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CP of wheat be Rs.100/kg So, when shopkeeper pays for 1kg wheat, he get 1.1kg of wheat.

CP of shopkeeper is Rs. $\frac{100}{1.1}perkg$

While selling, he sells 10% less

So, 5p = Rs. $\frac{100}{0.9kg}$

Profit percent = $\frac{\frac{100}{0.9}-\frac{100}{1.1}}{\frac{100}{1.1}}$

=22.22percent

The placement rate recorded during Durgadevi Saraf Global Business School placements stood at 100%. The table below states the same:

Note: The placement year is not mentioned on the official website. Hence, the placement data mentioned above is assumed for the year 2025.

The Andhra Pradesh EAMCET (EAPCET) cutoff is released by the Andhra Pradesh State Council of Higher Education (APSCHE) after each round of counselling. APSCHE publishes the cutoff ranks for every participating college, course, and category on the official Andhra Pradesh EAPCET counselling website.

The highest package offered during Durgadevi Saraf Global Business School placements 2024 stood at INR 10.4 LPA. Check out the table below to know more about the highest package recorded at Durgadevi Saraf Global Business School:

Note: The placement year is not mentioned on the official website. Hence, the placement data mentioned above is assumed for the year 2025.

Yes, ECE Paris does offer English-taught courses. To apply in these, students will have to score English proficiency scores along with other documents. However, students must acquire basic French language skills to easily converse with the locals. The minimum requirement for English proficiency score is as follows:

The placements at Durgadevi Saraf Global Business School are good. The following table presents the placement statistics for Durgadevi Saraf Global Business School:

Note: The placement year is not mentioned on the official website. Hence, the placement data mentioned above is assumed for the year 2025.

Total volume = 2800 cubic feet

Area of ceiling = 2800/28 = 100sqfeet

Total time taken = $\frac{100}{0.125}$ = 800min

= 13hr 20min

Time taken to paint four walls= 40 – 13× $\frac{1}{3}$ = 26hr 40min

Let us find the pattern

10⁴ – 21 = 9979

10⁶ – 21 = 999979

10⁸ – 21 = 99999979

.         .         .

.         .         .

.         .         .

10ⁿ – 21 = 999 (n–2times) 79

When, n = 78

10⁷⁸ – 21 = 999 (76times) 79

Sun of all digit = 77 * 9 + 7

= 693 + 7 = 700

The fees of studying MDS at Rungta College of Dental Sciences and Research is INR 16.2 lakh. Candidates must appear for the NEET MDS/ Chattisgarh NEET PG exam to take admission in the course at Rungta College of Dental Sciences and Research. Additionally, they must also ensure fulfilling the eligibility criteri before applying for admission in the MDS course at Rungta College of Dental Sciences and Research.

The seat intake for BDS course at Rungta College of Dental Sciences and Research is 100. Admissions to this course are entrance-based and scores of the NEET/ Chattisgarh NEET are accepted for the same. Candidates willing to take admission in the BDS course at Rungta College of Dental Sciences and Research, must appear for either of these exams and achieve a valid aggregate in the same. 

ECE consists of four campuses which are:

• Paris

• Lyon

• Bordeaux

• Rennes 

Paris campus is the main and the oldest campus. It is also known as Eiffle Campus because of it's location near the Eiffle Tower and is perfect to organise seminars, business meetings, conferences etc. All the campuses are easily accessible through public transport.

Let the CP of apple be p

Then, px + (p + 4)y – 8 = p * 3x + (p+4) (y–6)

px +py +4y = 3px + py – 6p + 4y – 24 + 8

2px – 6p = 16

p (x–3) = 8

The maximum value of p is 8 at x = 4

Then, CP of an apple and mango is 8 + 12 = 20 Rs.

Let fare for business class and economy class be Rs. 3x and Rs. 2x respectively. Let the passenger in business class and economy class be 12y and 25y respectively.

Total fare = 3x * 12y + 2x * 25y

=86xy = 430000

xy = 5000

Absolute difference = (50 – 36) * 5000

= Rs.70, 000

Yes, candidates can get admission in BDS course at Rungta College of Dental Sciences and Research with 70% in Class 12. The minimum required aggregate is 50% for the same. However, this is the minimum eligibility criteria, and selection for the course is based on a valid score in NEET/ Chattisgarh NEET exam. Interested candidates must fill out the application forms prior to the last date. 

Candidates are selected for BDS course at Rungta College of Dental Sciences and Research on the basis of marks in NEET/ Chattisgarh NEET exams. Candidates mus appear for either of these exams and achieve a valid aggregate in the same. Application forms for the BDS course are available online on the official website of Rungta College of Dental Sciences and Research.

To pursue certification from Zee Institute of Creative Art, Delhi, candidates need to pass Class 12 from a recognised board. Those who passed the minimum course requirements can apply for any of the certification programme on the college's official website.

The eligibility criteria for MDS course at Rungta College of Dental Sciences and Research requires the candidates to pass Class 12 from a recognised board and achieve a valid aggregate in the same. Candidates must submit the marksheets and certificate for the same to apply for and confirm admission at the college. Interested candidates can fill out the application forms available on the official website of the college. 

Let X = Total Amount of Gold

& Y = Total Amount of Platinum

$\frac{}{}$ $\frac{X}{Y}=\frac{2}{5}$  . (1)

Given U1 + P1 = U2 + P2. (2)

U1 + U1 = X & P1 + P2 = Y. (3)

Also, given U1 = 3U2

From (2) P2 − P1 = 2U2

Also, X = 4U2 & 2P1 = Y − 2U2

$\frac{X}{Y}=\frac{2}{5}=\frac{4U_2}{2P_1+2U_2}$

4P1 + 4U2 = 20U2

4P1 = 16U2 $=\frac{16}{3}{U}_1$

$\frac{U_1}{P_1}=\frac{4\times 3}{16}=\frac{3}{4}$ $\frac{}{}{}_{}$

U1 : P1 = 3 : 4