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c = -5, a = 2, b = 1

Around 1.8 Lacs candidates register for JEE Advanced every year. In 2025, the number of candidates who applied for JEE Advanced are 1,87,223. Of all the registered candidates, 1,80,422 candidates took the exam.

1 + x? - x? = a? (1+x)? + a? (1+x) + a? (1+x)² . + a? (1+x)?
Differentiate
4x³ - 5x? = a? + 2a? (1+x) + 3a? (1+x)².
12x² - 20x³ = 2a? + 6a? (1+x).
Put x = -1
12 + 20 = 2a? ⇒ a? = 16

$R=8\mathrm{c}\mathrm{m},A=2{\mathrm{m}\mathrm{m}}^2,B_0=0$  at   $t=0\mathrm{s}\mathrm{e}\mathrm{c}$ $$

$$ $B=2$  Tat $$ $t=0.2\mathrm{s}\mathrm{e}\mathrm{c}$

$$ $\left|\epsilon \right|=\frac{2-0}{0.2}\pi \times 64\times {10}^{-4}$  volts

$\frac{}{}$ $i=\frac{\left|\epsilon \right|}{r}=\frac{64\pi \times {10}^{-3}}{5\times {10}^{-3}}$  ampere

$$ $i=\frac{64\pi }{5}$  ampere

$$ $dF=idlB=$  magnetic force

$dm{\omega }^{2}R=$ centrifugal force

$\begin{array}{ll}\therefore & idlB=dm{\omega }^{2}R\\ \Rightarrow & idl\cdot B=\frac{m}{2\pi R}\cdot dl{\omega }^{2}R\\ \Rightarrow & \omega =\sqrt[]{\frac{2\pi iB}{m}}=\sqrt[]{\frac{2\pi \times 64\pi \times 1}{5\times 9\times {10}^{-3}}}\\ & \omega =\frac{16\pi }{3}\times 10\mathrm{r}\mathrm{a}\mathrm{d}/\mathrm{s}\mathrm{e}\mathrm{c}=170\mathrm{r}\mathrm{a}\mathrm{d}/\mathrm{s}\mathrm{e}\mathrm{c}\end{array}$

TANCET admit card helps candidates to get entry inside the exam centre. Candidates have to carry a hard copy of the TANCET admit card on the exam day. Nobody will get entry inside the test centre if he/she fails to carry the hall ticket.

A² - 4A + 4I = 0
(A - 2I)² = 0 ⇒ A-2I ≠ 0
B = 297A - 594I
= 297 (A - 2I)

Yes, candidates who will pass their class 12 boards in 2026 will be eligible for JEE Advanced 2026. Additionally, candidates who have passed their class 12 boards in 2025, can also apply for JEE Advanced 2026.

? C? +? C? =? C?
Σ (from r=0 to 3)? C? =? C? +? C? +? C? +? C?
=? C? +? C? +? C? +? C?
= ¹²C? = (12×11×10)/6 = 220

TANCET exam admit card is released soon after the registration window is closed. Candidates can download the hall ticket before the exam date. TANCET admit card can be excpected within 5-10 days before the scheduled exam date.

GATE Computer Science and Engineering (CS) and GATE Civil Engineering (CE) are conducted in multiple sessions. For such cases, the candidate will have to appear for the exam in only one of the sessions of the test paper. The details regarding the exam date and time will be mentioned on the GATE admit card. 

No. As per the JEE Advanced attempt limit, a candidate who have appeared for JEE Advanced in 2024 or earlier, cannot appear gain in JEE Advanced 2026.

From Guass’s Law

${\displaystyle ?\overrightarrow{E}.\overrightarrow{dA}=\frac{q_{in}}{{\in }_0}}$            

$E.4\pi r^2=\frac{{\displaystyle \underset{0}{\overset{r}{\int }}\left(4\pi r^2.dr\right)\left(\alpha r\right)}}{{\in }_0}$            

$E=\left(\frac{\alpha r^2}{4{\in }_0}\right)$            

Yes, the NIMCET 2025 seat allotment schedule is OUT. The below schedule was followed -
07 Jul ' 25: NIMCET 2025 Seat Allotment - Round 1    
12 Jul ' 25: NIMCET 2025 Seat Allotment - Round 2    
17 Jul ' 25: NIMCET 2025 Seat Allotment - Round 3    
23 Jul ' 25 - 25 Jul ' 25: NIMCET 2025 Special Round - Choice Filling    
26 Jul ' 25: NIMCET 2025 Special Round Seat Allotment 

lim (x→0) (ae²? - bcosx + c) / (x sinx)
= lim (x→0) (ae²? - bcosx + c) / x² * lim (x→0) x/sinx
For limit to exist
a - b + c = 0
2a + b = 0
(4a-b)/2 = 1
c = 2, b = 2, a = -1
a+b+c = 3

$y\left(x,t_0\right)=A\mathrm{s}\mathrm{i}\mathrm{n}?\left(\frac{x}{b}\right)$

$y(x,0)=A\mathrm{s}\mathrm{i}\mathrm{n}?\left(\frac{x+v{t}_0}{b}\right)$

$y(x,t)=A\mathrm{s}\mathrm{i}\mathrm{n}?\left(\frac{x+v{t}_0-vt}{b}\right)$

$\therefore y(x,t)=A\mathrm{s}\mathrm{i}\mathrm{n}?\left. [\frac{x-v\left(t-t_0\right)}{b}\right]$

Biomolecules in class 12 Chemistry include the following important topics: classification and structure of carbohydrates, amino acids, and proteins, enzymes and their characteristics, nucleic acids (DNA and RNA structure and components), and vitamins.

You must also prepare the following topics that are frequently asked in exams: zwitterion structure in amino acids, enzyme action mechanisms, and differences between DNA and RNA.

There are 9 BTech courses at Symbiosis International Deemed University. Admission to these courses is done through the SITEEE/JEE Mains/ Any other state entrance exam. These courses are BTech in AI and ML, BTech in Computer Engineering, BTech in CSE, BTech in Computer Science and Technology, BTech in Civil engineering, BTech in electronics and Telecommunication, BTech in Mechanical engineering, BTech robotics and automation and BTech in CSE (AI & ML).

TANCET admit card is released on the official website for all the candidates who have applied for the exam before the deadline. Candidates have to download the TANCET admit card before the exam date. The official website has the link to download the TANCET admit card, also known as TANCET hall ticket.

∫ (from 0 to π/2) (x/2)|cos (2x)|dx
∫ (from 0 to π/4) (x/2)cos (2x)dx - ∫ (from π/4 to π/2) (x/2)cos (2x)dx
= [x sin (2x)/4 - ∫sin (2x)/4 dx] (from 0 to π/4) - [x sin (2x)/4 - ∫sin (2x)/4 dx] (from π/4 to π/2)
= [x sin (2x)/4 + cos (2x)/8] (from 0 to π/4) - [x sin (2x)/4 + cos (2x)/8] (from π/4 to π/2)
= (π/16 - 1/8) - (-1/8 - π/16) = π/8

|3a+4b|² = 9|a|² + 16|b|² + 24a·b
But a·b = 0, |a|=|b|=k
|3a+4b| = 5k
|4a-3b|
10k = 20? k = 2 = |a| = |b|