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B.Com (Program) is a general course for commerce students. This course is best for students who wish to learn about commerce and related subjects without any specialized or advanced knowledge. However, B.Com (Hons) is the most opted course by commerce students. The B.Com (H) course provides advanced knowledge about commerce related subjects.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhaty=ta{n}^{-1}x\\ \Rightarrow x=tany\\ Differentiatingbothsidesw.r.t.y\\ \Rightarrow \frac{dx}{dy}=se{c}^{2}y\Rightarrow \frac{dy}{dx}=\frac{1}{se{c}^{2}y}=co{s}^{2}y\\ Againdifferentiatingbothsidesw.r.t.x\\ \Rightarrow \frac{d}{dx}\left(\frac{dy}{dx}\right)=\frac{d}{dx}\left(co{s}^{2}y\right)\\ \Rightarrow \frac{d^{2}y}{d{x}^2}=2cosy\left(-siny\right).\frac{dy}{dx}\\ \Rightarrow \frac{d^{2}y}{d{x}^2}=-2sinycosy.co{s}^{2}y\\ \therefore \frac{d^{2}y}{d{x}^2}=-2sinyco{s}^{3}y\end{array}$

Rearrangement refers to change the order of sentences (parajumbles) or words to form a structured or coherent sentence. There are several approaches to form a correct sentence or paragraph that one must follow.

For selection in BA course of Sant Baba Bhag Singh University, the aspirants must fulfil the course-specific eligibility criteria. Aspirants who are Class 12 or equivalent pass from a recognised board in any stream can apply for the course admission. During form filling and admission, the candidates must hold the important documents. These are required to verify that the student is eligible to pursue the course.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

Chennais Amirta International Institute of Hotel Management MBA admission is provided to candidates who fulfil the course-specific eligibility criteria. Eligible candidates must visit the institute's official website to register their candidature. The institute reviews the received applications to ensure the eligibility of prospective candidates. It selects eligible candidates based on their merit in the qualifying exam. It may also require aspirants to appear for TANCET. Selected candidates must confirm their admission by submitting the applicable fees.

Admission to the BSc programme at Mohamed Sathak A.J. College of Nursing is primarily merit-based. Candidates are selected based on their academic performance in qualifying examinations, such as their higher secondary or equivalent results. The college may also consider reservation policies and eligibility criteria as per regulations. Generally, there is no separate entrance exam for BSc admissions, making the process straightforward and accessible for eligible students.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

When selecting Mohamed Sathak A.J. College of Nursing for BSc, students should consider factors such as specialisations offered, curriculum relevance, faculty expertise, and placement support. It's also important to assess industry exposure, internship opportunities, tuition fees, infrastructure, and student feedback to ensure that the programme aligns with long-term career goals.

Yes, joining the top ranked Arts colleges in Coimbatore can be worthwhile for you. For that, you need to check its ROI. Listed below are some colleges along with their tuition fees and average placement package:

Source: official site and may vary.

Students are not required to take the GRE (Graduate Record Examination) for all the master's programs, although the students can submit the scores if they benefit the application. 

Other admisison requirements are mentioned below: 

• A four-year bachelor's degree with a cumulative GPA of 3 on 4 pointer scale
• English language proficiency
• GRE (optional)
• Official transcripts/ mark-sheet/electronics mark sheet
• Professional statements
• Resume
• Letter of recommendation

