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$100co{t}^2\alpha =15^2-9^2=144$

$\frac{OT}{15}=\frac{2}{3}$

$cot\alpha =\frac{6}{5}OT=10$

$\Delta AOT,OA=OTcot\alpha =10cot\alpha$

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During Sri Venkateswaraa College of Technology BTech placements a total of 80 students were placed. Check out the table below to know more:

The University of Alabama ranking in the U.S. is #171 in National Universities rankings by U.S. News. In 2024, this university ranked at #170. This shows that there has been a slight decline in the rankings of this university nationally. But, still it has managed to stay among the Top 200 Universities in the U.S. Furthermore, in the Global Universities ranking, this university ranks at #653 in 2025.

Sri Venkateswaraa College of Technology has not released branch wise placement statistics. Refer to the table below for the overall placement highlights recorded during Sri Venkateswaraa College of Technology BTech placements:

 $\left|f_1-f_2\right|=\frac{40}{12}=\frac{10}{3}$

$\Rightarrow v\left(\frac{1}{{\lambda }_1}-\frac{1}{{\lambda }_2}\right)=\frac{10}{3}$

$\Rightarrow$$V$$=$$\frac{10}{3}$$\times$$\frac{{\lambda }_1{\lambda }_2}{{\lambda }_2-{\lambda }_1}$$=$$\frac{10}{3}$$\times$$\frac{4.08\times 4.16}{.08}$$=$$\frac{10}{3}$$\times$$\frac{408\times 4.16}{8}$$=$$7$$0$$7$$.$$2$$m$$/$

Sri Venkateswaraa College of Technology has not released the highest package offered to BTech students. Once released it will be updated here. Meanwhile, check out the median package given below:

 $\left(\stackrel{?}{a}.\stackrel{?}{c}\right)\stackrel{?}{b}?\left(\stackrel{?}{a}.\stackrel{?}{b}\right)\stackrel{?}{c}$

$=\stackrel{?}{b}+?\stackrel{?}{c}\left(given\right)$

$\stackrel{?}{a}.\stackrel{?}{c}=1,?=?\stackrel{?}{a}.\stackrel{?}{b}$

$?=?\left(3,1,0\right).\left(1,2,1\right)$

= (3 + 2)= 5

IIITDM Jabalur cutoff 2025 has been released for different categories belonging to the All India quota. Students who belong to the General AI category need to attain a rank between 13297 and 64090. 

OBC AI students need to attain ranks within the range of 4946 and 81973. Students should know that other All India categories will have different qualifying cutoffs.

Using factual data.

The key highlights recorded during Sri Venkateswaraa College of Technology BTech Placements are:

Yes, SVVV offers scholarship to physically challeneged students. Ten Scholarships equivalent to 50% of Annual Tuition Fee or INR 50,000 only, whichever is less, will be awarded to the students who have more than 40% physical disability (certified by competent medical authority of the state government). The Scholarship will be awarded to only those students who are selected on merit. The Scholarship will stop if a student gets ATKT at any stage of the programme. A student will not be eligible to avail more than one Scholarship of the university at any given time.

A (1, 4, 3)

2x + my + nz = 4

$M\Rightarrow -4+\frac{7m}{2}+\frac{3n}{2}=4$

7m + 3n = 16

$\overrightarrow{AM}=\left(-1,\frac{-1}{2},\frac{-3}{2}\right)$

$\frac{2}{-1}=\frac{m}{\frac{-1}{2}}=\frac{n}{\frac{-3}{2}}$

m = 1, n = 3

Plane : 2x + y + 3z = 4

$cos\theta =\frac{\left|6-1-12\right|}{\sqrt[]{26}\sqrt[]{14}}=\frac{7}{2\sqrt[]{91}}$

AM = $\frac{\left|-2+4+9-4\right|}{\sqrt[]{14}}=\frac{7}{\sqrt[]{14}}$

$c$$o$$s$$\theta$$=$$\frac{AM}{AB}$$\Rightarrow$$A$$B$$=$$\frac{7/\text{exception 25:}}{7/2\text{exception 25:}}$$=$$\frac{2\text{exception 25:}}{\text{exception 25:}}$$=$$2$$\text{exception 25:}$$=$

Some the top recruiters for Sri Venkateswaraa College of Technology Placement are listed below:

Using factual data.

The average salary package for placements at Sri Venkateswaraa College of Technology has not yet been disclosed. However, the median salary package has been published. Please refer to the table below for the median packages recorded in recent years.

NOTE: The above data is obtained from the NIRF report 2025

y – 1 = m(x – 1)

mx – y + 1 – m = 0

$\frac{\left|1-m\right|}{\sqrt[]{m^2+1}}=\frac{4}{\sqrt[]{17}}$

$17{\left(1-m\right)}^2=16\left(m^2+1\right)$

m² – 3m + 1 = 0

$\begin{array}{l}bx+10y-8=0\\ y=\frac{2}{3}x\end{array}\}\Rightarrow \left(b+\frac{20}{3}\right)x=8$

$x=\frac{24}{3b+20},y=\frac{16}{3b+20}$

b = $\frac{2\left(3-2\sqrt[]{2}\right)\left(4+3\sqrt[]{2}\right)}{-2}$

$=\frac{12-8\sqrt[]{2}+9\sqrt[]{2}}{-1}=-\sqrt[]{2}$

b² = 2

$\frac{x^2}{5}+\frac{y^2}{2}=1$

2 = 5 (1 – e²)

$e^2=\frac{3}{5}$

$e$$=$

Sri Venkateswaraa College of Technology provides good placements to its graduating students. Check out the table below to know the key highlights of the Sri Venkateswaraa College of Technology placement packages 2024:

NOTE: The above data is obtained from the NIRF report 2025

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