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OH group is the more activating group and ortho-para director, hence ortho position attach will provide meta substituted product with respect to – CH₃ in option (C).

The key exam date to keep in mind for BTech admission at Chitkara University is the JEE Main result announcement, typically released in April. Since admissions are based on JEE Main scores, candidates should track both JEE Main exam and result dates closely to ensure timely application and counselling participation.

Kindly consider the following figure

Yes BTech admissions at Chitkara University for 2025 academic session is open. Interested students can apply through official university website. Admission is primarily based on JEE Main scores and students are advised to apply soon after release of JEE Main results for better chances of seat allotment.

mg = 10 × 10

= 100 of

NA = $F_{\omega }$ reaction force offered by the wall

$\sqrt[]{N_3^2+f_B^2}=F_f$ reaction force offered by the floor.

By NLM 1

Translational fB = NA

NB = mg = 100N

Ac² + Bc² = AB²

Ac² = 34 – 9

Ac = 5m

Rotational equilibrium ${\tau }_B=0$

mg $\frac{\mathcal{l}}{2}cos\theta =N_A\mathcal{l}sin\theta$

$100\frac{cos\theta }{2}=N_{A}sin\theta$

NA = 50 cot

Now cot = $\frac{3}{5}$

N_A = $50\times \frac{3}{5}=30N$

Therefore, NA = $F_{\omega }=30N$ - (i)

$F_f=\sqrt[]{N_B^2+f_B^2}=\sqrt[]{100^2+30^2}=10\sqrt[]{109}N$ - (2)

$\raisebox{1ex}{$f_{\omega }$}\!\left/ \!\raisebox{-1ex}{$F_f$}\right.=\frac{30}{10\sqrt[]{109}}=\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$109$}\right.$

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Yes, Google offers many free certification courses after graduation in commerce. Some of the free courses that candidates can pursue after graduation in Commerce are:

• Google Digital Marketing & E-commerce Certificate
• Google Analytics Individual Qualification (GAIQ)

Candidates looking for course admission at the Dehradun Institute of Hospitality must meet the eligibility criteria set by the college. For certificate courses, candidates must pass Class 10 or Class 12. The selection criteria are based on merit. This course is open to Class 10 students who must have studied the English language as one of the subjects. The Course duration is for 20 weeks, followed by 24 weeks of Industrial Training.

The latest ranking for JSS Science and Technology University was provided by the IIRF in the year 2024. The ranking isprovided for the overall performance of the university. The IIRF gave a rank of 4th place to the JSS Science and Technology University in both the state and zone rankings. The IIRF also gave a national rank of 10th in its assessment during 2024. Candidates can check the IIRF ranking for the JSS Science and Technology University by visiting the official website. 

Some of the best BCA colleges in Delhi/NCR do have good reported average salaries and graduates get hired by well-known domestic and international recruiters. The table below lists these information. 

Note: All info. is from official sites and can change. 

Nucleophilicity is directly proportional to the electron density of atom and inversely proportional to its electronegativity.

Dehradun Institute of Hospitality offers four certificate courses. Students can check the table below to know the course-wise eligibility and selection criteria:

by, WET ${\displaystyle \int F}dx=\Delta k.6$

${\displaystyle \int -}kxdx=\frac{1}{2}m\left[v_t^2-v_i^2\right]$

$\Rightarrow \frac{-k}{2}{\left[x_f^2-x_i^2\right]}_{0.5}^{1.5}=\frac{1}{2}\times 2\left[v_f^2-16\right]$ $\left[?v_i=4m/sec\right]$

$\frac{-12}{2}\left[1.5^2-0.5^2\right]=\left[v_f^2-16\right]$

$v_f^2=16-12=4$

vf = 2m/sec

There are several BCA specializations that students can pursue at the best BCA colleges in Delhi/NCR. Students can take a look at the table below for more details.

Disclaimer: This information is sourced from the official website and may vary.

Six months courses are usually called certification courses or Diploma course. Though many certification courses lasts for more than six months. Candidates must check the duration and mode of the certification when pursuing the short term courses after graduation or after class 12th.

Highly polluted water has higher value of BOD $\ge$ 17 ppm

The Commission earlier released a total of 1340 vacancies. As per the official notice, the vacancies are increased. Now, the number of vacancies are 1731. The exam will be held to recruit junior engineers across the several central government departments. The notification was released on June 30, 2025.

a = 6t² – 2t,        of t 20, w = 10 rad/sec

, q = 4 rad

$\alpha =\frac{d\omega }{dt}$

$\Rightarrow {\displaystyle \underset{10}{\overset{\omega }{\int }}d\omega }={\displaystyle \underset{t-0}{\overset{t}{\int }}\alpha dt}$

$\Rightarrow \omega -10={\displaystyle \underset{0}{\overset{t}{\int }}\left(6t^2-2t\right)dt}$

$\omega =\frac{d\theta }{dt}$

$d\theta =\omega dt$

${\displaystyle \underset{4}{\overset{\theta }{\int }}d\theta ={\displaystyle \underset{0}{\overset{t}{\int }}\left(2t^3-t^2+10\right)dt}}$

= $\frac{t^4}{2}-\frac{t^3}{3}+10t+4$

 $C{e}^{3+}\to \left[Xe\right]4f^{1}5d^0$

$C{e}^{4+}\to \left[Xe\right]4f^{0}5d^0$  (Noble gas configuration)

This is the formation of free radical mechanism, hence free radical will be formed