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At Nehru Gram Bharati University Kotwa, the BA programme includes top specialisations such as Economics, Sociology, Communication Studies, Psychology, and more. BA Economics graduates see the highest average salary at INR 16.4 LPA, while Public Administration and Psychology follow. Other fields like English, History, and Journalism offer salaries ranging from INR 3.9 to 5.5 LPA.

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol.

$\begin{array}{l}Letxbethelengthofthecube\\ \therefore VolumeofthecubeV=x^3\dots \left(i\right)\\ Giventhat\frac{dV}{dt}=K\\ Differentiatingeq\left(i\right)w.r.t.t,weget\\ \frac{dV}{dt}=3x^2.\frac{dx}{dt}=K\left(constant\right)\\ \therefore \frac{dx}{dt}=\frac{K}{3x^2}\\ Nowsurface\text{?}\text{?}areaofthecube,S=6x^2\\ Differentiatingbothsidesw.r.t.t,weget\\ \frac{dS}{dt}=6.2.x.\frac{dx}{dt}=12x.\frac{K}{3x^2}\\ \Rightarrow \frac{dS}{dt}=\frac{4K}{x}\Rightarrow \frac{dS}{dt}\propto \frac{1}{x}\left(4K=constant\right)\\ Hence,surface\text{?}\text{?}areaofthecubevariesinverselyasthelengthoftheside.\end{array}$

No, students can only receive one form of support, either a Freeship or Financial Aid/Fee Rebate. The policy is designed to ensure fair distribution of benefits. Students are encouraged to check the university's detailed financial aid guidelines to determine which option they qualify for and how to apply for the most suitable support scheme.

Yes, Nehru Gram Bharati University Kotwa offers a full-time BA programme. The course is available in both Honours and Honours with Research formats, with several specialisations such as Political Science, Sociology, Music, Sanskrit, and Philosophy.

National Institute of Technology Hamirpur accepts various national-level entrance exams such as JEE Main, NATA, CAT, MAT, GATE, IIT JAM, and others. Candidates willing to get admission to several courses at the National Institute of Technology Hamirpur must apply online on the official website of the university. 

BA admission at Nehru Gram Bharati University, Kotwa, is entrance-based. Students must appear for the CUET exam, which is a key requirement. Final selection is made based on CUET performance and academic merit in Class 12.

Yes. Hemwati Nandan Bahuguna Uttarakhand Medical Education University (HNBUMU) had announced counselling dates for Uttarakhand NEET 2025 round-3. But seat allotment was put of hold. Candidates had to register online and submit application to participate in the counselling till October 30, 2025. Seat allotment result was to be published on November 3, 2025.

While the BA course at Nehru Gram Bharati University Kotwa does not yet have a Shiksha rating, the UPRTOU BA programme holds a 3.5/5 rating, and Ewing Christian College's BA course scores slightly higher with a 3.8/5 rating. These ratings help students gauge academic quality and campus experience during college selection.

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol.

$\begin{array}{l}GiventhatL=200{\left(10-t\right)}^2\\ whereLrepresentsthenumberoflitresofwaterinthepool.\\ Differentiatingbothsidesw.r.t.,t,weget\\ \frac{dL}{dt}=200\times 2\left(10-t\right)\left(-1\right)=-400\left(10-t\right)\\ Buttherateatwhichthewaterisrunningout\\ =-\frac{dL}{dt}=400\left(10-t\right)\dots \left(i\right)\\ Rateatwhichthewaterisrunningafter5seconds\\ =400\left(10-5\right)=2000L/s\left(finalrate\right)\\ Forinitialrateputt=0\\ =400\left(10-0\right)=4000L/s\\ Theaveragerateatwhichthewaterisrunningout\\ =\frac{Initialrate+Finalrate}{2}=\frac{4000+2000}{2}=\frac{6000}{2}=3000L/s\\ Hence,therequiredrate=3000L/s.\end{array}$

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol: 

