Ask & Answer: India's Largest Education Community

The final RRB NTPC post allotment depends on the CBT 1 and 2 scores, order of post preference, availability of vacancies in chosen zones. Candidates are required to enter their RRB NTPC post preferences while filling the application form. The eligibility attached to various posts are different. 

In total, 51 recruiters took part during the Justice K S Hegde Institute of Management placement drive during 2023. The key information on the institute placement packages are presented below for MBA:

The Justice K S Hegde Institute of Management placement's the highest package stood at INR 10.5 LPA. Check out the table below to know more about the highest packages offered during the institute placements for the year 2021-23 for MBA:

Ajeenkya DY Patil University Seamedu offers BTech course to candidates for a duration of three years. To apply for admission in this course at the university, candidates must pass Class 12 from an recognised board. They must also submit the marksheet and certificate for the same to apply for, and confirm admission at Ajeenkya DY Patil University Seamedu.

Let PT perpendicular to QR

$\frac{x+1}{2}=\frac{y+2}{3}=\frac{z-1}{2}=\lambda \Rightarrow T\left(2\lambda -1,3\lambda -2,2\lambda +1\right)$ therefore

$2\left(2\lambda -5\right)+3\left(3\lambda -4\right)+2\left(2\lambda -6\right)=0\Rightarrow \lambda =2$

$T\left(3,4,5\right)\therefore PT=\sqrt[]{1+4+4}=3\therefore QT=\sqrt[]{26-9}=\sqrt[]{17}$

$\therefore \Delta PQR=\frac{1}{2}\times 2\sqrt[]{17}\times 3=3\sqrt[]{17}$

Therefore square of $ar\left(\Delta PQR\right)$ = 153.

Poona College of Pharmacy BPharm fees include multiple components such as tuition fees, hostel fees, admission fees, application fees, etc. The tuition fee of the course is INR 5.3 lakh; apart from tuition fees, students are required to submit an application fee, admission fee, hostel fees + mess charges, etc. Check out the fee components: 

Note: This information is sourced from the official website/ sanctioning body and is subject to change.

Takshashila University M.Tech eligibility criteria state the conditions to be fulfilled by candidates seeking admission. To be eligible for admission, candidates must have completed their BTech/BE in Computer Science and Engineering, Information Technology, or related disciplines with a minimum of 50% marks. Moreover, as per the official website, the university does not require any entrance test score.

 $f\text{'}\left(x\right)=\frac{4x^2?1}{x}$ so f (x) is decreasing in $\left(0,\frac{1}{2}\right)and\text{?}\text{?}\left(\frac{1}{2},?\right)$ $?a=\frac{1}{2}$

Tangent at y² = 2x is y = mx + $\frac{1}{2m}$ it is passing through (4, 3) therefore we get m = $\frac{1}{2}or\text{?}\text{?}\frac{1}{4}$

So tangent may be $y=\frac{1}{2}x+1\text{?}\text{?}or\text{?}\text{?}y=\frac{1}{4}x+2\text{?}\text{?}\text{?}but\text{?}\text{?}y=\frac{1}{2}x+1$ passes through (-2, 0) so rejected.

Equation of normal $\frac{x}{9}+\frac{y}{36}=1$

R = tanq = tan 45° = $\frac{\rho L}{A}$

$\text{?}1=\rho \times \frac{31.4}{\pi {\left(1.2\right)}^2}$

$\rho =\frac{3.14\times 1.2\times 1.2}{31.4}$

$\rho =12\times 12\times 10^{-3}$

$\rho =12\times 12\times 10^{-3}$

$\rho =144\times 10^{-3}=x\times 10^{-3}\Omega -cm$

The average package for BTech students at IIIT Ranchi was around INR 12.36 LPA in 2025. Last year, the college offered INR 12.14 LPA as the average package. 

To be eligible for admission to BArch course via UPTAC counselling, candidates must have passed class 12 or equivalent examination and obtained at least 50 percent marks in total in Physics, Chemistry & Mathematics and also at least 50 percent marks in class 12 examination.

or 

Passed 10+3 Diploma and obtained at least 50 percent marks in total.

Slope of AH = $\frac{a+2}{1}$ slope of BC = $-\frac{1}{p}\therefore p=a+2$ $\therefore C\left(\frac{18p-30}{p+1},\frac{15p-33}{p+1}\right)$

slope of HC = $\frac{16p-p^2-31}{16p-32}$

slope of BC × slope of HC = -1 p = 3 or 5

hence p = 3 is only possible value.

Yes,  MTech is available at Takshashila University. Under this course, the university offers various specialisations, including Computer Science and Engineering (AI), Communication Systems, and more. All these courses run for a duration of two years. Moreover, all these courses are offered in full-time mode. Admissions to these courses are offered based on marks obtained in the qualifying examination.

Candidates change but only for the specifc zones and posts they have listed. Candidates indicating partial prefetrences are considered only for those choices and not for others.

Yes, the School of Law, Pandit Deendayal Energy University, admits students based on SOLLACE entrance exam scores. For the LLB and BA LLB courses, the institute admits students based on the SOLLACE entrance exam. However, for BA LLB, CLAT entrance exam scores are also accepted. 

Teesside University offers various resources inorder to provide students an excellent experience. Some of these include campus tour, research labs for Science and clinical subjects, campus heart that links South and North sides offering space for events, food markets, parade, graduation celebrations, a healthcare center, a cafe to enjoy delicious food and chill with friends. Apart from this, the university also offers access to digital-based services to support students in developing skills in areas like AI, cybersecurity, game design and many more.

 ${\displaystyle \underset{3}{\overset{x}{\int }}f\left(x\right)dx}={\left(\frac{f\left(x\right)}{x}\right)}^3\Rightarrow x^3{\displaystyle \underset{3}{\overset{x}{\int }}f\left(x\right)dx}=f^3\left(x\right),$ differentiating w.r.to x

$x^{3}f\left(x\right)+3x^2\frac{f^3\left(x\right)}{x^3}=3f^2\left(x\right)f\text{'}\left(x\right)\Rightarrow 3y^2\frac{dy}{dx}=x^{3}y=\frac{3y^3}{x}\Rightarrow 3xy\frac{dy}{dx}=x^4+3y^2$

After solving we get $y^2=\frac{x^4}{3}+c{x}^2$ also curve passes through (3, 3) c = -2

$\therefore y^2=\frac{x^4}{3}-2x^2$ which passes through $\left(\alpha ,6\sqrt[]{10}\right)$ $\therefore \frac{{\alpha }^4-6{\alpha }^2}{3}=360\Rightarrow \alpha =6$

The median package offered stood at INR 6.36 LPA during the Justice K S Hegde Institute of Management placements 2023. Check out the table for more information:

Yes, aspirants can join the School of Law, Pandit Deendayal Energy University after Class 12 exam. The institute offers BA LLB and LLB courses. SOL, PDEU admits students based on the entrance exam. To get admission to SOL, PDEU, candidates must meet the eligibility criteria set by the college. The application process at the School of Law, Pandit Deendayal Energy University, is conducted online.