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5 months agoContributor-Level 10
NIT Silchar CCMT cutoff 2025 for various rounds has been released for different categories of students. If you belong to the General AI category, the cutoff for all specialisations and rounds ranged from 360 to 526, wherein M.Tech. in Computer Science and Engineering was the most competitive. For the OBC AI and SC AI category candidates, the last round cutoff ranged from 317 to 486, and 231 to 328, wherein M.Tech. in Computer Science and Engineering and M.Tech. in Transportation Engineering were the toughest specialisations to crack, respectively. For more detailed cutoff results, M.Tech.4 here.
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5 months agoContributor-Level 10
MTech CSE cutoff 2025 was released for the year 2025, wherein the range was from 526 to 602, according to the last and first round cutoff for the General AI category. Please note that different categories will have different cutoffs accordingly; for example, the OBC AI category, the NIT Sikkim M.Tech cutoff 2025 ranged from 555 to 486. For the SC and ST AI quota, admissions were closed at 403 and 278, respectively. M.Tech admissions are based on GATE score, followed by the CCMT counselling process for NIT Silchar 2025.
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5 months agoNew Question
5 months agoBeginner-Level 5
Yes, DME Tripura conducts all rounds of Tripura NEET PG counselling in online mode. Although earlier, the last round, or the stray vacancy round used to be conducted in offline mode, but since the past few years, all rounds have been held in online mode only. Within each round of the Tripura NEET PG counselling process, the steps such as registration, choice filling, etc. are held in online mode, and the steps of the institute reporting or nomination collection is done in offline mode.
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5 months agoBeginner-Level 5
No. Candidates have to register on the official website and submit the application form to participate in Tripura NEET PG 2025 counselling in online mode. Only the eligible candidates will be allowed to register for Tripura NEET PG Counselling 2025.
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5 months agoBeginner-Level 5
There will be at least four rounds of counselling, including the mop-up round for seat allotment for the Tripura PG 2025 counselling process. However, the number of rounds may be extended based on the vacant seats, or other external factors like revision of cutoff or seat matrix.
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5 months agoContributor-Level 10
The total tuition fee for the BSc course at NTRUHS ranges from INR 3,200 to INR 67,500. The tuition fee mentioned here differs from university to affiliated college and specialisations selected by the students. Moreover, at the time of admission confirmation, applicants are required to pay a certain amount of the course tuition fee. The fee amount mentioned is sourced from the official website/sanctioning body and is subject to change. Therefore, it is indicative.
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5 months agoBeginner-Level 5
The merit list for Tripura NEET PG 2025 was released on November 24. DME Tripura releases separate merit lists for each round. Candidates could download the merit list from the official website or from Shiksha.com. The merit list includes information such as candidate name, application number, NEET PG rank, category, score obtained, among others.
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5 months agoBeginner-Level 5
Tripura NEET PG 2025 counselling is being held in an online mode, except for institute reporting. The registration, choice filling and locking rounds will be conducted in an online mode. Also, the release of the merit list and seat allotment result are done in online mode on the official website.
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5 months agoContributor-Level 10
The total tuition fee for BSc courses at KUHS ranges from INR 46,000 to INR 4.4 lakh, and the tuition fee for BSc at NTRUHS ranges from INR 3,200 to INR 67,500. Therefore, the fee structure of NTRUHS is more affordable than KUHS. The fee amount mentioned is sourced from the official website/sanctioning body and is subject to change. Therefore, it is indicative.
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5 months agoContributor-Level 9
The BFUHS BSc programme is offered in various specialisations, such as Medical Radiology & Imaging Technology, Radiotherapy Technology, Medical Technology, etc. NTRUHS also offers various specialisations in BSc courses. Check out the number of seats offered by each university and its affiliated colleges in the table below:
| University Name | BSc Seats |
|---|---|
| Baba Farid University of Health Science | 4,367 |
| N.T.R University of Health Sciences | 5,123 |
Therefore, NTR University of Health Sciences offers a greater number of seats in the BSc course compared to Baba Farid University of Health Sciences.
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5 months agoContributor-Level 10
After the NBS EHSLC exam date are out, the students can prepare for the exam accordingly. Knowing the NBSE HSLC exam dates in advance gives the students a clear idea of how many days left for the preparation of the exam. Using the NBSE 10th exam dates, the students should plan their daily study. They must complete the entire syllabus before the exams. They should try to give more time to tough papers and also practice sample papers and previous years question papers.
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5 months agoContributor-Level 10
Yes, it is possible. Sometimes the Nagaland Board revised the NBSE HSLC routine due to unavoidable situation like public events, government holidays. Hence, the students should keep visiting the official website of the board and this page for the latest updates on NBSE HSLC exam even after the official dates are out. We provide all the updates related to the Nagaland Board exams here.
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5 months agoContributor-Level 10
2x=tan (π/9)+tan (7π/18)
=sin (π/9+7π/18) / cos (π/9)cos (7π/18)
=sin (π/2) / cos (π/9)cos (7π/18)
=1 / cos (π/9)cos (7π/18)
=1 / cos (π/9)sin (π/2−7π/18)
=1 / cos (π/9)sin (π/9)
⇒x=1 / 2cos (π/9)sin (π/9)
=1 / sin (2π/9)=cosec (2π/9)
Again 2y=tan (π/9)+tan (5π/18)
⇒2y=sin (π/9+5π/18) / cos (π/9)cos (5π/18)
=sin (7π/18) / sin (π/2−π/9)sin (π/2−5π/18)
=sin (7π/18) / sin (7π/18)sin (4π/18) = cosec (2π/9)
⇒|x−2y|=0
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5 months agoContributor-Level 10
Yes, the NBSE release the same HSLC routine for all schools across the state. All the students will be required to appear for the exams as per the released the NBSE 10th routine. Students are suggested to follow the official NBSE HSLC exam date sheet only.
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5 months agoContributor-Level 10
f (x)= {sinx, 0? x /2; 1? /2? x? 2+cosx, x>? }
f' (x)= {cosx, 0
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5 months agoContributor-Level 10
The Nagaland Board released the NBSE HSLC routine online on its website. The students need to visit the official website at nbsenl.edu.in and find the direct link to download the NBSE 10th exam date sheet. Apart from the official website, we also provide a direct link to download the NBSE HSLC routine PDF on this page. Moreover, we also provide the exam routine in tabular form on this page.
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5 months agoContributor-Level 10
. xdy - ydx - x² (xdy + ydx) + 3x? dx = 0
⇒ (xdy - ydx)/x² - (xdy + ydx) + 3x²dx = 0 ⇒ d (y/x) - d (xy) + d (x³) = 0
Integrate both side, we get
y/x - xy + x³ = c
Put x = 3, y = 3
⇒ 1 - 9 + 27 = c
c = 19
Put x = 4
y/4 - 4y = 19 - 64
⇒ y = 12
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5 months agoContributor-Level 10
BTech programme at Christ University comes with a total tuition fee of approximately INR 6.4 Lacs and INR 11.6 Lakh. This fee covers eight semesters of comprehensive academic learning, industry-focused training, and internships. Students can visit the official wesbite for more information.
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