Ask & Answer: India's Largest Education Community

1000+ExpertsQuick ResponsesReliable Answers

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post




Ok

All Questions

New Question

11 months ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

8.30 

 

Lanthanoids

Actinoids

Electronic Configuration

It is represented by [Xe]4fx5dy6s2, where x varies from 0 to 14 and y= 0 or 1

It is represented by [Rn]5fx6dy7s2, where x varies from 0 to 14 and y= 0

or 1.

Oxidation state

Generally shows +3 oxidation state only in some cases it is +2 or +4 but never greater than +4

It has +3 oxidation state but also shows higher oxidation states such as +4, +5, +6, +7.

Atomic and ionic sizes

Ionic radii of M3+ions decrease in size with increase in atomic number this is called as lanthanoid contraction.

There is a gradual decrease in the size of M3+ ions across the series, this is known as actinoid contraction.

Chemical Reactivity

Lanthanoids are less reactive in nature and form oxides, sulphides, nitrides etc. They have a lesser tendency to form complexes.

They are highly reactive in nature when they are in the finely divided state. They have a higher tendency to form complexes and even react with non-metals at moderate temperature.

Actinoid Contraction > Lanthanoid contraction

Lanthanoids show lanthanoid contraction due to which their size is quite small as compared to actinoids although there is actinoid contraction also lanthanoid contraction has more impact on elements as there is one shell less than actinoids, so lanthanoids have less tendency to lose an electron and to undergo any reaction like the formation of oxide etc.

New Question

11 months ago

0 Follower 11 Views

S
Salviya Antony

Contributor-Level 10

The Kerala Plus one admission 2025 fee is given below.

CategoryFee
General/ Open categoryINR 25/-.
Reserved Category/SC/ST/OBC etc.INR 10/-.

New Question

11 months ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

8.29 It can be observed from the above table that in the starting of 3d transition series elements like Sc, Ti, V, Cr in +2 state are not that stable in their elements in the +3 state.

In the middle Mn2+, Fe2+, Co2+are quite known. In fact, Mn2+ and Mn7+ are most stable states in Mn. Fe2+ is less stable when compared to Fe3+ which is due to fact that Fe3+ is able to loose one electron to acquire d5 state which has extra stability. Co2+ is less stable as compared to Co3+.

Ni2+ is the most common and stable among its +2, +3, +4 states. Cu2+ is more stable and is quite common as compared to Cu+. Towards the end, Zn forms only Zn2+ whic

...more

New Question

11 months ago

0 Follower 1 View

H
Himanshu Singh

Contributor-Level 10

In the first semester of the MSc programme at Nagaland University – Kohima Campus, students focus on core foundational subjects. The curriculum includes Geomorphology and Remote Sensing, Structural Geology and Geodynamics, Palaeontology, and Mineralogy. These subjects provide a strong academic foundation and essential skills required for more specialised geological topics in the later semesters.

New Question

11 months ago

0 Follower 48 Views

P
Payal Gupta

Contributor-Level 10

8.28 Metal ions which have valence electrons in d-orbital and in which d-d transition can take place will be coloured and the metal ions which have completely filled orbital or have d- orbital will be colourless as no d-d transition is possible in those configurations.

Element

Atomic Number

Ionic State

Electronic configuration in ionic state

Ti

22

Ti3+

[Ar] 3d1

V

23

V3+

[Ar] 3d2

Cu

29

Cu+

[Ar] 3d10

Sc

21

Sc3+

[Ar]

Mn

25

Mn2+

[Ar] 3d5

Fe

26

Fe3+

[Ar] 3d5

Co

27

Co2+

[Ar] 3d7

From the above table, it can be observed that only Sc3+ and Cu+ have either completely filled d- orbital or empty d-orbital. So, all other ions except Sc3+ and Cu+ will be coloured in aqueous solution because of absorption of radiations which fall in the visible region as on obtaining energy electrons jump from one d-orbital to another.

