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Students can find the latest BSc admission dates and deadlines on the official Risali Institute of Management website, specifically in the “Admissions” or “BSc programme” sections. The site is regularly updated with timelines for applications, document submissions, and merit listing

The SKCET average package stood at INR 6.20 LPA. Check the table below to know more:

1° →  60’

⇒ 60’ → 10°

$60\text{'}\to {\frac{\pi }{180}}^C$

$\theta =\frac{\pi \times 2\times 10^3}{180\times 3600}$          

L = 1.5 × 10¹¹ m

$D=L\theta =1.5\times 10^{11}\times \frac{\pi }{180\times 3600}\times 2\times 10^3=1.45\times 10^{9}m$    

Yes, BSc admissions for 2025 at Risali Institute of Management are currently open. Interested and eligible students should apply early and check the official website regularly for important dates, application deadlines, and updates regarding the admission process.

This is an objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat\underset{x\to \frac{\pi }{4}}{lim}\frac{se{c}^{2}x-2}{tanx-1}\\ =\underset{x\to \frac{\pi }{4}}{lim}\frac{1+ta{n}^{2}x-2}{tanx-1}=\underset{x\to \frac{\pi }{4}}{lim}\frac{ta{n}^{2}x-1}{tanx-1}=\underset{x\to \frac{\pi }{4}}{lim}\frac{\left(tanx+1\right)\left(tanx-1\right)}{\left(tanx-1\right)}\\ =\underset{x\to \frac{\pi }{4}}{lim}\left(tanx+1\right)=tan\frac{\pi }{4}+1=1+1=2.\\ Hence,thecorrectoptionis\left(d\right).\end{array}$

The number of offers provided during SKCET Placements has not been released yet. Check out the other placement highlights recorded during the placement drive:

The SKCET the highest package offered to students during the 2025 placement drive stood at INR 47 LPA. The following table showcases the highest package offered in SKCET placements 2025: 

As per the official record, overall 221 recruiters participated during SKCET placements 2025. Check out the data present below to know more:

The number of students placed during SKCET has not been released yet. Once out it will be updated on this page. Meanwhile, students can refer to the placement rate present in the table below:

For the female candidate, the last round cutoff ranks for IIT Bombay varied between 369 and 13761 for BTech admission among the General category under the All India quota. The cutoff ranks vary for different rounds, courses, specialisations, categories, and genders. For IIT Bombay, the category-wise cutoff ranges for the last round are tabulated below under the AI quota for female-only candidates. 

Sol:

$\begin{array}{l}Giventhat\underset{x\to 0}{lim}\frac{sinx}{\sqrt[]{x+1}-\sqrt[]{1-x}}\\ =\underset{x\to 0}{lim}\frac{sinx}{\sqrt[]{x+1}-\sqrt[]{1-x}}\times \frac{\sqrt[]{x+1}+\sqrt[]{1-x}}{\sqrt[]{x+1}+\sqrt[]{1-x}}\\ =\underset{x\to 0}{lim}\frac{sinx\left[\sqrt[]{x+1}+\sqrt[]{1-x}\right]}{x+1-1+x}=\underset{x\to 0}{lim}\frac{sinx\left[\sqrt[]{x+1}+\sqrt[]{1-x}\right]}{2x}\\ =\frac{1}{2}.\underset{x\to 0}{lim}\frac{sinx}{x}\left[\sqrt[]{x+1}+\sqrt[]{1-x}\right]\\ Taking\text{\hspace{0.17em}limit},weget\\ =\frac{1}{2}\times 1\times \left[\sqrt[]{0+1}+\sqrt[]{1-0}\right]=\frac{1}{2}\times 1\times 2=1\\ Hence,thecorrectoptionis\left(c\right).\end{array}$

This is an objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat\underset{x\to 0}{lim}\frac{cosec x-cot x}{x}\\ =\underset{x\to 0}{lim}\frac{\frac{1}{sinx}-\frac{cos x}{sinx}}{x}=\underset{x\to 0}{lim}\frac{1-cosx}{xsinx}=\underset{x\to 0}{lim}\frac{2si{n}^2\frac{x}{2}}{x.2sin\frac{x}{2}cos\frac{x}{2}}\\ =\underset{x\to 0}{lim}\frac{sin\frac{x}{2}}{xcos\frac{x}{2}}=\underset{x\to 0}{lim}\frac{tan\frac{x}{2}}{x}=\underset{x\to 0}{lim}\frac{tan\frac{x}{2}}{2\times \frac{x}{2}}=\frac{1}{2}\times 1=\frac{1}{2}\left[?\underset{x\to 0}{lim}\frac{tanx}{x}=1\right]\\ Hence,thecorrectoptionis\left(c\right).\end{array}$

The SKCET reports successful placements over the years. At present, 221 companies took part in the placements 2025. For more information on SKCET placements 2025 refer to the table below:

B.E. in Computer Science and Engineering is one of the most popular UG level courses of Alva's College, Moodbidire (constituent college of Mangalore University). The university offers BTech in Computer Science and Engineering in full-time mode for the duration of 4 years in UG level. The university offers the respective courses on the basis of 45% aggregate in Class 12 with Physics and Maths as compulsory subject. The university considers KCET scores for final admission. Furthermore, the BTech in Computer Science and Engineering graduates have received the median package of worth INR 2.82 Lakh.  

The graduating students of SKCET are reported to have been placed in good companies. Check out the table below to know more about SKCET placement statistics:

The SKCET placement rate stood at 90.9%. The institute is known for its good placements that has been successful in placing graduating students over the years. Check out the table below for more information on SKCET placements for the year 2025:

This is an objective Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat\underset{\theta \to 0}{lim}\frac{1-cos4\theta }{1-cos6\theta }\\ =\underset{\theta \to 0}{lim}\frac{2si{n}^{2}2\theta }{2si{n}^{2}3\theta }\left[?1-cos\theta =2si{n}^2\frac{\theta }{2}\right]\\ =\underset{\theta \to 0}{lim}\frac{si{n}^{2}2\theta }{si{n}^{2}3\theta }=\underset{\theta \to 0}{lim}{\left[\frac{sin2\theta }{sin3\theta }\right]}^2=\underset{\begin{array}{l}\theta \to 0\\ 2\theta \to 0\\ 3\theta \to 0\end{array}}{lim}{\left[\frac{\frac{sin2\theta }{2\theta }\times 2\theta }{\frac{sin3\theta }{3\theta }\times 3\theta }\right]}^2\\ ={\left[\frac{2\theta }{3\theta }\right]}^2={\left(\frac{2}{3}\right)}^2=\frac{4}{9}\\ Hence,thecorrectoptionis\left(a\right).\end{array}$

The SKCET is showing an impressive placement record as of now. A total of companies are taking part in the placements 2025. Check out the table for more information on SKCET placements 2025