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhaty={\left(cosx\right)}^{{\left(cosx\right)}^{\left(cosx\right)\dots \infty }}\\ \Rightarrow y={\left(cosx\right)}^y\left[?y={\left(cosx\right)}^{{\left(cosx\right)}^{\left(cosx\right)\dots \infty }}\right]\\ Takinglogonboththesides,logy=y.log\left(cosx\right)\\ Differentiatingbothsidesw.r.t.x\\ \frac{1}{y}.\frac{dy}{dx}=y.\frac{d}{dx}log\left(cosx\right)+log\left(cosx\right).\frac{dy}{dx}\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=y.\frac{1}{cosx}.\frac{d}{dx}\left(cosx\right)+log\left(cosx\right).\frac{dy}{dx}\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}=y.\frac{1}{cosx}.\left(-sinx\right)+log\left(cosx\right).\frac{dy}{dx}\\ \Rightarrow \frac{1}{y}.\frac{dy}{dx}-log\left(cosx\right).\frac{dy}{dx}=-ytanx\\ \Rightarrow \left[\frac{1}{y}-log\left(cosx\right)\right]\frac{dy}{dx}=-ytanx\\ \Rightarrow \frac{dy}{dx}=\frac{-ytanx}{\frac{1}{y}-log\left(cosx\right)}=\frac{y^{2}tanx}{ylogcosx-1}\\ Hence,\frac{dy}{dx}=\frac{y^{2}tanx}{ylogcosx-1}\\ Hence,proved.\end{array}$

Yes, The table below shows the top private Arts colleges in Coimbatore along with their India Today ranking 2024:

Disclaimer: This information is sourced from the official website and may vary.

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhat{y}^x=e^{y-x}\\ Takinglogonboththesides,\\ log{y}^x=log{e}^{y-x}\\ \Rightarrow xlogy=\left(y-x\right)loge\Rightarrow xlogy=y-x\left[?loge=1\right]\\ \Rightarrow xlogy+x=y\\ \Rightarrow x\left(logy+1\right)=y\\ \Rightarrow x=\frac{y}{logy+1}\\ Differentiatingbothsidesw.r.t.y\\ \frac{dx}{dy}=\frac{d}{dy}\left(\frac{y}{logy+1}\right)\\ \Rightarrow =\frac{\left(logy+1\right).1-y.\frac{d}{dy}\left(logy+1\right)}{{\left(logy+1\right)}^2}\\ \Rightarrow =\frac{\left(logy+1\right)-y.\frac{1}{y}}{{\left(logy+1\right)}^2}=\frac{logy+1-1}{{\left(logy+1\right)}^2}=\frac{logy}{{\left(logy+1\right)}^2}\\ Weknowthat\\ Hence,\frac{dy}{dx}=\frac{1}{\frac{dx}{dy}}=\frac{1}{\frac{logy}{{\left(logy+1\right)}^2}}=\frac{{\left(logy+1\right)}^2}{logy}\\ Hence,proved.\end{array}$

This is a Short Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhatx=e^{\frac{x}{y}}\\ Takinglogonboththesides,\\ logx=log{e}^{\frac{x}{y}}\\ \Rightarrow logx=\frac{x}{y}loge\Rightarrow logx=\frac{x}{y}\left[?loge=1\right]\dots \left(1\right)\\ Differentiatingbothsidesw.r.t.x\\ \frac{d}{dx}logx=\frac{d}{dx}\left(\frac{x}{y}\right)\\ \Rightarrow \frac{1}{x}=\frac{y.1-x.\frac{dy}{dx}}{y^2}\Rightarrow y^2=x\left(y-x.\frac{dy}{dx}\right)\\ \Rightarrow y^2=xy-x^2.\frac{dy}{dx}\Rightarrow -x^2.\frac{dy}{dx}=y^2-xy\\ \Rightarrow \frac{dy}{dx}=\frac{y^2-xy}{-x^2}=\frac{-y^2+xy}{x^2}=\frac{y\left(x-y\right)}{x^2}\\ \Rightarrow \frac{dy}{dx}=\frac{y}{x}.\frac{\left(x-y\right)}{x}=\frac{1}{logx}.\left(\frac{x-y}{x}\right)\left[?logx=\frac{x}{y}fromeqn\left(1\right)\right]\\ Hence,\frac{dy}{dx}=\frac{x-y}{xlogx}.Hence,proved.\end{array}$

 The institute offers BSc and BA programmes at the UG level. Candidates looking for course admission must complete Class 12 as the basic educational qualification. Apart from the UG courses, the college also offers Diploma/ Certificate/Honours courses.  Students can check the table below to know some of the course tuition fee at Bunts Sangha's Ramanath Payyade College of Hospitality Management Studies: