 0}{lim}\frac{-2si{n}^{x}x}{x^2}\times 2=-4...............\left(ii\right)$

$and\underset{x\to 0}{lim}f\left(x\right)=k.............\left(iii\right)$

$f\left(0^{-}\right)=f\left(0^{+}\right)=f\left(0\right)$

$\Rightarrow \frac{1}{a}+\frac{1}{b}=-4=k$

From (i), (ii) and (iii) we get $\therefore \frac{1}{a}+\frac{1}{b}+\frac{4}{k}=k+\frac{4}{k}=-4-1=-5$

Time period T = 2π $\sqrt[]{\frac{l}{g_{eff}}}$

$\Rightarrow T_i=T=2\pi \sqrt[]{\frac{l}{g}}$    

$\Rightarrow T_f=T\text{'}=2\pi \sqrt[]{\frac{4l/3}{g\left(1-\frac{\rho }{\sigma }\right)}}=2\pi \sqrt[]{\frac{16l}{9g}}$

$\Rightarrow T\text{'}=\frac{4}{3}T$

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The institute offers the DPharma course. Candidates must complete Class 12 in Science stream with Physics, Chemistry, Biology/Mathematics. Once selected, candidates must pay the programme fee to confirm their seats in the institute. Admission to all the courses is merit-based.