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Yes, IHM Education Dehradun admissions are open for the academic year 2025. Candidates willing to take admission in the institute must apply on the official website by filling out the application form and paying the application fee to successfully submit the form. They must ensure filling out this form prior to the last date. Additionally, candidates must also ensure fulfilling the eligibility criteria for admission. 

$A{B}_2\left(g\right)?A\left(g\right)+2B\left(g\right)$

Initial1 mole -

At equilirbium 1-x mole x mole2x mole

V = 25 L and

T = 300 K.

At equilibrium, P = 1.9 atm

Total moles at equilibrium, n = 1 + 2x

V = 25 L

T = 300 K

Using, PV = nRT

1.9 × 25 = (1 + 2x) × 0.08206 × 300

x = 0.465

Now;Partial pressure of AB2 at equilibrium = $\frac{0.535}{1.93}\times 1.9atm$

Using ; $K_p=\frac{P_A.P_B^2}{P_{A{B}_2}}$

$K_p=\frac{\left(\frac{0.465\times 1.9}{1.93}\right){\left(\frac{2\times 0.465}{1.93}\times 1.9\right)}^2}{\frac{0.535}{1.93}\times 1.9}$ = 0.728

K_P = 0.73

K_p = 73 × 10^-2

So; x = 73

X → Y

$\begin{array}{l}{E}_{a_f}-E_{a_b}=-20\\ 30-E_{a_b}=-20\end{array}$

$E_{a_b}=50kJ/mole$

$Mn{O}_4^{-}+8H+5e^{-}\to Mn+4H_{2}O{E}^o=1.51V$

Quantity of electricity required to reduce 1 mole of $Mn{O}_4^{-}$ is 5F

So, for 5 mole $Mn{O}_4^{-}$ 25F electricity is required.

$P\left(V_m-b\right)=RT$

$\frac{P{V}_m}{RT}-\frac{Pb}{RT}=1$

$Z=1+\frac{Pb}{RT}$

${\left(\frac{\partial z}{\partial P}\right)}_T=\frac{b}{RT}$

So, comparing with $\frac{xb}{RT}$

x = 1

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[Mn₂ (CO)₁₀]

Bridging ligand (CO) is (0)

Heavy water (D₂O) is used in organic reaction to know the kinetics of reaction

Heavy water D₂O is obtained by repeated electrolysis of H₂O.

Heavy water has b.pt 101.4°C and ordinary water has b.pt 100°C

(b.pt of D₂O > b.pt of H₂O)

D₂O has more molecular mass than H₂O, so greater degree of association and hence greater b.pt and viscosity.

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O₃ generally exist in stratosphere and they acts as protector, because it protect us from harmful UV radiations but sometimes O₃ formed in troposphere and it acts as a pollutants.

O₃ in stratosphere : - Protector

O₃ in Troposphere : - Pollutant (photochemical smog)

Kernite $\left(N{a}_2{B}_4{O}_7.4H_{2}O\right)\to$ it is ore of boron

Cassiterite (SnO₂) → it is ore of tin

Calamine (ZnCO₃) → it is ore of zinc

Cryolite (Na₃AlF₆) → it is ore fluorine

Option (A) is false statement because estimation of nitrogen in an organic compound is done by Kjeldahl's method.

A Levels stand for advanced level, and they are UK-based academic qualifications that are taken by students between the age group between ages of 16 to 18 years. They focus on in-depth knowledge of particular subjects and are recognised by Cambridge and the rest of the world. As an international student, these levels are not required, but the candidate must have passed with the highest scores possible. 

PbO₂ is used is lead storage battery and is amphoteric as strong oxidizing agent since Pb (II) is more stable than Pb (IV).

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$N{H}_3+\underset{A}{H_{2}O}+C{O}_2\to {\left(N{H}_4\right)}_{2}C{O}_3$

${\left(N{H}_4\right)}_{2}C{O}_3+H_{2}O+\underset{B}{C{O}_2}\to N{H}_{4}HC{O}_3$

$N{H}_{4}HC{O}_3+NaCl\to N{H}_{4}Cl+\underset{C}{NaHC{O}_3}$