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$\stackrel{•}{C}l+C{H}_3-H\to \stackrel{•}{C}{H}_3+HCl$

The MAHA TET exam is a qualifying exam for candidates who want to be Classes 1 to 8 teachers. Candidates need to clear the MAHA TET exam to obtain eligibility certificate for applying to the Maharashtra Teacher recruitment drives. 

According to the available cutoff data for MBA courses at JSS Science and Technology University, the MBA in Retail Management course has the lowest cutoff for admissions. However, there is a drastic increase in the cutoff for the MBA in Retail Management between 2023 and 2024.  The increase in cutoff ranks is present in almost every MBA course offered by JSS Science and Technology University. From the current data, candidates can expect the closing ranks to increase this year as well.

Spring constant of wire (k) =   $\frac{AE}{L}$

Case 1

      $k\left[\Delta \right]=1g$          

                      $k\left[L_1-L\right]=1g$  - (1)

              Case 2         $k\left[L_2-L\right]=2g$             - (2)

          $\left(1\right)÷\left(2\right)$      

$\frac{L_1-L}{L_2-L}=\frac{1}{2}$

L = 2L₁ – L₂

 $\stackrel{+7}{M}n{O}_4^{-}+8H^{+}+5e\to \stackrel{+2}{M}{n}^{2+}+4H_{2}O$ change in oxidation number of Mn = 7 – 2 = 5

The admission process for CIS Foundation includes multiple steps starting from application followed by selection and admission confirmation. Interested students who meet the admission criteria can follow the steps mentioned below to complete CIS Foundation's admission procedure online:

1. Go to the official website and fill out the application online.
2. Check out the courses on offer and their eligibility criteria. 
3. Participate in the merit-based admission process. 
4. After being chosen, confirm and reserve your spot by paying the designated fee.

There are about 20 top UP NEET accepting BDS colleges in India. Some of them are mentioned below along with their tuition fees:

Source: Official site and may vary.

It is reduction process, while rest are examples of disproportionation reaction.

The MAHA TET exam process has these stages-

1. Release of notification
2. Submission of online applications
3. Hall ticket
4. Conduct of the exam
5. Interim answer key to invite objections
6. Final answer key
7. Interim Result to invite objections
8. Release of final result

 Number of neutrons = 26

Number of electrons = 25

% of extra electrons = $\frac{26-25}{25}\times 100=4\mathrm{\%}$

Universal Institute of Hotel Management admissions are currently open for all courses. Candidates are selected for courses based on merit. Aspirants can apply online. Interested candidates meeting the eligibility criteria can fill out the form. The selection criteria of the Universal Institute of Hotel Management are merit-based. 

$B_2{H}_6+N{H}_3\underset{}{\overset{HighTemperature}{\to }}{B}_3{N}_3{H}_6\left(Borazine\right)$

PV = nmixRT

$n_{mix}=\frac{6*12.5}{0.083*300}?3$

Let moles of He is x

Moles of H₂ = 3 – x

4x + 2 (3 – x) = 10

x = 2 mol

Mass of He = 8 gm

$2BeC{l}_2+LiAl{H}_4\to 2Be{H}_2+LiCl+AlC{l}_3$

Phenolphtalein is a pH dependant indicator. It is a weak acid which is colourless in acidic medium but gives pink colour in basic medium. The pink colour is due to its conjugate form. Phenolphthalein dissociates in basic medium. Therefore, assertion is true but reason is false.

$\underset{\left(Colourless\right)}{HPh\left(aq.\right)}?H^{+}+\underset{\left(Pink\right)}{P{h}^{-}}$

MMMUT MBA fees is inclusive of various components such as tuition fees, caution deposits, etc. Moreover, students must note that only those who opt for hostel facilities are charged a hostel fee. Combining all, the total fees for the M.Tech programme amount to INR 3.71 lakh. Check the table below to learn the component-wise bifurcation of the total fees:

Note: The above-mentioned fee is as per the official sources. However, it is indicative and subject to change.

Urea acts as negative catalyst for decomposition of H₂O₂.

              44.4 litres of He $\frac{44.8}{22.4}moles$

            $\eta =2$    moles of He

              Q =   $\eta C_v\Delta T$ (for fixed capacity (v = constant)

              =   $2\times \frac{R}{\gamma -1}\Delta T$

              =   $\frac{2\times R}{\frac{5}{3}-1}\times 20$

= $=2\times \frac{3R}{2}\times 20$

 Q = 60R = 60 × 8.3

  Q = 498 J

Liquation process is used for purification of that metal, whose melting point is lesser then that of impurities.