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New Question

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

1 2 m u 3 2 - 1 2 m u 2 = - F R × 24

0 - 1 2 m u 2 = - F R × d

1 2 m u 2 1 2 m u 2 × 8 9 = d 24

d = 24 × 9 8 = 27 c m

New Question

5 months ago

0 Follower 1 View

H
Himanshu Singh

Contributor-Level 10

Yes, PITM (Prajnanananda Institute of Technology and Management) is affiliated with Maulana Abul Kalam Azad University of Technology. This ensures that the curriculum, examinations, and degree offered are recognised, maintaining strong academic standards and credibility for students pursuing the BCA programme.

New Question

5 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

(x-a)/3 = (y-b)/ (-4) = (z-c)/12 = -2 (3a-4b+12c+19)/ (3²+ (-4)²+12²)
(x-a)/3 = (y-b)/ (-4) = (z-c)/12 = (-6a+8b-24c-38)/169
(x, y, z) = (a–6, β, γ)
(a-b)-a)/3 = (β-b)/ (-4) = (γ-c)/12 = (-6a+8b-24c-38)/169
(β-b)/ (-4) = -2
=> β = 8+b
=> 3a – 4b + 12c = 150 . (i)
a + b + c = 5
=> 3a + 3b + 3c = 15 . (ii)
Applying (i) – (ii), we get :
= 56 + 216 + 7b – 9c = 56 + 216 – 135 = 137

New Question

5 months ago

0 Follower 1 View

H
Himanshu Singh

Contributor-Level 10

To pursue a BCA at PITM, students must have passed their Class 12 examination from a recognised board in any stream. Once eligible, they can apply online through the college's official website by filling out the application form, uploading documents, and paying the application fee. Selection details may vary each year.

New Question

5 months ago

0 Follower 1 View

S
Sanjana Dixit

Contributor-Level 10

In order to get admission at Brilliko Institute of Multimedia, Dehradun, candidates must keep certain documents ready. Students can check the list of documents below:

  • Scanned Class 10 and Class 12 marksheet
  • Leaving Certificate
  • Aadhaar Card
  • Passport-size photograph
  • Signature

Note: The list of documents mentioned above is the general list of documents. For more details, visit the official website.

New Question

5 months ago

0 Follower 25 Views

V
Vishal Baghel

Contributor-Level 10

Let the equation of circle be
x (x-1/2) + y² + λy = 0
=> x² + y² - x/2 + λy = 0
Radius = √ (1/16 + λ²/4) = 2
=> λ² = 63/4 => (x-1/4)² + (y+λ/2)² = 4
∴ This circle and parabola
y-α = (x-1/4)² touch each other, so
α = -λ/2 + 2 => α-2 = -λ/2 => (α-2)² = λ²/4 = 63/16
(4α–8)² = 63

New Question

5 months ago

0 Follower 10 Views

N
Nishtha Singh

Contributor-Level 10

RMIT is ranked at #1 in Australia and #21 in the world for courses in Architecture and Built Environment as per QS Rankings by subject 2025. Few of the reasons to study this course are: 

  • Learn in an urban lab of design

  • Students can learn from award-winning architects. The staff and alumni of this university have been awarded the prestigious Victorian Architecture model

The university is globally recognised for its contribution to Architecture. The career paths of this university's Architecture graduates are Architect, Design Journalist, Interior Designer, Urban Designer, etc. 

New Question

5 months ago

0 Follower 2 Views

H
Himanshu Singh

Contributor-Level 10

BCA course at PITM is a four-year programme curated with a detailed curriculum to develop strong core technical skills. This programme is ideal for those aspiring to build prosperous careers in the field of computer application. 

New Question

5 months ago

0 Follower 5 Views

H
Himanshi Shekhar

Contributor-Level 10

RMIT offers Future Leaders Scholarship which provides students belonging to Indian sub-continent 20% tuition fee reduction for eligible programs. This scholarship is applied to students who want to pursue Bachelor's and Master's by coursework program. As per this scholarship, there is a 20% tuition fee reduction for the programme duration outlined on the offer letter. The eligibility of this scholarship is: 

  • Be a citizen of India, Sri Lanka, Bangladesh, Nepal or Pakistan

  • Be an international student having a valid student visa or plan to apply for a student visa prior to the start of the program

  • Have an offer letter to commence the st

...more

New Question

5 months ago

0 Follower 7 Views

R
Rupali Singh

Contributor-Level 10

A comparison between RMIT University and Deakin University (for choosing CS course) is given below: 

Particulars

RMIT 

Deakin

Reputation 

Strong global reputation in Tech, Design & Innovation; Part of Australian Technology Network

Good reputation, practical curriculum, more-industry-focused

Ranking for MS in CS & IT

Top 200-250 worldwide

Top 300-350 worldwide

Course focus

More research and Advanced Technical subjects (Data Science, AI, Cloud Computing, etc.)

