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5 months agoContributor-Level 10
C (graphite) → C (diamond)
ΔH? = Δ? H° (graphite) - Δ? H° (Diamond) = -832.8 - [-834.8] = 2kJ/mole
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5 months agoContributor-Level 10
Yes, Patna University released a second merit list for MEET 2025 MEd admission on August 23, 2025. Candidates who were not selected in the first round could participate from August 25 to August 27, 2025.
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5 months agoNew Question
5 months agoContributor-Level 10
ppm of O? = (wt. of O? ) / (wt. of H? O) × 10?
= (10.3 mg) / (1.03 × 10? mg) × 10?
= 10ppm
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5 months agoContributor-Level 10
i = total no. of particles after dissociation/association / total no. of particle before dissociation/association
HA? H? + A? (Dissociation)
0.5a
2HA → (HA)? (Association)
0.5a/2
i = (a + 0.25a)/a = 125 x 10? ²
Ans. = 125
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5 months agoContributor-Level 10
The MEET 2025 admission process involves applying online, appearing for the entrance test, checking the result and merit list, and participating in counseling. Qualified candidates are selected based on merit for MEd admission at Patna University, following document verification and fee payment.
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5 months agoContributor-Level 10
Percentage packing fraction of diamond is 34% and number of particle per unit cell is 8.
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5 months agoContributor-Level 10
The MEET 2025 entrance exam for MEd was conducted on September 03, 2025. Now, Patna University is conducted merit-based admission for this course.
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5 months agoContributor-Level 10
BCl → B? + Cl?
B? + H? O? BOH + H? , K? = K? /K?
0.25 – –
(0.25 – x) x
Given, pH = 2.7 = [H? ] = 2 × 10? ³
∴ x²/ (0.25) = (10? ¹? )/K?
= 4 × 10? × 4 × K? = 10? ¹?
= K? = (1/16) × 10? = 6.25 × 10? ¹?
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5 months agoNew Question
5 months agoContributor-Level 10
Trans product is more stable than Cis. ( Trans product feel less repulsion due to opposite direction)
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5 months agoContributor-Level 10
BOD is the amount of oxygen required by bacteria to break down the organic matter present in a certain volume of sample of water.
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5 months agoGuide-Level 15
Candidates who have completed Class 12 from any recognised board with Physics & Mathematics as optional subjects with a minimum of 45% aggregate can apply for BSc (Hons) programmes at NMIT Bangalore. Aspirants must have relevant documents to prove their eligibility for verification at the time of admission.
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5 months agoContributor-Level 10
Polymer Monomers
Buna-N CH? = CH – CH = CH?
and
CH? = CH – CN
Neoprene H? C = C (Cl) – CH = CH?
Nylon-6, 6 Hexamethylenediamine + Adipic Acid
PHBV CH? – CH (OH) – CH – COOH
and
CH? – CH? – CH (OH) – CH? – COOH
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5 months agoContributor-Level 10
(A) Carbon monoxide – Haemoglobin
(B) Sulphur dioxide – Stiffness of flower buds
(C) Polychlorinated biphenyls – Carcinogenic
(D) Oxides of nitrogen – Metabolized by pyrus plants
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