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New Question

11 months ago

0 Follower 65 Views

A
alok kumar singh

Contributor-Level 10

1.8 (a) The situation is represented in the following figure.

O is the midpoint of AB, hence OA = OB = 10 cm = 10×10-2 m2

The electric field at O caused by the charge at A is given by

 

 E1 =4π?0×qAr2 along OB and the electric field at O caused by the charge at B is given by,

 E2 =14π?0×qBr2along OB

where ?0= Permittivity of free space = 8.854 ×10-12
 C2N-1 m - 2

Net electric field at point O, E = E1+E2 = 14π?0r2×qA+qB

 14×π×8.854×10-12×(10×10-2)2 ×3×10-6+3×10-6 

=5.39 ×106 NC-1 along OB

 

(b) A test charge of amount 1.5×10-9  C is placed at the midpoint O

So the force experienced by the test charge, F = q ×E

= 1.5 ×10-9× 5.39×106 
 N = 8.088 ×10-3
 N

This force is directed along the line OA, this is because th

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11 months ago

0 Follower 2 Views

A
Anya Vimal

Contributor-Level 10

Yes, the Dr. Shakuntala Misra National Rehabilitation University does follow a seat reservation policy for all its programmes, including BBA. The university reserves a minimum of 50% of seats across all academic programmes for students with disabilities, of which 25% of the total seats are reserved for visually impaired students. These seat reservations ensure that all students have equal opportunities to secure a seat in their desired course.

New Question

11 months ago

1 Follower 116 Views

A
alok kumar singh

Contributor-Level 10

1.7

(a) An electrostatic field line is a continuous curve because a charge experiences a continuous force when traced in an electrostatic field. The field line cannot have sudden breaks because the charge moves continuously and does not jump from one point to another.

(b) The electric field intensity will show two directions at that point where two filed lines crosses. This is not possible. Hence they do not cross.

New Question

11 months ago

0 Follower 3 Views

New Question

11 months ago

0 Follower 1.5k Views

A
alok kumar singh

Contributor-Level 10

1.6

 

In the adjoining figure ABCD is a square with sides AB = BC = CD = DA = 10 cm

Diagonals, AC = BD  = 102+102 = 102cm

AO = OC = DO = BO = 5 2 cm

At the centre of the square ABCD, O, a charge of 1 μCisplaced.

The force of repulsion between the charges placed at A and at O is equal in magnitude but opposite in direction between the charges placed at point C and centre O. Similarly ,the force of attraction between the charges placed at B & O and D & O will be equal in magnitude but opposite in direction. These charges will cancel each other.

Hence, the net charge at centre O will be zero.

Here is a deeper explanation. 

What you just saw is the us

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11 months ago

0 Follower 9 Views

N
Nallamothu Arun Kumar

Contributor-Level 6

Jagannath Institute of Engineering and Technology, Cuttack (JIET) is a private engineering college established in 1996, located at Jagatpur Industrial Estate, Phase II, Cuttack – 754021, affiliated to Biju Patnaik University of Technology (BPUT) and approved by AICTE. The institute offers B.Tech programs in Computer Science, Electronics & Telecom, and Mechanical Engineering, each typically with seats of 60 to 120 and a per? year fee of around ?46,000. Campus facilities include hostels, library, labs, cafeteria, sports complex, WiFi, and medical centre.

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11 months ago

0 Follower 73 Views

A
Ashmit Saini

Beginner-Level 5

So, Maharashtra 10th Boards are usually declared in May or early June.

And for this year 2025, you can expect the results to be released in last week of May. You can view the official website for more details.

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11 months ago

0 Follower 5 Views

V
Vidhi Jain

Contributor-Level 10

The average B Tech Aerospace Engg. tuition fees is approximately INR 3 lakh to INR 15 lakh, which varies on the basis of the college where you're planning to study the course, the college location, NIRF ranking, and placement records. Also, you need to pay extra amount for hostel accommodation (if you're staying in the college hostel), admission application, semester exam registration, lab work, etc.

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11 months ago

0 Follower 117 Views

A
alok kumar singh

Contributor-Level 10

Ans.1.5 When two bodies are rubbed against each other, it produces charges of equal magnitude in both the bodies but of opposite in nature. Hence the net charges of the two bodies are zero. When a glass rod is rubbed with a silk cloth, similar phenomena occur. This is as per the law of conservation of energy.

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11 months ago

0 Follower

N
Nikita Pandey

Contributor-Level 10

The intake of seats in DSMNRU BBA is determined based on various factors. However, the university provides limited seats for its BBA programme, which ensures that only eligible and deserving students are shortlisted for this programme. Below are the key factors on which Dr. Shakuntala Misra National Rehabilitation University's BBA seat intake is determined, which candidates should consider:

  • Availability of Seats
  • Number of students who applied
  • Number of shortlisted students
  • Academic record
  • Performance in the entrance exam

New Question

11 months ago

0 Follower 376 Views

A
alok kumar singh

Contributor-Level 10

1.4 

(a) Electric charge of a body is quantized, this means that only integers (1,2,3, ….n) number of electrons can be transferred from one body to the other. Charges are not transferred in fraction. Hence, a body possesses total charge only in integers.