More applied and career-focused with practical exposure, project-based learning, etc. 

Approx. tuition fees

AUD 38,000 - AUD 41,000 per year

AUD 37,000 - AUD 40,000 per year

Part-time work & internships

Easier access because of central Melbourne location

Available, but slightly less access as compared to RMIT

Deakin University offers better employability support and affordability. On the other hand, RMIT University offers better brand value internationally. 

New Question

5 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

As slope of line joining (1, 2) and (3, 6) is 2 given diameter is parallel to side
∴ a = √ (3-1)²+ (6-2)² = √20 and
b/ (a/2) = 4/a => b = 8/√5
Area
ab = 2√5 * 8/√5 = 16

New Question

5 months ago

0 Follower 2 Views

P
Pragati Taneja

Contributor-Level 10

To be eligible for Certificate course admission at Brilliko Institute of Multimedia, Dehradun, candidates must complete Class 12. Students can check the points below to know the detailed eligibility:

  • Complete Class 12
  • The selection criteria are merit-based
  • The application process is conducted online.

New Question

5 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

T? = r/ (2r²)²+1)
= r/ (2r²+1)²- (2r)²)
= (1/4) * (4r)/ (2r²+2r+1) (2r²-2r+1)
S? = 1/4 Σ? ¹? [ 1/ (2r²-2r+1) - 1/ (2r²+2r+1) ]
=> S? = (1/4) * (220/221) = 55/221 = m/n
∴ m+n = 276

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

M? = (√3/4 a²)I × 4 = √3I² no. of turns = 4
M? = a²I × 3 = 3Ia² no. of turns = 3

New Question

5 months ago

0 Follower 2 Views

V
Virajita Mehra

Contributor-Level 10

Yes, YBN University offers BSc programmes in different course specialisations. Some of the available course specialisations are Nursing, Post Basic Nursing, Agriculture, Optometry, etc. Candidates who are Class 12 or equivalent examination pass with required aggregate the subject combination can apply. The eligible students can go to the official website to register and apply.

New Question

5 months ago

0 Follower 1 View

S
Sejal Baveja

Contributor-Level 10

Yes,  Janki Devi College of Hotel Management admissions 2025 are merit-based. The college grants admissions to candidates in various courses at the UG level. These include- BBA, BSc and UG Diploma. Candidates are selected for these courses based on the merit of graduation. Interested candidates must apply online on the official website of  Janki Devi College of Hotel Management. 

New Question

5 months ago

0 Follower 2 Views

L
Liyansha Gaurav

Contributor-Level 10

Candidates are admitted to various courses based on merit. The application process at the Brilliko Institute of Multimedia, Dehradun, is conducted online. Here, the admission process is generally in three steps:

  1. Where students can apply- At the official website.
  2. Selection Procedure: Merit-based
  3. Merit-list and Confirmation: Shortlisted candidates must complete document verification and pay the admission fee.

New Question

5 months ago

0 Follower 19 Views

V
Vishal Baghel

Contributor-Level 10

Required area (above x-axis)
A? = 2∫? (8/2 - x - √x)dx
= 2 [16 - 16/4 - 8/3*2] = 40/3
and A? = 4 (1/2 k²) = 2k²


∴ 27 * (40/3) = 5 * (2k²)
=> k = 6
for above x-axis.

New Question

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

220 × i? = 44
⇒ I? = 44/220 = 1/5 = 0.2 A

New Question

5 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

T? =? C? (x¹/³)? (x? ¹/? )? (5¹/²)? (5? ¹)?
for x¹? : (60-r)/3 - r/5 = 10
=> 180 – 3r – 2r = 60
=> r = 24
k = 3 + exponent of 5 in? C?
= 3 + [60/5] + [60/25] – [24/5] – [24/25] – [36/5] – [36/25]
= 3 + (12+2–4–0–7–1)
= 3+2=5

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