$\begin{array}{l}Internalradiusr=3cm\\ ExternalradiusR=r+\Delta r=3.0005cm\\ \therefore \Delta r=3.0005-3=0.0005cm\\ Lety=r^3\Rightarrow y+\Delta y={\left(r+\Delta r\right)}^3=R^3={\left(3.0005\right)}^3\dots \left(i\right)\\ Differentiatingbothsidesw.r.t.,r,weget\\ \frac{dy}{dx}=3r^2\\ \therefore \Delta y=\left(\frac{dy}{dr}\right).\Delta r=3r^2\times 0.0005\\ =3\times {\left(3\right)}^2\times 0.0005=27\times 0.0005=0.0135\\ \therefore {\left(3.0005\right)}^3=y+\Delta y\left[Fromeqn\left(i\right)\right]\\ ={\left(3\right)}^3+0.0135=27+0.0135=27.0135\\ Volumeoftheshell=\frac{4}{3}\pi \left[R^3-r^3\right]\\ =\frac{4}{3}\pi \left[27.0135-27\right]=\frac{4}{3}\pi \times 0.0135\\ =4\pi \times 0.0045=4\times 3.14\times 0.0045=0.018\pi c{m}^3\\ Hence,approximateVolumeofthemetalintheshellis0.018\pi c{m}^3.\end{array}$

Yes, IIFT Kakinada provides relaxation in the aggregate to SC/ ST candidates. Those belonging to SC/ ST category get 5% relaxation in the Class 12 score. Such aspirants need to complete Class 12/ HSc examination in Arts, Commerce, Science stream or equivalent with at least 55% aggregate to apply for IPM. 

Yes, BSEB 12th sample papers are created as per the latest syllabus and exam pattern released by the Bihar School Examination Board. These papers include objective, short, and long-answer questions similar to those asked in the actual board exams. They are designed to help students prepare effectively. Students should always check the year and syllabus mentioned on the sample paper before using it. Practicing the right papers ensures accurate preparation.

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol: 

$\begin{array}{l}{\left(1.999\right)}^5={\left(2-0.001\right)}^5\\ Letx=2and\Delta x=-0.001\\ Lety=x^5\\ Differentiatingbothsidesw.r.t.,x,weget\\ \frac{dy}{dx}=5x^4=5{\left(2\right)}^4=80\\ Now\Delta y=\left(\frac{dy}{dx}\right).\Delta x=80.\left(-0.001\right)=-0.080\\ \therefore {\left(1.999\right)}^5=y+\Delta y\\ =x^5-0.080={\left(2\right)}^5-0.080=32-0.080=31.92\\ Hence,approximatevalueof{\left(1.999\right)}^{5}is31.92.\end{array}$

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol: 

$\begin{array}{l}Asperthegivencondition,\\ \frac{d\theta }{dt}=2\frac{d}{dt}\left(sin\theta \right)\\ \Rightarrow \frac{d\theta }{dt}=2cos\theta \frac{d\theta }{dt}\Rightarrow 1=2cos\theta \\ \therefore cos\theta =\frac{1}{2}\Rightarrow cos\theta =cos\frac{\pi }{3}\Rightarrow \theta =\frac{\pi }{3}\\ Hence,therequiredangleis\frac{\pi }{3}.\end{array}$

Admission to the respective courses is offered on the basis of valid scores of accepted entrance exams such as CEE/ JEE/ NEET/ CUET/ IPMAT or other equivalent national-level exams. In addition to this, candidates must secure a minimum aggregate of 50% to 60% in Class 10 and 12 to achieve the eligibility criteria. 

BA programme at Nehru Gram Bharati University Kotwa has a tuition fee ranging from INR 43,000 to 48,000, which is comparatively higher than UPRTOU's BA course (INR 6,000–32,000) and Ewing Christian College's BA course (INR 23,300). Students should evaluate costs alongside curriculum and outcomes before making a choice.

This is a Short Answer Type Question as classified in NCERT Exemplar

Sol: 

$\begin{array}{l}Weknowthat\\ Areaofcircle,A=\pi r^2,wherer=radiusofthecircleandperimeter=2\pi r\\ AsperQuestion,\frac{dA}{dt}={\rm K},whereK=constant\\ \Rightarrow \frac{d}{dt}\left(\pi r^2\right)=K\\ \Rightarrow \pi .2r.\frac{dr}{dt}=K\\ \therefore \frac{dr}{dt}=\frac{{\rm K}}{4\pi r^2}\dots \left(1\right)\\ NowPerimeterc=2\pi r\\ Differentiatingbothsides\text{?}w.r.t.t,weget\\ \Rightarrow \frac{dc}{dt}=\frac{d}{dt}\left(2\pi r\right)\\ \Rightarrow \frac{dc}{dt}=2\pi .\frac{dr}{dt}\\ \Rightarrow \frac{dc}{dt}=2\pi .\frac{K}{2\pi r}=\frac{K}{r}\left[Fromeqn\left(1\right)\right]\\ \Rightarrow \frac{dc}{dt}\propto \frac{1}{r}\\ Hence,theperimeterofthecirclevariesinverselyastheradiusofthecircle.\end{array}$