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Chennai Institute of Technology does not have any set cutoff but those who have scored high in Class 12 are better. TNEA ranks are ascending through ranks and specialisation. Students whose average is more than 80 percent in Physics, Chemistry and Mathematics have a good chance. Counselling rank is a very considerate factor during final seat nomination.

CMAT is one of the accepting exams for admission to PGDM. In 2024, the overall CMAT cutoff was 85. This was same in 2023 as well. However, it is not compulsory to have a CMAT score for admission. Aspirants with a valid score in CAT, MAT, ATMA, etc. can also get admission in the PGDM programme.

Candidates should have completed a minimum of three-years bachelor's degree awarded by any of the universites recognised by UGC or AIU in any discipline with at least 50% aggregate or equivalent to apply for Global MBA programme at NL Dalmia Institute of Management Studies and Research. Applicants in their final year of graduation can also apply for this course.

Yes, IRMA Anand gives credence to national-level examinations like CAT, XAT, and CMAT to take admission to PGDM. FPM, in the case, accepts other exams, such as GATE, NET and ICAR. Besides, IRMA undertakes its own IRMAWAT test. Short listed candidates also go through PI rounds.

IRMA Anand is the institute equipped with a PGDM in Rural management and FPM (Fellow Programme in Management) in Rural management. The main courses rely on rural development, management, and research. The two are residential and full-time programmes. They admit students using national level Entrance examination and personal evaluation.

CAT alone is not a mandatory test because IRMA Anand accepts the scores of XAT and CMAT in admitting the postgraduate diploma. Aspirants may use any of these tests to apply. Other national level tests are also accepter at FPM. The decision of the test should fit course requirements.

Tribhuvan Sahkari University does not have a definite rank but takes percentile scores in various exams such as CAT and XAT. As a rule, admission chances are increased by a percentile higher than 80. The last component of selection comprises performance at PI and academic records.

On the official website, the last date to apply for IRMA Anand admission in 2025 will be announced. Candidates must submit the application early to avoid facing deadline issues. The college accepts only on, line applications. Interested candidates are advised to regularly check the official colege website for updates on admission dates.

It is highly improbable that a general category student will be able to get in with CUET normalized score of 218, for microbiology or biotechnology admissions to Delhi University. These courses are highly competitive, and scores usually range above 400, sometimes very close to 475 or more. If you belong to a reserved category, such as SC, ST, or PwD, and apply to less competitive colleges in DU, then there may be a small possibility depending on seat fill rate and cut-off. You could also check similar life sciences majors or other universities with more accommodating cut-off levels. Just keep checking in on the CSAS portal.

SBM NMIMS shortlists candidates for the interview process for MBA based on their NMAT scores. Candidates seeking admission in Part-time MBA or PG Diploma need to pass an essay test to get shortlisted for the interview process. Once the candidates pass all the rounds of selection, they are offered seat in the institute.

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}GiventhatADisthe\text{\hspace{0.17em}internalbisector}of\angle A\\ \therefore \frac{AB}{AC}=\frac{BD}{DC}\\ AB=\sqrt[]{{\left(5-2\right)}^2+{\left(6-2\right)}^2+{\left(9+3\right)}^2}=\sqrt[]{9+16+144}=\sqrt[]{169}=13\\ AC=\sqrt[]{{\left(2-2\right)}^2+{\left(7-2\right)}^2+{\left(9+3\right)}^2}=\sqrt[]{0+25+144}=\sqrt[]{169}=13\\ \therefore \frac{AB}{AC}=\frac{BD}{DC}=\frac{13}{13}\Rightarrow BD=DC\\ \Rightarrow Disthemid\text{\hspace{0.17em}point}ofBC\\ \therefore CoordinatesofD=\left(\frac{5+2}{2},\frac{6+7}{2},\frac{9+9}{2}\right)=\left(\frac{7}{2},\frac{13}{2},9\right)\\ Hence,therequiredcoordinatesare\left(\frac{7}{2},\frac{13}{2},9\right).\end{array}$

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}CoordinatesofthecentroidG=\left(0,0,0\right)\\ \therefore 0=\frac{x_1+x_2+x_3}{3}\Rightarrow 0=\frac{a-2+4}{3}\Rightarrow a=-2\\ 0=\frac{y_1+y_2+y_3}{3}\Rightarrow 0=\frac{1+b+7}{3}\Rightarrow b=-8\\ and0=\frac{z_1+z_2+z_3}{3}\Rightarrow 0=\frac{3-5+c}{3}\Rightarrow c=2\\ Hence,therequiredvaluesarea=-2,b=-8andc=2.\end{array}$

SBM NMIMS offers admission in MBA programme based on NMAT scores of the candidates. In the 2024 NMAT cutoff for SBM, the overall score requirement was 248 and above. The cutoff score was same as 2024 in 2023 as well for General All India Category. Below is the NMAT cutoff for last three-years for SBM NMIMS MBA:

There is no separate entrance test conducted by ACS College of Engineering for admission. The college considers scores from external exams like CET, COMEDK, and GATE, which are moderately competitive. Students can improve their chances by thorough preparation using mock tests and regular revision. 

For getting admission in mathematics hons the scores of physics, chemistry and mathematics are evaluated. Only these three are considered for admission and your score should be around 350. 

ACS College of Engineering requires a certain Rank in CET and COMEDK, which varies with the level of competitiveness every year. Having a better rank enhances the chances of getting admission in the branches that you desire. Cutoffs are published in the process of counselling. Rank expectation can be estimated with previous year trends.

ACS College of Engineering will accept COMEDK marks to get admission in BTech programmes. Applicants should meet the eligibility of COMEDK and they are also involved in the process of counselling. It is selected according to the merit list as well as the availability of seats.

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l}LetCandDbethe\text{\hspace{0.17em}points}whichdividesthegivenlineAB\text{\hspace{0.17em}into}threeequalparts.\\ Here,AC:CB=1:2\\ Let\left(x_1,y_1,z_1\right)bethecoordinatesofC\\ \therefore x_1=\frac{1\times 5+2\times 2}{1+2}=3and{y}_1=\frac{1\times -8+2\times 1}{1+2}=-2\\ z_1=\frac{1\times 3+2\times -3}{1+2}=-1So,C=\left(3,-2,-1\right)\\ NowDismid\text{\hspace{0.17em}point}ofCB\\ Let\left(x_2,y_2,z_2\right)bethecoordinatesofD\\ \therefore x_2=\frac{3+5}{2}=4and{y}_2=\frac{-8-2}{2}=-5\\ z_2=\frac{3-1}{2}=1So,D=\left(4,-5,1\right)\\ Hence,therequiredcoordinatesareC\left(3,-2,-1\right)andD\left(4,-5,1\right).\end{array}$$\begin{array}{l}\end{array}$

The final date for ACS College of Engineering admissions for 2025 has not been officially announced yet. Candidates are advised to regularly check the college’s official website for updates. Since different courses may have varying deadlines for entrance exam registration and counselling, it's wise to apply early. This helps avoid potential last-minute complications.

Yes, admission in ACS College of Engineering 2025 is open now to all the UG and PG courses of engineering offered. The candidates are to be able to apply online with regard to the official site of the college. Depending on the course, the applicable entrances examinations are such as CET, COMEDK, and GATE. The applicants should fulfill the minimum requirements.