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For Aman,

SP of 1 book = 14Rs.

CP of 1 book = $\frac{100}{(100+x)}\times 14$

For Baman,

SP of 1 book = 12Rs.

CP of 1 book = $\frac{100}{(100+y)}\times 12$

Price of all notebooks is same, therefore.

$\frac{100}{(100+x)}\times 14$ = $\frac{100\times 12}{100+y}$

100 + 7y = 6a

100 = 12y – 7y; [x=2y]

5y = 100

y = 20

a = 40

CP each notebook = $\frac{100\times 12}{100+20}$ = 10Rs.

In his sales with Daman, he sold 10 books to her for Rs. 130

CP of 10books = Rs. 100

Profit percent = $\frac{130-100}{30}\times 100$

=30percent

MIT BIO Campus was formerly owned by the Late. Shri. Raj Kapoor's family. It is popularly known as the Raj Baugh Campus and is spread over 125 acres of lush greenery on the beautiful banks of the Mula-Mutha river. MIT BIO campus offers stat-of-art infrastructure and is well-equipped with facilities like Hostel, Central Library, Sports Complex, Wi-Fi, Cafeteria, Transportation, Laboratories, AC Classrooms, Medical facilities, Auditorium, Music and Dance rooms, etc.

Cotton University offers various courses along with multiple specialisations. Candidates have a variety of fields to choose from when applying for admission. Though, it's important to consider other factors like infrastructure, faculty, curriculum, fees structure, etc. while taking admission. Candidates can visit the campus or check alumni/student reviews. 

a + b + c + d = 7

a ³ 0, b³ 0, c ³ 1, d ³ 1

(a, b, c, d are the numbers of balls)

Let c = c' + 1 = 0, 0 ≤ c' ≤ 5

d = d' + 1 = 0, 0 ≤ d' ≤ 5

a + b + c' + d' = 5

Numbers of solution = ^{5 + 4 – 1}C_4–1

= ⁸C₃ = 56

To take admission in I2CAN Pune, prospective students must satisfy the admission criteria as prescribed by the institute. Those who meet the eligibility requirements can register online. Once registered, someone from the institute's admission desk will reach out to guide the students through the remaining process. Those who get selected need to pay the fees as prescribed by the institute to secure their seats at I2CAN.

Hey,  

Here are some skill sets required to learn [removed]

1. You should have basic Computer Knowledege and browser
2. Learn HTML and CSS basics.
3. Learn JavaScripts basics like variables, loops, functions.
4. Learn DOM like change text, buttons, etc. 

I hope this will help you.

Let f (x) = ax² + bx + c

f (0)= 2

2 = a (0)² + b (0) + c

c = 2

f (– 2) = 3

a (–2)² +b (–2) + 2 = 3

4a – 2b = 1                    ………. (1)

The given equation has a maximum value at x = –2

$\frac{-b}{2a}=-2$

b = 4a

put in equation 1

we get, $a=\frac{-1}{4},b=-1$

f (6)= $\frac{-1}{4}{(6)}^2+(-1)6+2$

= –13

In order to get admission at Vaagdevi Degree and PG College, candidates must keep certain documents ready. Students can check the list of documents below:

• Class 12 (Original)
• Transfer Certificate (Original)
• Bonafide & Study Certificate (Class 6 to 12)
• Any other certificate
• (Sports/PH/NCC/NSS/Ex-Serviceman)
• Caste certificate (If applicable)
• Four recent passport-size colour photos
• Copy of Aadhar Card
• Bridge Course Certificate

The data regarding tuition fee structure for BE courses at BITS Pilani is currently unavailable. Generally, BE courses at BITS Pilani charge the tuition fee on a per semester basis. The tuition fee for each semester is paid in 2 instalments. The BE course fees at BITS Pilani is comprised of the tuition fee, caution deposit and other one time fees. 

No, candidates looking for a course application must apply offline. However, candidates must have registered their names through Online-Web Options must be given for seats allotment (admission). Aspirants can download the application form from the official website of Vaagdevi Degree and PG College. Candidates need to download the application form, fill it out and submit it along with other necessary documents.

P₁ + P₂ + P₃ = 59

P₁ and P₂ → minimize

Then P₃ → minimum i.e. 47

So, only possible value of P₃ can take → 29, 31, 37, 41, 43, and 47

Total 6 values

Yes, I2CAN Pune admissions are currently open for several courses. Interested students can visit the official website of the institute to get all the latest admission-related information. Before starting the process, students can go through the brochure available at the official website to learn all about the desired course. For any queries, students can fill out the enquiry form available online.

Time period of Oscillation, $T=2\pi \sqrt[]{\frac{I}{MB}}$

$\Rightarrow \frac{1}{4}=2\pi \sqrt[]{\frac{9.8\times 10^{-6}}{M\times 0.049}}$

$\Rightarrow \frac{1}{16}=4{\pi }^2\times \frac{9.8\times 10^{-6}}{M\times 49\times 10^{-3}}$

$\Rightarrow M=\frac{4{\pi }^2\times 9.8\times 10^{-6}}{49\times 10^{-3}}\times 16$

$=\frac{4{\pi }^2\times 9.8\times 16\times 10^{-3}}{49}$

$=12.8{\pi }^2\times 10^{-3}\times 10^{-2}\times 10^2$

$=1280{\pi }^2\times 10^{-5}A{m}^2$

A GNM is not a doctor. GNM is a diploma-level course that prepares you to be a Nurse or a Midwife. Nurses and Midwives assist senior doctors in treatments and procedures done on patients. Though GNMs work closely with doctors and other healthcare professionals, they are not qualified and trained to diagnose illness, prescribe medicine, or perform any surgical treatment.

No, candidates cannot complete MDS at Rungta College of Dental Sciences and Research in one year. The duration of this course is of two years. Admissions are entrance-based and scores of the NEET exam is accepted for the same. Candidates must apply on the official website by filling out the application form before the last date.