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King George Medical College provides good placements to its graduating students.However, the institution has not released the placement report as of yet. In the meantime, check out the table below to know the median package recorded during King George Medical College placements 2024:

This is a multiple choice answer as classified in NCERT Exemplar

(b) First velocity of the iron sphere increases and after sometimes becomes constant called terminal velocity. Hence according first KE increases and then becomes constant which is best represented by b.

Yes, MBBS coarse started in 2018 with annual intake of 50 and from 2020 annual intake increased to 125 and is continuing with the same annually, admission is via NEET UG exam.

Tritya Institute of Event Management BBA programme fee is INR 4.8 lakh. The fee strcture includes components, such as the tuition fee, hostel charges, and refundable deposits. Only applicants who have cleared the admission procedure, are allowed to make the payment. Students must note that this fee information is sourced from the official website/ sanctioning body and is subject to changes. 

This is a multiple choice answer as classified in NCERT Exemplar

(d) h =15m, v= 1m/s, m= 10kg, g= 10m/s²

From conservation of mechanical energy

(PE+KE)_initial= (PE+KE)_final

Mgh + $\frac{1}{2}m{v}^2$ =0+KE

KE= mgh + $\frac{1}{2}m{v}^2$

KE= 10 $\times 10\times 1.5+\frac{1}{2}\times 10\times 1$

KE= 150+5=155J

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=ta{n}^{-1}\left[\frac{3a^{2}x-x^3}{a^3-3a{x}^2}\right]\\ Putx=atan\theta \therefore \theta =ta{n}^{-1}\frac{x}{a}\\ \Rightarrow y=ta{n}^{-1}\left[\frac{3a^{2}atan\theta -a^{3}ta{n}^3\theta }{a^3-3a.a^{2}ta{n}^2\theta }\right]\\ \Rightarrow y=ta{n}^{-1}\left[\frac{3a^{3}tan\theta -a^{3}ta{n}^3\theta }{a^3-3a^{3}ta{n}^2\theta }\right]\\ \Rightarrow y=ta{n}^{-1}\left[\frac{3tan\theta -ta{n}^3\theta }{1-3ta{n}^2\theta }\right]\\ \Rightarrow y=ta{n}^{-1}\left(tan3\theta \right)\left[?tan3\theta =\frac{3tan\theta -ta{n}^3\theta }{1-3ta{n}^2\theta }\right]\\ \Rightarrow y=3\theta \Rightarrow y=3ta{n}^{-1}\frac{x}{a}\\ Differentiatingbothsidesw.r.t.x\\ \frac{dy}{dx}=3.\frac{d}{dx}\left(ta{n}^{-1}\frac{x}{a}\right)=3.\frac{1}{1+\frac{x^2}{a^2}}.\frac{d}{dx}.\left(\frac{x}{a}\right)=3.\frac{a^2}{a^2+x^2}.\frac{1}{a}=\frac{3a}{a^2+x^2}\\ Hence,\frac{dy}{dx}=\frac{3a}{a^2+x^2}\end{array}$

King George Medical College average package for MDS has not been disclosed yet. However, students can refer to the median package given in the table below:

This is a multiple choice answer as classified in NCERT Exemplar

(b) When drop falls first velocity increases, hence first KE also increases, after sometime speed is constant this is called terminal velocity, hence KE also become constant PE decreases continuously as the drop is falling continuously . the variation in PE and KE is best represented by b.

No, CISCE does not release the ICSE toppers list along with the ICSE result. The Council has stopped the practice of releasing the toppers list to avoid unhealthy competition. However, Shiksha.com interviews students who manage to score over 90 percent in their Class 10 board exams to learn about their preparation strategy, and tips they want to share with those preparing for the upcoming session. Students can read these interviews by clicking on the ICSE result link provided here.

The median package for MDS stood at INR 16.50 LPA in 2025. Check out the data tabulated below to know more:

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

Tritya Institute of Event Management offers top-notch facilities offered to the students with all the necessary amenities. Students have access to modern classrooms, a well-equipped event management lab, and a computer lab. The institute also boasts a library, a spacious seminar hall equipped with audio-visual aids, and sports facilities. 

The key highlights recorded during King George Medical College BDS Placements are:

This is a multiple choice answer as classified in NCERT Exemplar

(a) Mass m = 5kg

Radius =1m=R

Revolution per minute  w= 300rev/min

= 300 ( $2\pi$ )rad/min

= $\frac{\frac{300\times 2\times 3.14}{60}rad}{s}=\frac{10\pi rad}{s}$

Linear speed v= rw

= $\frac{300\times 2\pi }{60}=10\pi m/s$

KE= 1/2mv²

= $\frac{1}{2}\times 5\times {10\pi }^2=250\pi$ ²J

The median salary for M.Tech placements at Gandhi Engineering College in 2024 was INR 5.2 LPA. These stats are collated from the NIRF data released for the Engineering branch. Check out the table for reference:

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Lety=ta{n}^{-1}\left(\frac{acosx-bsinx}{bcosx+asinx}\right)\\ \Rightarrow y=ta{n}^{-1}\left[\frac{\frac{acosx}{bcosx}-\frac{bsinx}{bcosx}}{\frac{bcosx}{bcosx}+\frac{asinx}{bcosx}}\right]\\ \Rightarrow y=ta{n}^{-1}\left[\frac{\frac{a}{b}-tanx}{1+\frac{a}{b}tanx}\right]\\ \Rightarrow y=ta{n}^{-1}\frac{a}{b}-ta{n}^{-1}\left(tanx\right)\left[?ta{n}^{-1}\left(\frac{x-y}{1+xy}\right)=ta{n}^{-1}x-ta{n}^{-1}y\right]\\ \Rightarrow y=ta{n}^{-1}\frac{a}{b}-x\\ Differentiatingbothsidesw.r.t.x\\ \frac{dy}{dx}=\frac{d}{dx}\left[ta{n}^{-1}\frac{a}{b}\right]-\frac{d}{dx}\left(x\right)=0-1=-1\\ Hence,\frac{dy}{dx}=-1\end{array}$

No, it is not easy to get admission at Tritya Institute of Event Management. The institute offers admission based on aptitude test, personal interview, and group discussion. The institute also accepts national entrance exams for the MBA course, such as MAT, CMAT,  CAT, and others. Aspiring candidates must qualify the eligibility criteria set by the institute for the desired course. 

This is a multiple choice answer as classified in NCERT Exemplar

(c) When a pendulum oscillates in air, it will lose energy continuously in overcoming resistance due to air. Therefore total mechanical energy of the pendulum decreases continuously with time. This variation is correctly represented by option c.