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$\frac{a^{a^x}+a^{1-a^x}}{2}\ge \sqrt[]{a^{a^x}.a^{1-a^x}}$ $\left(AM\ge GM\right)$

$\Rightarrow a^{a^x}+a^{1-a^x}\ge 2\sqrt[]{a}$

When a soft ferromagnetic substance is placed in external magnetic field, the size of domain lying in the opposite direction of external magnetic field increases while size of domain lying in the opposite direction of field decreases if field is weak. However, if field is strong then the domain rotate in the direction of external magnetic field due to strong torque.

As we go pole to equator, acceleration due to gravity decreases. So, weight of the body will also reduces. Thus, weight on equator will be slightly smaller than 49 N.

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Sure! Here are the names and course fees of the best AI and Robotics colleges in Tamil Nadu list for the reference of students:

Read More: Artificial Intelligence Course in Tamilnadu Colleges List PDF

Adichunchanagiri University offers full-time BTech / BE programme in multiple specialisations. The course duration is four-year. Popular specialisations include Civil Engineering, Computer Science Engineering, Electronics Engineering, Mechanical Engineering, and Artificial Intelligence & Machine Learning. Multiple specialisations help students choose their preferred niche.

Zener break down occurs in p-n junction having p and n both : Heavily doped and have narrow depletion layer.

Manipal University Jaipur provides great placements to its students. Check out the table below to know about the Manipal University Jaipur placement statistics:

The placement rate recorded during Manipal University Jaipur placements 2024 was 94%. The table below presents the same:

The highest package offered during Manipal University Jaipur placements 2024 stood at INR 88 LPA. The table below presents the same:

The Ranchi University provides decent placements. Check out the table presented below to know about the Ranchi University placements 2022-2024:

The placements at Manipal University Jaipur are good. The following table presents the placement statistics for Manipal University Jaipur:

$T=2\pi \sqrt[]{\frac{L}{g}}or{T}^2=4{\pi }^2\left(\frac{L}{g}\right)$

$\Rightarrow g=4{\pi }^2\left(\frac{L}{T^2}\right)$

$\Rightarrow \frac{\Delta g}{g}\mathrm{\%}=\left(\frac{\Delta L}{L}+\frac{2\Delta T}{T}\right)\mathrm{\%}=\left[\frac{1mm}{1m}+\frac{2\times 0.01}{1.95}\right]\times 100\mathrm{\%}=\left(0.001+0.0102\right)\times 100=1.13\mathrm{\%}$

To be eligible for the BTech / BE programme at Adichunchanagiri University:

• General category students need a minimum aggregate score of 45% in the last qualifying examination, while non-reserved category students require at least 40%.
• Students need to have the following subject combination: Physics and Mathematics, along with any one of Chemistry, Biotechnology, Biology, Electronics, or Computer Science. Students must have studied English in Class 12 (compulsory).

According to the KUK Management NIRF report 2025, the median package offered to MBA students in 2024 was INR 4 LPA. The median package offered to MBA students during Kurukshetra University placements between 2023 and 2024 is presented below:

R = $2\Omega$ $$

L = 2 mH

E = 9V

$i=\frac{\epsilon }{2R}=\frac{9v}{4\Omega }=2.25A$

Just after the switch ‘S’ is closed, the inductor acts as open circuit.

P {a person chosen from the group has chest disorder}

$=\frac{160}{400}\times 0.35+\frac{100}{400}\times 0.20+\frac{140}{400}\times 0.10$

$P\left(\frac{Personissmoker\&non-vegetarian}{Personhaschestdisorder}\right)$

$=\frac{\frac{160}{400}\times 0.35}{\frac{160}{400}\times 0.35+\frac{100}{400}\times 0.20+\frac{140}{400}\times 0.10}$

$=\frac{40\times 0.7}{40\times 0.7+25\times 0.4+35\times 0.2}=\frac{23}{23+10+7}=\frac{28}{45}$

Some of the top colleges for Artificial Intelligence in Tamil Nadu include Sri Ramakrishna College, Chennai Institute of Technology, HICAS, SDNB Vaishnav College for Women, SNMV College, Great Lakes Institute of Management, etc.

Read More: Best AI & Robotics Institutes in Tamil Nadu

Equation of given line x – y + 1 = 0 .(i),

equation of per perpendicular line PP’ is

-x – y + $\lambda =0$  

As line passing through (3, 5)

$\therefore -3-5+\lambda =0$   

$\lambda =8$  

Equation of line PP’ is –x – y + 8 = 0 .(ii)

Solving (i) and (ii)

$\begin{array}{l}-2y=-9\\ y=\frac{9}{2}\end{array}\}Q=\left(\frac{7}{2},\frac{9}{2}\right)$

$y=\frac{9}{2}$

$\therefore x-\frac{9}{2}+1=0$

$P\text{'}=\left(4,4\right)$           

$\frac{5+y_1}{2}=\frac{9}{2}$           

y₁ = 4

According to KTG, the gas exerts pressure because its molecule :

suffer change in momentum when impinge on the walls of container.

$x^2-2\left(3k-1\right)x+8k^2-7>0\Rightarrow a>0,\&D<0,$       

a = 1 > 0 and D < 0

4 (3k – 1)² – 4 (8k² – 7) < 0

$\left(9k^2+1-6k-8k^2+7<0\right)$            

$k(k-4)-2(k-4)<0$    

$k\in \left(2,4\right)$           

K = 3