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As per unofficial source, Conestoga College acceptance rate is 85%. This makes it highly easy to secure admission to this Canadian college. While selecting students at Conestoga, it checks academic factors such as school scores, class rank, academic GPA, recommendations, and application essay.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\frac{x^5-cosx}{sinx}\\ \frac{dy}{dx}=\frac{d}{dx}\left(\frac{x^5-cosx}{sinx}\right)\\ =\frac{sinx\frac{d}{dx}\left(x^5-cosx\right)-\left(x^5-cosx\right)\frac{d}{dx}\left(sinx\right)}{si{n}^{2}x}\left[quotientrule\right]\\ =\frac{sinx\left(5x^4+sinx\right)-\left(x^5-cosx\right)\left(cosx\right)}{si{n}^{2}x}\\ =\frac{5x^4.sinx+si{n}^{2}x-x^{5}cosx+co{s}^{2}x}{si{n}^{2}x}\\ =\frac{5x^4.sinx-x^{5}cosx+\left(si{n}^{2}x+co{s}^{2}x\right)}{si{n}^{2}x}=\frac{5x^4.sinx-x^{5}cosx+1}{si{n}^{2}x}\end{array}$

No, Abhinav College(Thane) does not offer B.Sc in Biotechnology.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\frac{3x+4}{5x^2-7x+9}\\ \frac{dy}{dx}=\frac{d}{dx}\left(\frac{3x+4}{5x^2-7x+9}\right)\\ =\frac{\left(5x^2-7x+9\right)\frac{d}{dx}\left(3x+4\right)-\left(3x+4\right)\frac{d}{dx}\left(5x^2-7x+9\right)}{{\left(5x^2-7x+9\right)}^2}\left[\text{\hspace{0.17em}Using}quotientrule\right]\\ =\frac{\left(5x^2-7x+9\right)\left(3\right)-\left(3x+4\right)\left(10x-7\right)}{{\left(5x^2-7x+9\right)}^2}\\ =\frac{15x^2-21x+27-30x^2+21x-40x+28}{{\left(5x^2-7x+9\right)}^2}\\ =\frac{-15x^2-40x+55}{{\left(5x^2-7x+9\right)}^2}\\ =\frac{55-40x-15x^2}{{\left(5x^2-7x+9\right)}^2}\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\left(secx-1\right)\left(secx+1\right)\\ =\left(se{c}^{2}x-1\right)\left[?a^2-b^2=\left(a-b\right)\left(a+b\right)\right]\\ =ta{n}^{2}x\left[?ta{n}^{2}x=se{c}^{2}x-1\right]\\ \frac{dy}{dx}=\frac{d}{dx}ta{n}^{2}x\\ =2tanx\frac{d}{dx}tanx=2tanx.se{c}^{2}x\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\left(3x+5\right)\left(1+tanx\right)\\ \frac{dy}{dx}=\frac{d}{dx}\left(3x+5\right)\left(1+tanx\right)\\ =\left(3x+5\right)\frac{d}{dx}\left(1+tanx\right)+\left(1+tanx\right)\frac{d}{dx}\left(3x+5\right)\left[\begin{array}{l}?\frac{d}{dx}\left[f\left(x\right).g\left(x\right)\right]\\ =f\left(x\right).g\text{'}\left(x\right)+g\left(x\right).f\text{'}\left(x\right)\end{array}\right]\\ =\left(3x+5\right)se{c}^{2}x+\left(1+tanx\right)\left(3\right)\\ =3xse{c}^{2}x+5se{c}^{2}x+3+3tanx\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety={\left(x+\frac{1}{x}\right)}^3\\ \frac{dy}{dx}=\frac{d}{dx}{\left(x+\frac{1}{x}\right)}^3\\ =\frac{d}{dx}\left(x^3+\frac{1}{x^3}+3x+\frac{3}{x}\right)\\ =\frac{d}{dx}\left(x^3+x^{-3}+3x+3.x^{-1}\right)=3x^2-3x^{-4}+3-3.x^{-2}\\ =3x^2-\frac{3}{x^4}+3-\frac{3}{x^2}\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=\left(\frac{x^4+x^3+x^2+x+1}{x}\right)\\ \therefore \frac{dy}{dx}=\frac{d}{dx}\left(\frac{x^4+x^3+x^2+x+1}{x}\right)\\ =\frac{d}{dx}\left(x^3+x^2+x+\frac{1}{x}\right)=3x^2+2x+1-\frac{1}{x^2}\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat\underset{x\to 1}{lim}\frac{x^4-1}{x-1}=\underset{x\to k}{lim}\frac{x^3-k^3}{x^2-k^2}\\ \Rightarrow 4{\left(1\right)}^{4-1}=\underset{x\to k}{lim}\frac{\left(x-k\right)\left(x^2+k^2+kx\right)}{\left(x-k\right)\left(x+k\right)}\\ \Rightarrow 4=\underset{x\to k}{lim}\frac{x^2+k^2+kx}{x+k}\Rightarrow 4=\frac{k^2+k^2+k^2}{2k}\\ \Rightarrow 4=\frac{3k^2}{2k}\Rightarrow 4=\frac{3}{2}k\Rightarrow k=\frac{8}{3}.\end{array}$

Centennial College has a vast alumni network with more than 200,000 members. The graduates of this college work at the companies like Amazon, Walmart Canada, BMO, Air Canada, etc. The top sectors where these graduates work are Business Development, Operations, Engineering, IT, and more. 

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat\underset{x\to 0}{lim}\frac{sinx-2sin3x+sin 5x}{x}\\ =\underset{x\to 0}{lim}\frac{sinx}{x}-\frac{2sin3x}{x}+\frac{sin 5x}{x}=\underset{x\to 0}{lim}\frac{sinx}{x}-\underset{3x\to 0}{lim}2\left(\frac{sin3x}{3x}\right)\times 3+\underset{5x\to 0}{lim}\left(\frac{sin 5x}{5x}\right)\times 5\\ =1-6+5=0.\end{array}$

Yes, you can be part of The Yoga Institute once you have completed Class 12 (particularly when it comes to study BA or any certificate course). Minimum eligibility criteria of these courses is Class 10 or 12. The admissions are based on merit and there is an application and selective procedure. Send in your documents accordingly.

The last date for admissions at The Yoga Institute for the 2025 academic year has not been officially announced yet. Applications will be accepted on a rolling basis until all available seats are filled. Applicants are advised to apply early through the official portal to avoid last-minute issues. Important updates regarding deadlines and seat availability are regularly posted on the institute’s website.

Yes, admission to The Yoga Institute 2025 is open to any course such as BA, MA, and other different certificate courses. All the interested individuals can apply online on the official web site of The Yoga Institute. It is a merit based admission and one should ensure that they are qualified before they apply.

Arka Jain University, including its online programs, attracts a diverse range of companies for recruitment. Some of the prominent recruiters include TCS, Wipro, Cognizant, IBM, Byju's, Tata Steel, Tata Motors, Tech Mahindra, Infosys, and companies in the healthcare sector like Dr. Lal Path Labs, Max Healthcare, Medanta, Fortis Hospital, Apollo Hospitals, and Manipal Hospitals.