(b) In macroscopic i.e. large scale charges, the charges used are huge as compared to the electric charge of electrons or protons. Therefore, it is ignored and it is considered that electric charge is continuous.

New Question

11 months ago

0 Follower

H
Himanshu Singh

Contributor-Level 10

Yes, MIT International School of Broadcasting and Journalism BA is a decent option for students seeking media education. It offers a balanced mix of theory and practical training, with opportunities to explore journalism, advertising, and digital media through a structured curriculum and relevant industry exposure.

New Question

11 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

3.28 The graph has a non-uniform slope between the intervals t1 and t2 – the graph is not a straight line. The equations (a), (b), and (e) do not describe the motion of the particle. Only the relations (c), (d) and (f) are correct.   

New Question

11 months ago

0 Follower 697 Views

V
Vishal Baghel

Contributor-Level 10

3.27

(a) Distance travelled by the particle between t = 0 s and t = 10 s is the area of the triangle = (1/2) x base x height = (1/2) x 10 x 12 = 60 m

The average speed of the particle is 60/10 m/s = 6 m/s

 

(b) Distance travelled by the particle between t = 2 s and t = 6 s

Let S1 be the distance travelled by the particle in time 2 to 5 s and S2 be the distance travelled between 5 to 6s.

For the motion  from 0 to 5 sec, u = 0, t = 5, v = 12 m/s

From the equation v = u + at we get a = (v-u)/t = 12/5 = 2.4 m/s2

Distance covered from 2 to 5 sec, S1 = distance covered in 5 s – distance covered in 2 s

From the equation s = ut + at2 we

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New Question

11 months ago

0 Follower 1 View

V
Vidhi Jain

Contributor-Level 10

The syllabus for the BTech Aerospace Engineering program includes both. Theory-based learning in the classroom and practical training via lab sessions and projects. The coursework is planned out in a manner striking a balance of both, with various internship opportunities and informative workshops for you to learn, experiment, and explore as much as possible. The syllabus would seem exciting to aviation enthusiasts with an engineering mindset. 

New Question

11 months ago

0 Follower 4 Views

A
Akshay Nigam

Beginner-Level 3

The fee is INR 3.8 Lacs after all concession and you should consider the total number of placements, quality of teaching, and increase with other universities or across different institutes when comparing MIT International School of Broadcasting Journalism BA program

New Question

11 months ago

0 Follower 114 Views

V
Vishal Baghel

Contributor-Level 10

3.26 For the first stone,

Initial velocity, u1 = 15m/s, acceleration, a = -g = -10 m/s

From the relation  s1=s0+u1t+ (1/2)at2 where

s0 = cliff height, s1 = total height of the fall of the first stone, we get

s1 = 200 + 15t – 5t………. (1)

When the stone hit the floor, s1 = 0, so the equation (1) becomes

0 = 200 +15t - 5t2 = t2 -3t – 40 = (t-8) (t+5) = 0

So t = 8s or -5s

Since the stone was thrown at t=0, so t cannot be –ve. Hence t = 8s

For the second stone,

Initial velocity, u1 = 30 m/s, acceleration, a = -g = -10 m/s

From the relation  s2=s0+u1t+ (1/2)at2 where

s0 = cliff height, s2= total height of the fall of the s

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New Question

11 months ago

0 Follower 94 Views

V
Vishal Baghel

Contributor-Level 10

3.25 Speed of the child = 9 km/h

Speed of belt = 4 km/h

(a) When the boy runs in the direction of motion of the belt, then the speed of the child observed by the stationary observer = 9 + 4 = 13 km/h

 

(b) When the boy runs in the opposite direction of motion of the belt, then the speed of the child observed by the stationary observer = 9-4 = 5 km/h

 

(c) Distance between the parents = 50 m = 0.05km

Speed of the boy, as observed by both parents = 9 km/h.

Time required by the boy to move to any parent = 0.05 / 9 h = 20s

New Question

11 months ago

0 Follower 1 View

T
Tasbiya Khan

Contributor-Level 10

: Listed below is the fee range of top BMLT colleges in Delhi NCR:

Fee Range

Top BMLT Colleges

Less than INR 1 lakh

4 (Pt. Bhagwat Dayal Sharma Post Graduate Institute of Medical Sciences, Sun Rise University, Shri Vishwakarma Skill University, etc.)

INR 1-2 lakh

8 (Jamia Millia Islamia, Delhi Pharmaceutical Sciences and Research University, Galgotias University, etc.)

INR 2-3 lakh

13 (IP University, SVSU, IIMT University, etc.)

INR 3-5 lakh

19 (Jamia Hamdard, SGT University, Gurgaon, ICRI - Jagannath University, Delhi, etc.)

INR > 5 lakh

6 (Amity University, Noida, Sharda School of Allied Health Sciences, GD Goenka University, etc.)

New Question

11 months ago

0 Follower 6 Views

N
Nallamothu Arun Kumar

Contributor-Level 6

With 38 marks in CUET PG, it will be very difficult to get seat in universities because their cut offs are much higher. But you can still try for some of the smaller or new universities where cut off is low, and also state universities or private colleges which accept CUET PG score. Your chances are better in less competitive courses or in universities located in north? east or central region where seat demand is less.

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