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Yes, UGI Greater Noida BBA selection is done based on applicants scores in IPU CET. This entrance test is mandatory for admission. Moreover, it is also crucial that the aspirants meet the course-specific eligibility requirements. The students who are Class 12 pass with at least 50% aggregate with English as a mandatory subject are eligible for admission. As per the latest brochure, there is also provision for direct admission. However, certain criteria must be fulfilled for the same.

True dip is less than the apparent dip.

Let the speeds be 2Aand A kmph respectively

$\frac{216}{3A}=6$

A = 12 and the speed of B = 3 kmph

Let PS = x

PR + PQ = 7x and PR = x + 18

So,

PQ = 6x – 18, QR = PS = x

In rectangle PQR

(18 + x)² = (6x – 18)² + x²  

X = 7cm

PQ = 42 – 18 = 24cm

Area of rectangle = 7 * 24

= 168sq.cm

No, JEE Main scores are not compulsory for admission to the BTech course at BML Munjal University. The university also accepts other entrance exams for admission to the BTech course. For admission, applicants are required to have completed one of the following entrance examinations: JEE/ SAT/ CUET or BMU-SAT (BMU's Aptitude Test). Thus, with relevant scores in JEE Mains, candidates can get admission to the BTech course. However, it is not compulsory. 

$si{n}^{7}x=co{s}^{7}x=1,x\in \left[0,4\pi \right]$            

will satisfy for sin x = 1, cos x = 0

$\Rightarrow x=\frac{\pi }{2}\&\frac{5\pi }{2}.$              

or, cos x = 1, sin x = 0

x = 0, 2π, 4π              total 5 solutions

d = 150 km

$d=\sqrt[]{2hR}$

$h=\frac{d^2}{2R}=\frac{{\left(150\times 10^3\right)}^2}{2\times 6.5\times 10^6}=1731m.$

Population covered

$\pi r^2\times \sigma =3.14\times 150^2\times 2000=1413\times 10^5$

$\frac{\left(28-25\right)}{\left(45-28\right)}=\frac{3}{17}$

United Group of Institutions, Greater Noida BBA selection is done based on merit in IPU CET. The applicants entrance test score is evaluated for selection purposes. Besides, it is crucial that the aspirants meet the course-specific eligibility requirements as well. The minimum eligibility criteria is Class 12 or equivalent pass with at least 50% aggregate with English as a mandatory subject. Eligible candidates can further proceed with online registeration to apply for admission.

Rahul can occupy any one of the two corner positions and therefore, Rahul can occupy a position in two ways.

The other four people can seat themselves in 4! ways, that is, 24 ways.

Total ways = 2 * 24 = 48 ways.

for bullet

$l=\Delta p=mv-0$

$=\frac{4}{1000}\times 50=\frac{20}{100}=0.2kg-m/s$

Using conservation of momentum :

Pi = Pt

$\Rightarrow \frac{4}{1000}\times 50=4\times v$

v = 0.05 m/s

The tuition fee for Bachelor's in Technology courses at BML Munjal University can range between INR 14 Lacs and INR 15.2 lakh. Moreover, this is only the tuition fee, which candidates need to cover in their four-year course duration. Apart from this fee structure, students might be required to pay hostel fee, admisison fee, maintenance charges, and many more. This fee amount is taken from the official website/ sanctioning body. However, it is indicative. 

The official placement data on Manipal College of Dental Sciences, Mangalore BDS courses is currently unavailable. The only placement data available for Manipal College of Dental Sciences, Mangalore BDS courses comes from the NIRF report. According to it, the average package of BDS students of Manipal College of Dental Sciences, Mangalore stood at INR 3.9 lakh. The report does not mention any details regardingthe the highest package.

f : R -> R.

$f\left(x\right)=[\begin{array}{l}\frac{x^3}{{\left(1-cos2x\right)}^2}log\left(\frac{1+2x{e}^{-2x}}{{\left(1-x{e}^{-x}\right)}^2}\right)x\ne 0\\ \alpha x=0\end{array}$                

As f is continuous at x = 0

$\therefore \alpha =\underset{x\to 0}{Lim}f\left(x\right)$              

$=\underset{x\to 0}{Lim}\frac{1}{2}\left[e^{-2x}+e^{-x}\right]=\frac{1}{2}\times 2=1$            

$\therefore \alpha =1$              

As per the problem, we have Length of the first train = 120 m

Length of the second train = 180 m

As per the problem,

$\frac{(120+180)}{(8+s)}=5$

8 + s = 60

s = 52 m/sec

I : at high temperature, ferromagnet becomes paramagnet.

II : at high temperature, domains of ferromagnet will break

The duration of the BBA course at Techno Main Salt Lake is of three years. Eligible candidates are those who have passed Class 12/equivalent with a valid aggregate from a recognised board. Admissions to this course are entance-based and scores of the CET/CUET exams are accepeted for the same. 

Candidates who are Class 12 or equivalent pass with at least 50% aggregate with English (Core/ Elective/ Functional) as a mandatory subject can apply for BBA at UGI Greater Noida. The aspirants must hold the pass certificates as well. These documents are required to verify that the applicant is eligible for selection. The selection committee shall verify the documents before selection.