New Question

11 months ago

0 Follower 4 Views

New Question

11 months ago

0 Follower 11 Views

P
Payal Gupta

Contributor-Level 10

8.27 (i) Reduction potential tells us the ease with which the Metal can get reduced, As E° for Cr3+/Cr2+ is negative (–0.4 V), this means that Cr3+ ions in solution cannot be reduced to Cr2+ ions i.e., Cr3+ ions are very stable. As a further comparison of E° values show that Mn3+ ions more readily than Fe3+ ions which means that Mn3+ is least stable.

So Stability of metal ions is as follows:

Mn3+3+

(ii) Reduction potential tells us the ease with which the Metal can get reduced or the difficulty with which they are oxidized, As the reduction potential increases in the following order Mn2+/Mn < Cr2+/Cr< Fe2+/Fe

So oxidation of Fe is not as easy

...more

New Question

11 months ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

8.26 Potassium permanganate can be prepared from MnO2. It can be done by fusing the ore with KOH in presence of an oxidizing agent like atmospheric oxygen/KNO3 etc to give green coloured K2MnO4 as the product.

2MnO2 + 4KOH + O2 → 2K2MnO4 + 2H2O

The Product K2MnO4 is extracted with water and then oxidised by passing ozone/chlorine into the solution or electrolytically.

Electrolytic oxidation:

(i) Acidified KMnO4 solution oxidizes Fe(II) ions to Fe(III) ions and water as product

MnO4 - + 8H+ + 5e- → Mn2+ + 4H2O

Fe2+→ Fe3++ e- } x5

Overall: MnO4 - + 8H+ + 5Fe2+ → Mn2+ + 4H2O + 5Fe3+

(ii) Acidified potassium permanganate oxidiz

...more

New Question

11 months ago

0 Follower 20 Views

New Question

11 months ago

1 Follower 159 Views

S
Salviya Antony

Contributor-Level 10

The Kerala plus one trial allotment was conducted on May 24, 2025. 

  • Visit the official website of HSCAP at hscap.kerala.gov.in.
  • Click on HSCAP Kerala Plus One trial allotment list link available on the home page.
  • A new page will be opened.
  • Enter the login details.
  • Click on submit.
  • Allotment details will be displayed.

New Question

11 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

8.25 K2Cr2O7 acts as a very strong oxidizing agent in acidic medium. K2Cr2O7 gets reduced and acts as an oxidizing agent by oxidizing Iodide to iodine

(i) K2Cr2O7 oxidizes iodide to iodine

Cr2O72-+ 14H++ 6e-→ 2Cr3+ + 7H2O

2I-→ I2 + 2e- } x3

Overall: Cr2O72-+ 14H++ 6I-→ 2Cr3+ + 7H2O+ 3I2

(ii) K2Cr2O7 oxidizes iron(II) to iron(III)

Cr2O72-+ 14H++ 6e-→ 2Cr3+ + 7H2O

Fe2+→ Fe3+ + e- } x6

Overall: Cr2O72-+ 14H++ 6Fe2+→ 2Cr3+ + 7H2O + 6Fe3+

(iii) K2Cr2O7 oxidized H2S to sulphur

Cr2O72-+ 14H++ 6e-→ 2Cr3+ + 7H2O

H2S → S + 2H+ + 2e-} x3

Overall: Cr2O72-+ 8H++ 3H2S → 2Cr3+ + 7H2O +3S

New Question

11 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

8.24 Potassium dichromate is prepared from chromite ore (FeCr2O4) by the following steps:

Step1: Preparation of sodium dichromate in the reaction of Chromite ore with sodium hydroxide and oxygen gas.

4FeCr2O4 + 16NaOH + 7O2? 8Na2CrO4 + 2Fe2O3 + 8H2O

Step2: Conversion of Sodium Chromate on reaction with concentrated Sulfuric acid gives Sodium dichromate as a product.

2Na2CrO4 + conc. H2SO4? Na2Cr2O7 + Na2SO4 + H2O

Step3: Sodium dichromate on reaction with potassium chloride converts to potassium dichromate as a product.

Na2Cr2O7 + 2KCl? K2Cr2O7 + 2NaCl

As potassium dichromate is less soluble than sodium chloride so, potassium dichromate

...more

New Question

11 months ago

0 Follower 52 Views

S
Salviya Antony

Contributor-Level 10

The Kerala Plus one trial allotment will be conducted on May 24, 2025. The first allotment will be published on June 2, second allotment on June 10, and the third allotment on June 16, 2025. 

New Question

11 months ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

8.23 In transition metals, it can be observed that the oxidation state of the metal varies from +1 to +7 which is obtained by removing all its valence electrons. In transition elements the oxidation state differ by 1 unlike non transition elements whose oxidation state differs by 2, for example in transition metals (Cu2+, Cu3+ and Fe2+, Fe3+) and In non-transition elements, this variation is selective, always differing by 2, e.g. S exhibits +2, +4, +6 oxidation states and N exhibits +3, + 5, etc.

New Question

11 months ago

0 Follower 1 View

L
Liyansha Gaurav

Contributor-Level 10

For UG Diploma course admission, candidates must meet the eligibility criteria set by CII Institute of Hospitality - Taj Hotels, Chandigarh. Aspirants should pass Class 12 with 50% aggregate. The admission criteria for the course is entrance-based. Students must have cleared Class 12 from a recognised board in India with minimum 50% aggeragte. Added to that, candidate must pass class 12 with English as a subject.

New Question

11 months ago

0 Follower 55 Views

P
Payal Gupta

Contributor-Level 10

8.22 Interstitial compounds are those compounds in which small atomic size elements like H, C, N occupy the interstitial sites of the crystal lattice of the Transition metal due to their large size.

Example, in the diagram given below:

Here, Green Balls form the Crystal lattice of transition metal and Blue balls represent elements like H/C/N which occupy the interstitial sites.

New Question

11 months ago

2 Followers 468 Views

S
Salviya Antony

Contributor-Level 10

Kerala Plus one allotment 2025 will be done on June 2, second allotment on June 10, and the third allotment on June 16, 2025. Check the steps below.

  • Visit the official website of HSCAP at hscap.kerala.gov.in.
  • Click on HSCAP Kerala Plus One first allotment list link available on the home page.
  • A new page will open where candidates will have to enter the login details.
  • Click on submit and check the allotment details.

New Question

11 months ago

0 Follower 17 Views

P
Payal Gupta

Contributor-Level 10

8.21 (i) Transition metals and many of their compounds show paramagnetic behavior- Paramagnetic behaviour is shown by transition metals as paramagnetism is due to the presence of unpaired electrons which have a magnetic moment associated with its spin and angular momentum, as the orbital angular momentum is satisfied in the first transition series. So the paramagnetic is only due to the unpaired electrons.

(ii) The enthalpies of atomisation of the transition metals are high- Enthalpies of atomization is the enthalpy change when 1 mol of gaseous atoms is formed from its element in its defined physical state under standard cond

...more

New Question

11 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

8.20 +3 oxidation state is the most common oxidation state of lanthanides i.e., Ln (III) compounds are predominant. +2 and +4 oxidation states can also be found in the solution or in solid compounds, but are not predominant.

New Question

11 months ago

0 Follower 2 Views

P
Pragati Taneja

Contributor-Level 10

CII Institute of Hospitality - Taj Hotels, Chandigarh offers three Diploma courses in the field of Hospitality Management. The duration of these courses is 18 months. Listed below are the CII Institute of Hospitality - Taj Hotels, Chandigarh courses specialisations:

  • Swiss International Culinary Professional Diploma
  • Swiss International Food & Beverage Service Professional Diploma
  • Swiss International Rooms Professional Diploma

Register to get relevant
Questions & Discussions on your feed

Login or Register

Ask & Answer
Panel of Experts

View Experts Panel

Share Your College Life Experience

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.