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This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:$\begin{array}{l}\frac{\mathrm{}}{}\end{array}$

The best books to prepare for the PTE exam are given here below-

1. The Official Guide to PTE Academic- This book is a guide to understand the pattern, format question types, scoring and other aspects of the PTE exam. 
2. PTE Academic Practice Test Plus (Vol. 1 & 2)- Practice tests in these books closely simulate the PTE exam. The book presents the pictorial representations of the questions as they are asked in real time on the exam day.  

The highest number of students placed were from the CSE branch of BTech. The IIIT Nagpur placements 2025 data such as total strength, the number of students registered, and the number of students has been presented branch-wise below:

Students need to secure a minimum of 33 percent marks separately in practicals and theory and in aggregate to clear the Punjab board 10th exams. 

Securing 33 per cent marks is very easy in PSEB 10th exams with a little dedication and focus on studies. Try finishing all the topics and chapters mentioned in the syllabus, know the exam pattern well, and practice sample papers and previous years question papers for better preparation. 

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Giventhatncoinsaretwoheadedcoinsandtheremaining\left(n+1\right)coinsarefair.\\ Let{E}_1:theeventthatunfaircoinisselected.\\ E_2:theeventthatfaircoinisselected.\\ E_3:theeventthatthetossresultisahead.\\ \therefore P\left(E_1\right)=\frac{n}{2n+1}andP\left(E_2\right)=\frac{n+1}{2n+1}\\ P\left(E/E_1\right)=1\left(sureevent\right)andP\left(E/E_2\right)=\frac{1}{2}\\ \therefore P\left(E\right)=P\left(E_1\right).P\left(E/E_1\right)+P\left(E_2\right).P\left(E/E_2\right)\\ =\frac{n}{2n+1}.1+\frac{n+1}{2n+1}.\frac{1}{2}=\frac{1}{2n+1}\left(n+\frac{n+1}{2}\right)\\ =\frac{1}{2n+1}\left(\frac{2n+n+1}{2}\right)=\frac{3n+1}{2\left(2n+1\right)}\\ ButP\left(E\right)=\frac{31}{42}\left(given\right)\\ \therefore \frac{3n+1}{2\left(2n+1\right)}=\frac{31}{42}\Rightarrow \frac{3n+1}{2n+1}=\frac{31}{21}\\ \Rightarrow 63n+21=62n+31\\ \Rightarrow n=10\\ Hence,therequiredvalueofnis10.\end{array}$

It'll be based on your category ranking, if u are in OBC or sc / st you have high chances to get admission.please follow up every updations in your profile 

Yes, applications are open at NIMT - National Institute of Management and Technology for various courses. The mode of application is both online/offline. Aspirants need to apply at the official website, i.e., nimt.ac.in/apply for admission to the various programme. Candidates can fill out the application form on the institute's official website.

The NIT Hamirpur cutoff 2025 has been released for admission to the BTech programme. The Round 1 of the closing ranks varied between 10852 and 41548 for the students belonging to the General AI quota. The cutoff ranks vary for different courses, specialisations, rounds, categories, and quotas. Detailed Round 1 JEE Main closing ranks for all the courses available at NIT Hamirpur for the General AI quota are tabulated below: 

It totally depends on the authenticity of your free online study materials. If it is from official website or any reputed publishers, then it is valuable. It will be smart decision if you use both.

This is a Long Answer Type Questions as classified in NCERT Exemplar

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:$\begin{array}{l}\end{array}$

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

This is a Long Answer Type Questions as classified in NCERT Exemplar

Sol:

$\begin{array}{l}Let{E}_1:theeventthattheitemismanufacturedonmachineA\\ E_2:theeventthattheitemismanufacturedonmachineB\\ E_3:theeventthattheitemismanufacturedonmachineC\\ LetHbetheeventthattheselecteditemisdefective.\\ \text{\hspace{0.17em}Using}Bayes\text{'}Theorm\\ \therefore P\left(E_1\right)=\frac{50}{100},P\left(E_2\right)=\frac{30}{100}andP\left(E_3\right)=\frac{20}{100}\\ P\left(H/E_1\right)=\frac{2}{100},P\left(H/E_2\right)=\frac{2}{100}andP\left(H/E_3\right)=\frac{3}{100}\\ \therefore P\left(E_1/H\right)=\frac{P\left(E_1\right).P\left(H/E_1\right)}{P\left(E_1\right).P\left(H/E_1\right)+P\left(E_2\right).P\left(H/E_2\right)+P\left(E_3\right).P\left(H/E_3\right)}\\ =\frac{\frac{50}{100}\times \frac{2}{100}}{\frac{50}{100}\times \frac{2}{100}+\frac{30}{100}\times \frac{2}{100}+\frac{20}{100}\times \frac{3}{100}}=\frac{100}{100+60+60}=\frac{100}{220}=\frac{10}{22}=\frac{5}{11}\\ Hence,therequiredprobabilityis\frac{5}{11}.\end{array}$

Core practical subjects that are generally included in the curriculum of BSc in Microbiology are listed below:

• Microbial Physiology
• Molecular Biology
• BSc3 Biology
• Microbial Genetics
• Medical Microbiology
• Industrial Microbiology
• Food Microbiology
• Environmental Microbiology

Essential practical techniques/aspects that are introduced to the students are listed below.

• Microscopy
• Molecular Techniques
• Bioinformatics
• Laboratory Safety
• Culturing and Isolation
• Data Analysis and Interpretation

The level of competitiveness of the B Tech Dairy Technology entrance exams usually varies by exam. Generally speaking, prominent exams for the course, like ICAR AIEEA and JEE Main, are quite competitive and difficult to crack, given the competition for seats at top colleges across India. It is very important to prepare well and get excellent marks and rank to grab a seat at a premier institute. 

IIIT Nagpur has a good track record of placements for its BTech course. IIT Nagpur concluded the placements for its BTech batch 2025 with an 97.10% placement rate. The key highlights of IIIT Nagpur placements for the BTech Class of 2025 are tabulated below: