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Yes, the Indian School of Business Management and Administration Chandigarh is now accepting applications for all courses for the 2025–2026 academic year. Applications are available on the college's official website for each program. Applicants can check the eligibility and selection requirements prior to applying to the course of their choosing.

IIIT Manipur cutoff 2025 has been released for the fourth round, for candidates seeking admission to BTech specialisations. The cutoff has been released across different categories belonging to the All India category. Among the General AI category, the closing ranks varied between 53865 and 65165. 

For candidates belonging to the OBC AI category, the closing ranks ranged between 18092 and 20878. Among the SC AI category, the cutoff ranks varied between 10365 and 11782. For more information on branch-wise, category-wise, and round-wise cutoff for IIIT Manipur, click here. 

The campus for known for its BTech placements and provides better campus selection as well. Check out the table for reference:

For admission to a BSc course of BIT Mesra, the aspirants must meet the eligibility requirements. Aspirants who are Class 12 or equivalent exam pass with at least 60% aggregate can apply. The candidates must hold the important documents for verification purposes as well. These are required at the time of admission for verification purposes.

The institute is known for providing good placements to its BTech graduating students.Check out the table below to know the key highlights of the JNIT placements 2024:

The institute provides good placement opportunities to its graduating students. Check out the table below to know the key highlights of the JNIT placements for BTech during 2024:

Students seeking to get admission into IBS Dehradun need to provide certain credentials. Students must ensure the validity of these documents as any discrepancy may cause an issue later. Find below the list of documents needed for IBS Dehradun application:

• Passport-size colored photograph
• Class 12 marksheet
• Graduation marksheet

The institute provides decent BTech placements. Check out the tabulated data given below to know more about JNIT placement for BTech during 2024:

BIT Mesra BSc fee structure is cumulative of multiple components, which are either one-time chargeable or have to be paid annually or semester-wise. The total tuition fees for the BSc programme range from INR 6.3 Lacs to INR 6.9 lakh. Students who get selected have to pay the first semester fees or the prescribed amount. It must also be noted that the given fee is as per the official website/ sanctioning body. It is still subject to changes and hence, is indicative.

During the 2024 placements, 100% BTech students secured placements. Check out the table below to know the key highlights of the JNIT placements 2024:

Mangalore University offers courses such as BSc in various specialisations for the duration of 3 years to 4 years in full-time mode. Admissions to the respective courses is offered on the basis of merit and requires for candidates to secure a minimum aggregate of 35% in Class 12 with valid scores in CBSE 12, Karnataka 2 PUC, ISC, KCET, UK 12. The university offers admission to BSc with an annual intake of 5400+ students. 

Dimension

RC → [T]

$\frac{L}{R}\to \left[T\right]$

$\sqrt[]{Lc}\to \left[T\right]$

$\frac{L}{C}\to$ dimensionless

The average package has not been released as of yet. Check out the highest package for reference:

The institute has been providing successful placements over the years to its BTech graduates. Check out the table below to know the key highlights of the JNIT placements during 2024:

${\overrightarrow{B}}_{Net}=\frac{{\mu }_0}{4\pi }\times 2\left[\frac{i_1}{d_1}-\frac{i_2}{d_2}\right]\left(-\widehat{k}\right)$

$=10^{-7}\times 2\left[\frac{4}{4}\times 100-\frac{2}{6}\times 100\right]\left(-\widehat{k}\right)$

$=2\times 10^{-5}\left[1-\frac{1}{3}\right]-\widehat{k}$

${\overrightarrow{B}}_{Net}=\frac{4}{3}\times 10^{-5}\left(-\widehat{k}\right)$                        

q = 3πc

$\overrightarrow{v}=2\widehat{i}+3\widehat{j}$

$\overrightarrow{F}=q\left(\overrightarrow{v}\times \overrightarrow{B}\right)$               

= $3\pi \left[\left(2\widehat{i}\times 3\widehat{j}\right)\times \frac{4}{3}\times 10^{-5}\left(-\widehat{k}\right)\right]$

$\overrightarrow{F}=4\pi \times 10^{-5}\left(-3\widehat{i}+2\widehat{j}\right)N$  

x = 3

The institute provides good placements to its graduating BTech students. Check out the table below to know the key highlights of the JNIT placements 2024: